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Given a 6-digit integer, 543,2xy. Where x & y E {0, 2, 4, 6, 8}.

The total number of ways we can arrange them is 5 * 5 = 25.

For a number to be divisible by 8, the last three digits should be divisible by 8.
=> 2xy must be divisible by 8. Of the given set, we can have 9 values (00, 08, 24, 40, 48, 60, 68, 80, 88) we can have 8 values (00, 08, 24, 40, 48, 64, 80, 88).

Therefore, P(2xy divisible by 8) = 8/25. IMO is Option D.
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Total outcomes of x & y -> 5 x 5 -> 25
Favourable outcomes - 00 + multiples of 8, so possible favourable outcomes are : 00, 08, 24, 40, 48, 64, 80, 88 -> 8

Hence answer has to be D -> 8/25

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Correct option should be Option D

We should first know the divisibility rule by 8.

It says, if for any number, the last three digits are divisible by 8, the complete number is divisible by 8. For example, we take a number 35720. In this, the last 3 digits make the number 720 which is divisible by 8, so 35720 will be divisible by 8.

On the other hand, 35730 will not be divisible by 8 because 730 is not divisible by 8.

In our case, we have 0,2,4,6,8 as the choices for the last 2 digits. First let us see how many ways we can have for the last 2 digits. There is no restriction for repetition of digits. So we can have 5*5 = 25 ways for the last 2 digits.

From them some of the combinations would be divisible by 8, which are

2 00
2 08
2 24
2 40
2 48
2 64
2 80
2 88

So total 8 possibilities.

Probability = 8/25

Hence, answer should be D
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