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Is ax = 3 - bx? (1) x(a + b) = 3 (2) a = b = 1.5 and x = 1

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Is ax = 3 - bx? (1) x(a + b) = 3 (2) a = b = 1.5 and x = 1 [#permalink]

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New post Updated on: 29 Mar 2018, 21:18
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Is ax = 3 - bx?

(1) x(a + b) = 3

(2) a = b = 1.5 and x = 1

Originally posted by grantcke on 12 Oct 2016, 00:27.
Last edited by Bunuel on 29 Mar 2018, 21:18, edited 2 times in total.
RENAMED THE TOPIC.
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Re: Is ax = 3 - bx? (1) x(a + b) = 3 (2) a = b = 1.5 and x = 1 [#permalink]

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New post 12 Oct 2016, 00:36
1
Is ax=3-bx?

(1) x(a+b)=3 --> open the brackets: ax + bx = 3 --> re-arrange: ax = 3 - bx. Sufficient.

(2) a=b=1.5 and x=1 --> ax = 1.5*1 = 1.5 and 3 - bx = 3 - 1.5*1 = 1.5 --> LHS = RHS. Sufficient.

Answer: D.

P.S. Please read and follow: is-ax-3-bx-1-x-a-b-3-2-a-b-1-5-and-x-1-i-thought-61999.html Pay attention to rule #3. Thank you.
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Re: Is ax = 3 - bx? (1) x(a + b) = 3 (2) a = b = 1.5 and x = 1 [#permalink]

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New post 29 Aug 2017, 03:57
grantcke wrote:
Is ax=3-bx?

(1) x(a+b)=3

(2) a=b=1.5 and x=1

Is \(ax=3-bx\)

Rearranging the question we get;

\(ax + bx =3\)

\(x(a + b) = 3\)

Therefore we need to find If \(x(a + b) = 3\)

(1) \(x(a+b)=3\)

Statement I is Sufficient.

(2) \(a=b=1.5\) and \(x=1\)

\(x(a + b) = 3\)

\(1(1.5 + 1.5) = 3\)

\(3 = 3\) ------- (LHS \(=\) RHS)

Statement II is Sufficient.

Answer (D)...
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Re: Is ax = 3 - bx? (1) x(a + b) = 3 (2) a = b = 1.5 and x = 1 [#permalink]

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New post 29 Mar 2018, 18:15
Bunuel chetan2u niks18 amanvermagmat

Is below approach valid?

Is ax=3-bx?

Question stem can be simplified to:

a = 3 - b provided x is not equal to zero.

Quote:
(1) x(a+b)=3

Either of terms on RHS can NOT be equal to zero.
Suff.


Quote:
(2) a=b=1.5 and x=1

We have values for all three unknown in this linear equation.
Clearly suff.
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Re: Is ax = 3 - bx? (1) x(a + b) = 3 (2) a = b = 1.5 and x = 1 [#permalink]

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New post 29 Mar 2018, 19:43
adkikani wrote:
Bunuel chetan2u niks18 amanvermagmat

Is below approach valid?

Is ax=3-bx?

Question stem can be simplified to:

a = 3 - b provided x is not equal to zero.

Quote:
(1) x(a+b)=3

Either of terms on RHS can NOT be equal to zero.
Suff.


Quote:
(2) a=b=1.5 and x=1

We have values for all three unknown in this linear equation.
Clearly suff.


Hi adkikani

The highlighted part is incorrect

ax-3=bx, you cannot divide by x on both sides. You will have to rearrange the terms

So ax-3=bx can be written as ax-bx=3, hence x(a-b)=3
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Re: Is ax = 3 - bx? (1) x(a + b) = 3 (2) a = b = 1.5 and x = 1 [#permalink]

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New post 29 Mar 2018, 21:16
Sooooooooo easy.

First simplify the given equation from the question.
You will find statement one.
Therefore st1 sufficient
St.2 just substitute. Sufficient

D

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Re: Is ax = 3 - bx? (1) x(a + b) = 3 (2) a = b = 1.5 and x = 1   [#permalink] 29 Mar 2018, 21:16
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