carcass wrote:
If xyz < 0 and yz > 0, which of the following must be positive?
(A) xy
(B) xz
(C) (x^2)yz
(D) x(y^2)z
(E) xy(z^2)
Given:
xyz < 0 and
yz > 0 ======> This means that either x and y both are positive or both are negative.
So x can has to be negative, only answer choice which gives us a positive option will be the choice which squares x.
Hence, answer is C - (x^2)yz
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