Asad wrote:
Quote:
decrease i
-->Which one we have to do with
i? Should we decrease
i or fixed the previous value of
i?
Like,
if p=10; e=7; i=15
If we increase the value of those by 2 we get-->
p=12;
e=9; i=17If we decrease i by 2 to decrease e, we get-->
p=12;
e=7 (original value); i=15 (original value)Are you talking about the
blue part?
Thanks__
Asad, this is not a joint variation question and we don't have to use it.
This point is discussed here:
https://www.gmatclub.com/forum/veritas-prep-resource-links-no-longer-available-399979.html#/2015/0 ... questions/What happens in Joint Variation?
In joint variation, if p is directly proportional to e and e is directly proportional to i, then p is inversely proportional to i.
Note why: This relation of p and i holds when e is constant.
If we increase p, e increases (because e is directly proportional to p).
So what happens to i? Relation between p and i depends on keeping e constant. Since e has increased, it needs to be reduced back to keep it constant. So we should reduce i to reduce e (because i is directly proportional to e).
As per joint variation, pi/e = constant
If p doubles, i should become (1/2) to maintain the value of pi/e.
This question does not say that e needs to be held constant. So the impact will be in sequence. If p doubles, e doubles. If e doubles, i doubles. So p is directly proportional to i.