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29 Apr 2016, 16:05
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If x, y, and z are all positive integers, how many trailing zeros are contained in the product of (5^x)(2^y)(3^z)?
(1) x = 12
(2) x < y
(1) x = 12
(2) x < y
29 Apr 2016, 21:40
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The number of trailing zeros in a number will always depend on the number of 5's and 2's available as factors.
This question is basically asking us to find the number of pairs of 5 and 2.
First condition is certainly not enough.
Second condition is just a relation.Hence not enough.
Combining both conditions will tell us the exact number of pairs of 5 and 2. Thus C is the answer.
This question is basically asking us to find the number of pairs of 5 and 2.
First condition is certainly not enough.
Second condition is just a relation.Hence not enough.
Combining both conditions will tell us the exact number of pairs of 5 and 2. Thus C is the answer.
Balajikarthick1990
30 Apr 2016, 05:23
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Bunuel
If x, y, and z are all positive integers, how many trailing zeros are contained in the product of (5^x)(2^y)(3^z)?
(1) x = 12
(2) x < y
(1) x = 12
(2) x < y
C it is...(5,2) creates a zero....minimal pairing concept...
