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Bunuel
In a sequence of N consecutive integers, are there exactly two multiples of 8?

(1) N = 18
(2) The first integer in the sequence is not a multiple of 8.
Question: DOes sequence have exactly two multiples of 8?

Statement 1: N = 18

18 consecutive integer always include two or three multiple of 8 hence

e.g. 8, 16, 24 from 8 to 25 OR
e.g. 8, 16 from 1 to 18

NOT SUFFICIENT

Statement 2: The first integer in the sequence is not a multiple of 8

But teh number of multiples of 2 in set of N consecutive integers still depends on the value of N hence

NOT SUFFICIENT

e.g. 8, 16, 24 from 9 to 24 OR
e.g. 8, 16 from 1 to 18

Answer: Option E
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In a sequence of N consecutive integers, are there exactly two multiples of 8?

(1) N = 18
N = 18, but we don't know the starting number.
If N consecutive no. starts from 1, then 1 to 18 has 2 multiples of 8 (8 and 16)
If N consecutive no. starts from 10, then 1 to 18 has 1 multiples of 8 (8 and 16)
Hence not Sufficient.

(2) The first integer in the sequence is not a multiple of 8.

This means first int can be 1,2,3,4,5,7,(not 8), 9,10.... Not Sufficient

Both 1 and 2
=> will give multiple combinations and hence IMO answer should be E
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Bunuel
In a sequence of N consecutive integers, are there exactly two multiples of 8?

(1) N = 18
(2) The first integer in the sequence is not a multiple of 8.

The sequence is a set of N consecutive integers.

Statements:

(1) N = 18
Consider the following 2 cases:
A - (1,2,3 .... , 18) - Are there exactly 2 multiples of 8? YES
B - (7,8,9 .... , 24) - Are there exactly 2 multiples of 8? NO.

Insufficient.

(2) The first integer in the sequence is not a multiple of 8.
The list can be as long as we want.

Clearly, Insufficient.

Combining, we still have the (7,8,9 .... 24) sequence.

Insufficient.

Hence, the answer is (E).
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