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If x, y, and z are positive integers, what is the remainder when 100x

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If x, y, and z are positive integers, what is the remainder when 100x  [#permalink]

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New post 10 Jun 2008, 22:37
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If x, y, and z are positive integers, what is the remainder when 100x + 10y + z is divided by 7 ?

(1) y = 6
(2) z = 3

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Re: If x, y, and z are positive integers, what is the remainder when 100x  [#permalink]

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New post 25 Dec 2014, 11:37
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Hi All,

This post is from years ago, but the prompt still serves as an example of how TESTing VALUES can help you to prove the correct answer in many DS questions.

We're told that X, Y and Z are POSITIVE INTEGERS. We're asked for the REMAINDER when 100X + 10Y + Z is divided by 7.

Fact 1: Y = 6

Since we don't know the values of X or Z, let's TEST VALUES.

Technically, we can use ANY positive integers for X and Z, but I'm going to keep things simple...
X = 1, Z = 1

(100 + 60 + 1)/7
161/7 = 23r0 so the answer is 0

X = 1, Z = 3
(100 + 60 + 3)/7
163/7 = 23r2 so the answer is 2
Fact 1 is INSUFFICIENT

Fact 2: Z = 3

Again, we can use ANY positive integers for X and Y, but let's keep things simple...

We can use the second example from Fact 1 here...
X = 1, Y = 6, Z = 3
163/7 = 23r2 so the answer is 2

X = 1, Y = 1, Z = 3
(100 + 10 + 3)/7
113/7 = 16r1 so the answer is 1
Fact 2 is INSUFFICIENT

Combined, we know
Y = 6
Z = 3
X = ANY POSITIVE INTEGER

If X = 1 (from our prior work)
163/7 = 23r2 so the answer is 2

If X = 2
(200 + 60 + 3)/7
263/7 = 37r4 so the answer is 4
Combined, INSUFFICIENT

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Re: If x, y, and z are positive integers, what is the remainder when 100x  [#permalink]

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New post 10 Jun 2008, 23:11
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I think it should be E

you can represent 100X+10Y+Z as a three digit number XYZ


now from condition 1 and 2 , this three digit number is X63 , plug in different values for X : 163/7 --remainder is 2 , 263/7 ----remainder 4

One more comment on this solution : X , Y , Z can be > 10 ,so represtating 100X+10Y+Z as XYZ will not always be right , but by limiting the scope of X, Y, Z values we can simplyfy the solution ;-)
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Re: If x, y, and z are positive integers, what is the remainder when 100x  [#permalink]

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New post 11 Jun 2008, 00:40
rpmodi wrote:
I think it should be E

you can represent 100X+10Y+Z as a three digit number XYZ


now from condition 1 and 2 , this three digit number is X63 , plug in different values for X : 163/7 --remainder is 2 , 263/7 ----remainder 4

One more comment on this solution : X , Y , Z can be > 10 ,so represtating 100X+10Y+Z as XYZ will not always be right , but by limiting the scope of X, Y, Z values we can simplyfy the solution ;-)


Thanks rpmodi, smart explaination!and E is OA :P
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Re: If x, y, and z are positive integers, what is the remainder when 100x  [#permalink]

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New post 07 Dec 2014, 14:16
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sondenso wrote:
If x, y, and z are positive integers, what is the remainder when 100x + 10y + z is divided by 7 ?

(1) y = 6
(2) z = 3



Hi,

I set this problem up in a slightly different way.

I noticed that it has 1 equation and 4 unknowns, if you include remainder A.

Stmt 1 = With that logic, you substitute 6, you still have 3 unknowns and one equation. NS - Eliminate A
Stmt 2 = Set up the same equation by substituting 3, you still have 3 unknowns and one equation. NS - Eliminate B

If you set up the equation to include y and z (100x +10 (6) + 3)/7 = a) you have one equation and two unknowns Eliminate C.

