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In the correctly-worked multiplication problem above, each

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In the correctly-worked multiplication problem above, each [#permalink]

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A
B
C
D
E

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In the correctly-worked multiplication problem above, each symbol represents a different nonzero digit. What is the value of ʞ?

(1) ʠ is prime

(2) ◊ is not prime
[Reveal] Spoiler: OA

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In the correctly-worked multiplication problem above, each [#permalink]

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WoundedTiger wrote:
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In the correctly-worked multiplication problem above, each symbol represents a different nonzero digit. What is the value of ʞ?

(1) ʠ is prime

(2) ◊ is not prime



We can do the prime factorization of 1995.

1995= 5*3*7*19.

Statement-1 :

Since they are only 2 digit numbers.

19*7= 133 and since ʠ is prime number -> 7*3=21, are not a possible for ʞʠ .

Also 19*3= 57 and 7*5=35 are not possible as each digit are different.

So only options are

7*3= 21 and 19*5= 95.

Hence the value of ʞ is 9. Sufficient.

Eliminate B, C and E.

Statement-2 :

◊ is not prime. And which is 2 digit number so only value will be 21. As the multiple of other numbers unit digit will be prime and few combination results in repetition of numbers which is not allowed as they are different numbers.

And ʞʠ will be 19*5=95.

The value of ʞ= 9.

So sufficient.

The answer is D.
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Re: In the correctly-worked multiplication problem above, each [#permalink]

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WoundedTiger wrote:
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In the correctly-worked multiplication problem above, each symbol represents a different nonzero digit. What is the value of ʞ?

(1) ʠ is prime

(2) ◊ is not prime


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Hope this helps.
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Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and equations ensures a solution.


In the correctly-worked multiplication problem above, each symbol represents a different nonzero digit. What is the value of ʞ?

(1) ʠ is prime

(2) ◊ is not prime

Transforming the original condition and the question, we have 1995=21*95=95*21. (Since all the digits have different values we can't have 35*57)
There are 4 variables and 1 equation, thus we need 3 more equations to match the number of variables and equations. Since there is 1 each in 1) and 2), E is likely the answer.
Using both 1)& 2) together, both gives us 21*95=1995 thus ʞ=9 and 1)=2). Therefore, D is the answer.
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Re: In the correctly-worked multiplication problem above, each [#permalink]

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Re: In the correctly-worked multiplication problem above, each   [#permalink] 15 Oct 2017, 02:54
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