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08 Mar 2017, 06:04
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A
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Difficulty:
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Question Stats:
66% (00:58) correct
34%
(01:05)
wrong
based on 32
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Is ab positive?
1. \((a + b)^{2} < (a - b)^{2}\)
2. a = b
1. \((a + b)^{2} < (a - b)^{2}\)
2. a = b
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08 Mar 2017, 06:15
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Is ab positive?
(1) \((a + b)^{2}\) < \((a - b)^{2}\)
\(a^2 + 2ab + b^2 < a^2 - 2ab + b^2\)
\(4ab < 0\)
\(ab<0\)
Sufficient.
(2) a = b. If a = b = 0, then ab = 0 but if a = b = 1, then ab = 1 > 0. Not sufficient.
Answer: A.
(1) \((a + b)^{2}\) < \((a - b)^{2}\)
\(a^2 + 2ab + b^2 < a^2 - 2ab + b^2\)
\(4ab < 0\)
\(ab<0\)
Sufficient.
(2) a = b. If a = b = 0, then ab = 0 but if a = b = 1, then ab = 1 > 0. Not sufficient.
Answer: A.
08 Mar 2017, 06:29
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Bunuel
Is ab positive?
(1) \((a + b)^{2}\) < \((a - b)^{2}\)
\(a^2 + 2ab + b^2 < a^2 - 2ab + b^2\)
\(4ab < 0\)
\(ab<0\)
Sufficient.
(2) a = b. If a = b = 0, then ab = 0 but if a = b = 1, then ab = 1 > 0. Not sufficient.
Answer: A.
(1) \((a + b)^{2}\) < \((a - b)^{2}\)
\(a^2 + 2ab + b^2 < a^2 - 2ab + b^2\)
\(4ab < 0\)
\(ab<0\)
Sufficient.
(2) a = b. If a = b = 0, then ab = 0 but if a = b = 1, then ab = 1 > 0. Not sufficient.
Answer: A.
Just noticed - statements contradict here. ab<0 and a=b cannot simultaneously be true. So, the question is flawed: On the GMAT, two data sufficiency statements always provide TRUE information and these statements NEVER contradict each other or the stem.
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