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Bunuel

In the figure above, M and N are two points on the side PQ and PR of a triangle PQR, respectively such that MNQR is a trapezium and MN:QR = 2:5. What is the ratio of the area of triangle PMN to the area of trapezium MNQR?

A. 4:25
B. 4:21
C. 4:10
D. 4:9
E. 1:2


Are You Up For the Challenge: 700 Level Questions

Attachment:
The attachment Untitled.png is no longer available


The detailed video solution is attached here.

Answer: Option B


Attachments

Screenshot 2020-05-04 at 2.15.13 PM.png
Screenshot 2020-05-04 at 2.15.13 PM.png [ 1.05 MiB | Viewed 13363 times ]

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Please See Attached File

Let \(S\) be the area of ∆ PQR
Let \(S_{1}\) be the area of ∆ PMN

∆ PQR and ∆ PMN are similar triangles:
--> \(\frac{S_{1}}{S}= (\frac{2x}{5x})^{2}\)

\(S_{1}= (\frac{4}{25})S\)

The area of Trapezium = \(S- S_1= S- (\frac{4}{25})S = (\frac{21}{25})S\)

--> \((\frac{4}{25})/(\frac{21}{25})= \frac{4}{21}\)

Answer (B).
Attachments

Triangle_Treapezium.png
Triangle_Treapezium.png [ 13.49 KiB | Viewed 13061 times ]

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