Therefore, the only possible solution is E.

Does my logic make sense?
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Re: If x, y, and z are positive integers, what is the remainder when 100x  [#permalink]

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New post 24 Dec 2014, 20:04
sondenso wrote:
If x, y, and z are positive integers, what is the remainder when 100x + 10y + z is divided by 7 ?

(1) y = 6
(2) z = 3



10y when divided by 7 can leave different remainders.
19*6 = 60 leaves remainder 4

z = 3 leaves remainder 3

but 100x when divided by 7 can leave different remainders. As we don't have concrete value for x, the answer is E
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Re: If x, y, and z are positive integers, what is the remainder when 100x  [#permalink]

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New post 28 Jan 2017, 14:31
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100x+10y+z
a)y=6. if we take x,y as same and keep on changing z, we will get different remainders Thus insufficient.
b)z=3. keep x same and z as 6. 10y=10,20,30....
10 remainder = 3
20 remainder = 6
Insufficient.
a&b together) 100x+60+3 = 100x+63. 63 is divisible by 7, thus remainder is based on 100x
x=1, 100 remainder=2
x=2, 200 remainder=4
Hence E
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Re: If x, y, and z are positive integers, what is the remainder when 100x  [#permalink]

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New post 02 Mar 2017, 06:29
rpmodi wrote:
I think it should be E

you can represent 100X+10Y+Z as a three digit number XYZ


now from condition 1 and 2 , this three digit number is X63 , plug in different values for X : 163/7 --remainder is 2 , 263/7 ----remainder 4

One more comment on this solution : X , Y , Z can be > 10 ,so represtating 100X+10Y+Z as XYZ will not always be right , but by limiting the scope of X, Y, Z values we can simplyfy the solution ;-)


Hi - Why can we represent 100X+10Y+Z as a three digit number?
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Re: If x, y, and z are positive integers, what is the remainder when 100x  [#permalink]

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New post 02 Mar 2017, 06:36
mhill5446 wrote:
rpmodi wrote:
I think it should be E

you can represent 100X+10Y+Z as a three digit number XYZ


now from condition 1 and 2 , this three digit number is X63 , plug in different values for X : 163/7 --remainder is 2 , 263/7 ----remainder 4

One more comment on this solution : X , Y , Z can be > 10 ,so represtating 100X+10Y+Z as XYZ will not always be right , but by limiting the scope of X, Y, Z values we can simplyfy the solution ;-)


Hi - Why can we represent 100X+10Y+Z as a three digit number?


This is a way of writing an x-digit number.

For example, any two-digit integer can be represented as 10a+b (where a and b are single digit integers), for example 37=3*10+7, 88=8*10+8, etc.
Any three-digit integer can be represented as 100a+10b+c (where a, b and c are single digit integers), for example 371=3*100+7*10+1, ...

Hope it's clear.
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Re: If x, y, and z are positive integers, what is the remainder when 100x  [#permalink]

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New post 02 Mar 2017, 06:43
E... since we have no idea of what x is

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Re: If x, y, and z are positive integers, what is the remainder when 100x  [#permalink]

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New post 06 Mar 2017, 18:08
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sondenso wrote:
If x, y, and z are positive integers, what is the remainder when 100x + 10y + z is divided by 7 ?

(1) y = 6
(2) z = 3



We need to determine the remainder of (100x + 10y + z)/7. If we can determine the remainder of 100x/7, 10y/7, and z/7, then we can determine the remainder of (100x + 10y + z)/7.

Statement One Alone:

y = 6

Using the information in statement one, we have:

(100x + 60 + z)/7

Although we know the remainder of 60/7 is 4 (note: 60/7 = 8 + 4/7), we still cannot determine the remainder of 100x/7 or z/7. Statement one alone is not sufficient to answer the question.

Statement Two Alone:

z = 3

Using the information in statement two, we have:

(100x + 10y + 3)/7

Although we know the remainder of 3/7 is 3, we still cannot determine the remainder of 10y/7 or 100x/7.

