fitzpratik
If x>y, then is 1/x < 1/y?
A. x is negative
B. y is negative
Here's another approach....
Given: y < x Target question: Is 1/x < 1/y? Statement 1: x is negativeSince we already know that
y < x, we can conclude that y is also NEGATIVE
If x and y are both NEGATIVE, then the product xy is POSITIVE
Since xy is POSITIVE, we can safely take the target question,
Is 1/x < 1/y?, and multiply both sides by xy.
When we do so, we get the NEW target question:
Is y < x?Since it's given that
y < x, the answer to the NEW target question is
YES, y IS less than xSince we can answer the
NEW target question with certainty, statement 1 is SUFFICIENT
Statement 2: y is negativeThere are several values of x and y that satisfy statement 2. Here are two:
Case a: x = -1/3 and y = -1/2. In this case, 1/x = -3 and 1/y = 2. So, the answer to the target question is
YES, 1/x is NOT less than 1/yCase b: x = 1/2 and y = -1/2. In this case, 1/x = 2 and 1/y = -2. So, the answer to the target question is
NO, 1/x is NOT less than 1/ySince we cannot answer the
target question with certainty, statement 2 is NOT SUFFICIENT
Answer: A
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