carcass wrote:

If xyz < 0 and yz > 0, which of the following must be positive?

(A) xy

(B) xz

(C) (x^2)yz

(D) x(y^2)z

(E) xy(z^2)

Given:

xyz < 0 and

yz > 0 ======> This means that either x and y both are positive or both are negative.

So x can has to be negative, only answer choice which gives us a positive option will be the choice which squares x.

Hence, answer is C - (x^2)yz
_________________

"Nothing in this world can take the place of persistence. Talent will not: nothing is more common than unsuccessful men with talent. Genius will not; unrewarded genius is almost a proverb. Education will not: the world is full of educated derelicts. Persistence and determination alone are omnipotent."

Best AWA Template: https://gmatclub.com/forum/how-to-get-6-0-awa-my-guide-64327.html#p470475