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# If xy ≠ 0 and x^2y^2 xy = 6, which of the following

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Senior Manager
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If xy ≠ 0 and x^2y^2 xy = 6, which of the following [#permalink]

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22 Aug 2006, 06:32
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If xy ≠ 0 and x^2y^2 â€“ xy = 6, which of the following could be y in terms of x?

I. 1/(2x)
II. â€“ 2/x
III. 3/x

I have no idea how to go about this pls help

Last edited by apollo168 on 22 Aug 2006, 09:17, edited 1 time in total.
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22 Aug 2006, 09:15
II and III

by substitution

If y = 1/2x; then x^2y^2 - xy = x^2/4x^2 -x/2x = 1/4 -1/2 not equal to 6
You can substitute the other two values and see that they can be equal to 6
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22 Aug 2006, 09:19
hey thanks
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22 Aug 2006, 10:55
Substitute X*Y with A and solve the equation A^2-A-6=0 . Solutions are 3 and -2 so X*Y=3 and X*Y= -2
22 Aug 2006, 10:55
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# If xy ≠ 0 and x^2y^2 xy = 6, which of the following

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