DavidTutorexamPAL wrote:
Archit3110 wrote:
DavidTutorexamPAL wrote:
The answer is A.
1) This is true only for 0.
(any positive number will give 0 on the left side and a positive number on the right. and negative number will give a positive number on the left and 0 on the right).
Sufficient!
2) this is true for both x=0 (an even number) and x=1 (an odd number). insufficient!
@DavidTutorexamPAL
for stament 2:
sqrtk = k is given
and we can say
sqrtk= sqrtk * sqrtk
OR
1=sqrtk
or k= +/-1 .. which is in sufficient..
I am not sure why have you said that
"2) this is true for both x=0 (an even number) and x=1 (an odd number). insufficient!"
Not sure I understand the question...
The equation in 2) is indeed true for 1 and -1, as you mention, but it is also true for 0 (root0=0). Thus, k can be either even (0) or odd (1, -1), and this statement is insufficient.
Is this clearer?[/quote]
DavidTutorexamPAL:
Yes i did get that it would be true for both 0, +/-1 .. what I meant was that if you simplify stmt 2 you would get k = +/-1 only .. not 0 ..
In DS my approach is usually to simplify the given relation than plug in values..
anyways statement 2 is in sufficient ... thanks for replying..