GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 17 Jan 2019, 11:36

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Events & Promotions

Events & Promotions in January
PrevNext
SuMoTuWeThFrSa
303112345
6789101112
13141516171819
20212223242526
272829303112
Open Detailed Calendar
• The winning strategy for a high GRE score

January 17, 2019

January 17, 2019

08:00 AM PST

09:00 AM PST

Learn the winning strategy for a high GRE score — what do people who reach a high score do differently? We're going to share insights, tips and strategies from data we've collected from over 50,000 students who used examPAL.
• Free GMAT Strategy Webinar

January 19, 2019

January 19, 2019

07:00 AM PST

09:00 AM PST

Aiming to score 760+? Attend this FREE session to learn how to Define your GMAT Strategy, Create your Study Plan and Master the Core Skills to excel on the GMAT.

In the figure above, segments PQ and QR are each parallel to one of th

Author Message
TAGS:

Hide Tags

Retired Moderator
Joined: 29 Apr 2015
Posts: 842
Location: Switzerland
Concentration: Economics, Finance
Schools: LBS MIF '19
WE: Asset Management (Investment Banking)
In the figure above, segments PQ and QR are each parallel to one of th  [#permalink]

Show Tags

Updated on: 16 Aug 2015, 12:38
8
00:00

Difficulty:

55% (hard)

Question Stats:

58% (01:07) correct 42% (01:30) wrong based on 160 sessions

HideShow timer Statistics

In the figure above, segments PQ and QR are each parallel to one of the coordinate axes. What is the ratio of the length of QR to PQ?

(1) The slope of the line that passes through points P and R is 0.75.
(2) The coordinates of point P are (4,2).

Attachment:

Slope, ratio of sides.png [ 4.31 KiB | Viewed 3683 times ]

_________________

Saving was yesterday, heat up the gmatclub.forum's sentiment by spending KUDOS!

PS Please send me PM if I do not respond to your question within 24 hours.

Originally posted by reto on 13 Aug 2015, 09:33.
Last edited by Bunuel on 16 Aug 2015, 12:38, edited 1 time in total.
Edited the question.
Intern
Joined: 16 Apr 2015
Posts: 41
Concentration: Operations, Strategy
Schools: UFlorida '18, UFL '17
Re: In the figure above, segments PQ and QR are each parallel to one of th  [#permalink]

Show Tags

14 Aug 2015, 04:41
Retired Moderator
Joined: 29 Apr 2015
Posts: 842
Location: Switzerland
Concentration: Economics, Finance
Schools: LBS MIF '19
WE: Asset Management (Investment Banking)
Re: In the figure above, segments PQ and QR are each parallel to one of th  [#permalink]

Show Tags

14 Aug 2015, 04:50
1
vinnisatija wrote:

Statement 1 is sufficient because it gives you the slope of the line. Ask yourself "what is the slope" of the line?

Slope = $$\frac{y2-y1}{x2-x1}$$

Now, y2-y1 is actually the same as PQ.

x2-x1 is the same as QR.

Therefore 1 alone is sufficient. Statement 2 gives you just one point, alone this is clearly insufficient.
_________________

Saving was yesterday, heat up the gmatclub.forum's sentiment by spending KUDOS!

PS Please send me PM if I do not respond to your question within 24 hours.

CEO
Joined: 20 Mar 2014
Posts: 2639
Concentration: Finance, Strategy
Schools: Kellogg '18 (M)
GMAT 1: 750 Q49 V44
GPA: 3.7
WE: Engineering (Aerospace and Defense)
Re: In the figure above, segments PQ and QR are each parallel to one of th  [#permalink]

Show Tags

14 Aug 2015, 05:45
vinnisatija wrote:

The question asks us to find the ratio QR/PQ which is equal to the slope of line PR. The reason why QR/PQ = slope of PR is shown in attached figure.

Statement 1 is sufficient as it directly gives the slope of line segment PR.

Statement 2 is NOT sufficient as with coordinates of 1 point (P) we can calculate the slope of line PR.

