Last visit was: 19 Nov 2025, 04:05 It is currently 19 Nov 2025, 04:05
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 19 Nov 2025
Posts: 105,379
Own Kudos:
Given Kudos: 99,977
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,379
Kudos: 778,194
 [11]
Kudos
Add Kudos
11
Bookmarks
Bookmark this Post
avatar
pleasefix
Joined: 20 Sep 2021
Last visit: 20 Jun 2022
Posts: 7
Own Kudos:
5
 [1]
Given Kudos: 9
Location: Netherlands
GMAT 1: 730 Q47 V42
GPA: 3.4
GMAT 1: 730 Q47 V42
Posts: 7
Kudos: 5
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
rsrighosh
Joined: 13 Jun 2019
Last visit: 11 Dec 2022
Posts: 188
Own Kudos:
132
 [1]
Given Kudos: 645
GMAT 1: 490 Q42 V17
GMAT 2: 550 Q39 V27
GMAT 3: 630 Q49 V27
GMAT 3: 630 Q49 V27
Posts: 188
Kudos: 132
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
NarayanaGupta007
Joined: 21 Aug 2021
Last visit: 04 Sep 2025
Posts: 74
Own Kudos:
35
 [1]
Given Kudos: 51
Posts: 74
Kudos: 35
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
pleasefix
Assuming that the two conveyor belts are the same length the answer would be:

Total time: 64s.

Two belts, with effective speeds of \(2-0,5 = 1,5 & 2+0,5=2,5. \)

Let one way distance on a belt be D.

\(Total time = \frac{D}{2,5}+ \frac{D}{1,5}+\frac{D}{2,5}+\frac{D}{1,5}\)


Thus: \(64 = \frac{8D}{3,75}\)
Gives \(D = 30\)

As D is only half the distance; Total distance between P&R \(= 2*D = 2*30 = 60\)

Answer = C



I got answere by taking X and Y as distance as in ques not given Q is mid point how u take assumption of midpoint can u tell me cal part will be so easy after that.
User avatar
ShenotShih1017
Joined: 24 Jun 2024
Last visit: 12 Dec 2024
Posts: 14
Own Kudos:
Given Kudos: 17
Location: United States
Posts: 14
Kudos: 10
Kudos
Add Kudos
Bookmarks
Bookmark this Post
The answer seems to depend on the assumption that the distances are equal, can anyone explain how that conclusion is reached from the question stem?
User avatar
mvgkannan
Joined: 23 Apr 2025
Last visit: 01 Oct 2025
Posts: 58
Own Kudos:
36
 [2]
Given Kudos: 38
Location: India
Concentration: Finance, Entrepreneurship
GMAT Focus 1: 705 Q90 V85 DI80
WE:General Management (Government)
GMAT Focus 1: 705 Q90 V85 DI80
Posts: 58
Kudos: 36
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
There is no need to assume the belts are of equal length. Lets say PQ = x and QR = y. We know the belts move in opposite direction that is towards Q.

P-----------x------------->Q<--------------y---------------R.

Now the cart travels from P to Q and Q to R, then again from R to Q and finally from Q to P.

Speed of the belt = 0.5 m/s,
Speed of the cart = 2 m/s.
Speed when cart moves from P->Q = 2.5m/s,
Q->R = 1.5m/s,
R->Q = 2.5m/s,
Q->P = 1.5m/s,
\(Speed = \frac{Distance}{Time} \)

Inversely,

\(Time = \frac{Distance}{Speed}\)

Total time taken = 64s.

Therefore,

\(\frac{x}{2.5} + \frac{y}{1.5} + \frac{y}{2.5} + \frac{x}{1.5} = 64,\)

Rearranging,

\((x+y)(\frac{1}{2.5} + \frac{1}{1.5}) = 64\)

\((x+y) = 60\)

Bunuel
In an industry, the raw materials and the finished goods are transported on the conveyor belt. There are two conveyor belt, one for carrying parts from P to point Q and another for carrying parts from R to point Q. P, Q and R in that order are in a straight line. Sometimes, the belt serves to transport cart, which can themselves move with respect to the belts. The two belts move at a speed of 0.5 m/s and the cart move at a uniform speed of 2 m/s with respect to the belts. A cart goes from point P to R and back to P taking a total of 64 s. Find the distance PR in meters. Assume that the time taken by the cart to turn back at R is negligible?

A. 48
B. 54
C. 60
D. 64
E. 72


Are You Up For the Challenge: 700 Level Questions
User avatar
Kinshook
User avatar
Major Poster
Joined: 03 Jun 2019
Last visit: 19 Nov 2025
Posts: 5,794
Own Kudos:
5,509
 [1]
Given Kudos: 161
Location: India
GMAT 1: 690 Q50 V34
WE:Engineering (Transportation)
Products:
GMAT 1: 690 Q50 V34
Posts: 5,794
Kudos: 5,509
 [1]
Kudos
Add Kudos
Bookmarks
Bookmark this Post
In an industry, the raw materials and the finished goods are transported on the conveyor belt. There are two conveyor belt, one for carrying parts from P to point Q and another for carrying parts from R to point Q. P, Q and R in that order are in a straight line. Sometimes, the belt serves to transport cart, which can themselves move with respect to the belts. The two belts move at a speed of 0.5 m/s and the cart move at a uniform speed of 2 m/s with respect to the belts. A cart goes from point P to R and back to P taking a total of 64 s.

Find the distance PR in meters. Assume that the time taken by the cart to turn back at R is negligible?

----Conveyer belt 1---------> <-----Conveyer belt 2---------
P ------------------------------Q -------------------------------R

Let the distance PR be D and PQ be x meters

Time taken by a cart to go from point P to R and back to P = x/(2+.5) + (D-x)/(2-.5) + (D-x)/(2+.5) + x/(2-.5)= 64
x/2.5 + x/1.5 + (D-x)/2.5 + (D-x)/1.5 = 64
D/2.5 + D/1.5 = 64
8D/7.5 = 64
D = 60 meters

IMO C
Moderators:
Math Expert
105379 posts
Tuck School Moderator
805 posts