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# In a poll of 66,000 physicians, only 20 percent responded;

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Math Expert
Joined: 02 Sep 2009
Posts: 58446
In a poll of 66,000 physicians, only 20 percent responded;  [#permalink]

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08 Jan 2014, 07:07
1
2
00:00

Difficulty:

5% (low)

Question Stats:

90% (01:26) correct 10% (01:26) wrong based on 536 sessions

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The Official Guide For GMAT® Quantitative Review, 2ND Edition

In a poll of 66,000 physicians, only 20 percent responded; of these, 10 percent disclosed their preference for pain reliever X. How many of the physicians who responded did not disclose a preference for pain reliever X?

(A) 1.320
(B) 5,280
(C) 6,600
(D) 10,560
(E) 11,880

Problem Solving
Question: 26
Category: Arithmetic Percents
Page: 65
Difficulty: 600

GMAT Club is introducing a new project: The Official Guide For GMAT® Quantitative Review, 2ND Edition - Quantitative Questions Project

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Joined: 02 Sep 2009
Posts: 58446
Re: In a poll of 66,000 physicians, only 20 percent responded;  [#permalink]

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08 Jan 2014, 07:07
SOLUTION

In a poll of 66,000 physicians, only 20 percent responded; of these, 10 percent disclosed their preference for pain reliever X. How many of the physicians who responded did not disclose a preference for pain reliever X?

(A) 1.320
(B) 5,280
(C) 6,600
(D) 10,560
(E) 11,880

The # of physicians responded = 0.2*66,000 = 13,200.

Of these, 10 percent disclosed their preference for pain reliever X --> 1,320 disclosed, thus 13,200 - 1,320 = 11,880 did not.

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Re: In a poll of 66,000 physicians, only 20 percent responded;  [#permalink]

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08 Jan 2014, 21:29
1
Responded = (1/5)*66000 = 13,200.
No. of physicians who did not disclose = (.9) * 13,200 = 11,880

Ans is (E).
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Joined: 17 Oct 2013
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Re: In a poll of 66,000 physicians, only 20 percent responded;  [#permalink]

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08 Jan 2014, 23:13
3
Bunuel wrote:
The Official Guide For GMAT® Quantitative Review, 2ND Edition

In a poll of 66,000 physicians, only 20 percent responded; of these, 10 percent disclosed their preference for pain reliever X. How many of the physicians who responded did not disclose a preference for pain reliever X?

(A) 1.320
(B) 5,280
(C) 6,600
(D) 10,560
(E) 11,880

Problem Solving
Question: 26
Category: Arithmetic Percents
Page: 65
Difficulty: 600

GMAT Club is introducing a new project: The Official Guide For GMAT® Quantitative Review, 2ND Edition - Quantitative Questions Project

Each week we'll be posting several questions from The Official Guide For GMAT® Quantitative Review, 2ND Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution.

We'll be glad if you participate in development of this project:
2. Please vote for the best solutions by pressing Kudos button;
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Thank you!

it is as simple as 66000*(20/100)*(1-1/10)=11880
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Re: In a poll of 66,000 physicians, only 20 percent responded;  [#permalink]

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10 Jan 2014, 10:34
1
Bunuel wrote:
The Official Guide For GMAT® Quantitative Review, 2ND Edition

In a poll of 66,000 physicians, only 20 percent responded; of these, 10 percent disclosed their preference for pain reliever X. How many of the physicians who responded did not disclose a preference for pain reliever X?

(A) 1.320
(B) 5,280
(C) 6,600
(D) 10,560
(E) 11,880

90% of 20% of 66000 is the required answer
=> 18% of 66000.
13200 - 1320 = should end with 088. Hence Option E)
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Math Expert
Joined: 02 Sep 2009
Posts: 58446
Re: In a poll of 66,000 physicians, only 20 percent responded;  [#permalink]

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11 Jan 2014, 06:13
SOLUTION

In a poll of 66,000 physicians, only 20 percent responded; of these, 10 percent disclosed their preference for pain reliever X. How many of the physicians who responded did not disclose a preference for pain reliever X?

(A) 1.320
(B) 5,280
(C) 6,600
(D) 10,560
(E) 11,880

The # of physicians responded = 0.2*66,000 = 13,200.

Of these, 10 percent disclosed their preference for pain reliever X --> 1,320 disclosed, thus 13,200 - 1,320 = 11,880 did not.

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Joined: 07 Apr 2015
Posts: 153
Re: In a poll of 66,000 physicians, only 20 percent responded;  [#permalink]

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15 May 2015, 02:14
Damn and blast I hate it when i misread the question...
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Re: In a poll of 66,000 physicians, only 20 percent responded;  [#permalink]

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31 Aug 2016, 05:19
Bunuel wrote:
The Official Guide For GMAT® Quantitative Review, 2ND Edition

In a poll of 66,000 physicians, only 20 percent responded; of these, 10 percent disclosed their preference for pain reliever X. How many of the physicians who responded did not disclose a preference for pain reliever X?

(A) 1.320
(B) 5,280
(C) 6,600
(D) 10,560
(E) 11,880

Total Physician = 66000
People who responded = (20/100)*66000 = 13200

10% of respondents disclosed their preference

i.e. 10% of respondents did NOT disclose their preference = (90/100)*13200 = 11880

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Re: In a poll of 66,000 physicians, only 20 percent responded;  [#permalink]

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21 Feb 2019, 08:20
Bunuel wrote:
The Official Guide For GMAT® Quantitative Review, 2ND Edition

In a poll of 66,000 physicians, only 20 percent responded; of these, 10 percent disclosed their preference for pain reliever X. How many of the physicians who responded did not disclose a preference for pain reliever X?

(A) 1.320
(B) 5,280
(C) 6,600
(D) 10,560
(E) 11,880

Problem Solving
Question: 26
Category: Arithmetic Percents
Page: 65
Difficulty: 600

GMAT Club is introducing a new project: The Official Guide For GMAT® Quantitative Review, 2ND Edition - Quantitative Questions Project

Each week we'll be posting several questions from The Official Guide For GMAT® Quantitative Review, 2ND Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution.

We'll be glad if you participate in development of this project:
2. Please vote for the best solutions by pressing Kudos button;
3. Please vote for the questions themselves by pressing Kudos button;
4. Please share your views on difficulty level of the questions, so that we have most precise evaluation.

Thank you!

$$66000*20/100*90/100$$

=> $$11880$$, Answer must be (E)
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Re: In a poll of 66,000 physicians, only 20 percent responded;   [#permalink] 21 Feb 2019, 08:20
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