septwibowo wrote:

Nikkb wrote:

If x, y and z are positive single-digit integers and \(x^y = z\) . What is z?

(1) x and y even numbers

(2) x = y

Nikkb , I chose C because I thought that statement A is not sufficient,

\(Z\) can be 1 if \(x=4\) and \(y=0\)

\(Z\) can be 4 if \(x=2\) and \(y=2\).

Wdyt?

This one exploits our knowledge about an even and positive number. Is 0 positive even integer?

Generally below 4 terms are used in question stem:

Positive number x => \(x>0\) =>All Numbers more than 0 but not equal to 0

Non-Negative number x => \(x\geq{0}\) =>All Numbers above 0 or equal to 0.

Negative number x => \(x<0\) =>All Numbers less than 0 but not equal to 0

Non-Positive number x => \(x\leq{0}\) =>All Numbers less than 0 or equal to 0.

even integers : ... -4,-2,0,2,4, ......

odd integers : ... -3,-1,1,3,......

So 0 is considered even integer but its neither positive nor negative.Above question talks about "positive single digit integer" => Integers can be 1,2,3...,9 ... Value of integer cannot be equal to 0 here.

Hope this helps