A is thus the correct answer.
Attachments

image.jpg [ 24.16 KiB | Viewed 3261 times ]

Director
Joined: 23 Jan 2013
Posts: 559
Schools: Cambridge'16
Re: In the figure above, segments PQ and QR are each parallel to one of th  [#permalink]

Show Tags

02 Sep 2015, 23:57
We should find legs ratio in the right triangle. We know that any ratio in right triangle depends only on the non-right angles degree and does not depend on the length of sides. So, we need only one angle degree

St.1 gives us such information

St.2 does not give any

A
Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 6810
GMAT 1: 760 Q51 V42
GPA: 3.82
In the figure above, segments PQ and QR are each parallel to one of th  [#permalink]

Show Tags

04 Sep 2015, 03:47
Forget conventional ways of solving math questions. In DS, Variable approach is

the easiest and quickest way to find the answer without actually solving the

problem. Remember equal number of variables and equations ensures a solution.

In the figure above, segments PQ and QR are each parallel to one of the coordinate axes. What is the ratio of the length of QR to PQ?

(1) The slope of the line that passes through points P and R is 0.75.
(2) The coordinates of point P are (4,2).

Transforming the original condition and the question using variable approach method, we can find QR:PQ=QR/PQ=1/slope of line PR(Since Q is a right-angle). Since we have the slope from 1), A is the answer.
Attachments

Slope%2C ratio of sides.png [ 4.31 KiB | Viewed 3044 times ]

_________________

MathRevolution: Finish GMAT Quant Section with 10 minutes to spare
The one-and-only World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy.
"Only \$149 for 3 month Online Course"
"Free Resources-30 day online access & Diagnostic Test"
"Unlimited Access to over 120 free video lessons - try it yourself"

Board of Directors
Joined: 17 Jul 2014
Posts: 2600
Location: United States (IL)
Concentration: Finance, Economics
GMAT 1: 650 Q49 V30
GPA: 3.92
WE: General Management (Transportation)
Re: In the figure above, segments PQ and QR are each parallel to one of th  [#permalink]

Show Tags

03 Nov 2015, 15:45
can someone explain why ratio of legs is equal to the slope?
and why leg1/leg 2 = 1/slope and not leg2/leg1 = 1/slope?
Manager
Joined: 08 Sep 2010
Posts: 59
Re: In the figure above, segments PQ and QR are each parallel to one of th  [#permalink]

Show Tags

10 Nov 2015, 10:24
mvictor wrote:
can someone explain why ratio of legs is equal to the slope?
and why leg1/leg 2 = 1/slope and not leg2/leg1 = 1/slope?

Hi mvictor:
There is simple formula to calculate the slope of a line:
Change in y / Change in x

In the above problem, to calculate change in y: we have to points of y i.e. y co-ordinate at point P and point Q (Don't worry about the actual value). Now if you substract these two values, you will get PQ (no matter whatever is the actual values).

Similarly you can find out the change in x i.e. QR

So Statement is actually provided the value for PQ / QR = 0.75. Using this value you can easily find out QR / PQ. Hence Stmt. I is sufficient.

In Stmt. II - we just have the x and y co-ordinates for point P. We can't find out the co-ordinates for other points. Hence not sufficient.

Hope it helps.

Hit kudos if you like the explanation!!

Thanks,
Chanakya
Manager
Joined: 29 Nov 2018
Posts: 52
Location: India
Concentration: Entrepreneurship, General Management
GPA: 3.99
WE: Engineering (Computer Hardware)
Re: In the figure above, segments PQ and QR are each parallel to one of th  [#permalink]

Show Tags

30 Dec 2018, 22:39
1
Lets assume P = (x1,y1)
R = (x2, y2)
Than Q = (x2,y1)
pq = sqrt((x2-x1)^2)
QR = sqrt((y2-y1)^2)

ratio of pq/qr = sqrt((x2-x1)^2)/ sqrt((y2-y1)^2)

We are given slope of line PR. Hence we are given ratio of (y2-y1)/(x2-x1)

hence sufficient.

Please give kudos if you like the explanation.
Re: In the figure above, segments PQ and QR are each parallel to one of th &nbs [#permalink] 30 Dec 2018, 22:39
Display posts from previous: Sort by