Statement two alone is not sufficient to answer the question.

Statements One and Two Together:

Using the information from statements one and two, we have:

(100x + 60 + 3)/7 = (100x + 63)/7

Although we know the remainder of 63/7 is 0, we still cannot determine the remainder of 100x/7. Different values of x might yield different remainders. For example, if x = 1, then the remainder of 100/7 is 2, since 100/7 = 14 + 2/7. However, if x = 2, then the remainder of 200/7 is 4, since 200/7 = 28 + 4/7.

Answer: E
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Re: If x, y, and z are positive integers, what is the remainder when 100x  [#permalink]

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New post 08 May 2017, 19:01
I had guessed E because we are given only two of three variables with the two statements. I didn't consider testing values and/or reasoning it out - moreso guessed it straight away because we are still missing one variable within the equation (similar to hsingh2008's post above) -- is this a valid approach or no?
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If x, y, and z are positive integers, what is the remainder when 100x  [#permalink]

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New post 27 Aug 2018, 08:19
The number XYZ is devided by 7 if 2*Z-XY can be devided by 7. In this case we have got only Z and Y but not X. So the answer is E. Another way to silve is to take 163 and 263 and compare remainders - they are different.
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If x, y, and z are positive integers, what is the remainder when 100x  [#permalink]

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New post Updated on: 04 Apr 2019, 08:38
Bunuel wrote:
mhill5446 wrote:
rpmodi wrote:
I think it should be E

you can represent 100X+10Y+Z as a three digit number XYZ


now from condition 1 and 2 , this three digit number is X63 , plug in different values for X : 163/7 --remainder is 2 , 263/7 ----remainder 4

One more comment on this solution : X , Y , Z can be > 10 ,so represtating 100X+10Y+Z as XYZ will not always be right , but by limiting the scope of X, Y, Z values we can simplyfy the solution ;-)


Hi - Why can we represent 100X+10Y+Z as a three digit number?


This is a way of writing an x-digit number.

For example, any two-digit integer can be represented as 10a+b (where a and b are single digit integers), for example 37=3*10+7, 88=8*10+8, etc.
Any three-digit integer can be represented as 100a+10b+c (where a, b and c are single digit integers), for example 371=3*100+7*10+1, ...

Hope it's clear.



Bunuel,

Hi i wanted to understand how did we come to know that its a three digit number ?

But we are told that that X,Y,Z are positive integers. Had we be given that they are digits we can express 100X+10Y+Z as three digit positive integer.

Here is what i mean if X= 2 Y=6 Z=3 then the number would be 263

But if X = 20 Y=6 and Z 3 then the number would be 2063.

So with certainty how can we say that its a three digit positive number, while we only know that X,Y,Z are positive integers.

But i had a different approach for this question

n= 100X+10Y+Z
n= 98X+2X+7Y+3Y+Z
\(\frac{n}{7}\)= \(\frac{98X+2X+7Y+3Y+Z}{7}\)

so remainder will be \(\frac{2X+3Y+Z}{7}\)

So to answer the question we need to know all the three variable X,Y,Z
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Originally posted by Probus on 15 Mar 2019, 08:09.
Last edited by Probus on 04 Apr 2019, 08:38, edited 2 times in total.
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Re: If x, y, and z are positive integers, what is the remainder when 100x  [#permalink]

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New post 15 Mar 2019, 15:16
Hi Probus,

You're correct - there is nothing in the prompt that states that the final number must be a 3-digit number. By thinking in those terms however, the work becomes a lot easier - and you can quickly prove that Fact 1 and Fact 2 are each INSUFFICIENT (as well as prove that combining both Facts still leads to an INSUFFICIENT answer).

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Re: If x, y, and z are positive integers, what is the remainder when 100x   [#permalink] 15 Mar 2019, 15:16
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