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24 Aug 2017, 23:46
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D
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57% (02:00) correct
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In the figure above, what is the average (arithmetic mean) degree measure of the 12 marked angles?
(A) 40
(B) 50
(C) 60
(D) 70
(E) cannot be determined from the given information
Attachment:
2017-08-25_1041_001.png [ 18.09 KiB | Viewed 5490 times ]
septwibowo
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25 Aug 2017, 11:12
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Bunuel
- Total angles who meet in the centre should be 360-120 = 240.
- IF we assume that the centre angle of each triangle IS SAME, we can calculate the average.
- However, we can assume anything from given picture, so we can calculate.
E.
Waiting great explanation from Bunuel
25 Aug 2017, 11:21
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Let's call the point of intersection of the 6 triangles O, around which the sum of the angles is 360.
Since, the angle given is 120 degree, the remainder of the angles is 240.
There are 6 triangles and the angle(in each of the 6 triangles around point O) is \(\frac{240}{6} = 40\)
Since the sum of angles in a triangle is 180, the sum of the other 2 angles in each of the triangles is 140.
Therefore, the average degree measure is \(\frac{140*6}{12} =\) 70(Option D)
