DavidTutorexamPAL wrote:

Archit3110 wrote:

DavidTutorexamPAL wrote:

The answer is A.

1) This is true only for 0.

(any positive number will give 0 on the left side and a positive number on the right. and negative number will give a positive number on the left and 0 on the right).

Sufficient!

2) this is true for both x=0 (an even number) and x=1 (an odd number). insufficient!

@DavidTutorexamPAL

for stament 2:

sqrtk = k is given

and we can say

sqrtk= sqrtk * sqrtk

OR

1=sqrtk

or k= +/-1 .. which is in sufficient..

I am not sure why have you said that

"2) this is true for both x=0 (an even number) and x=1 (an odd number). insufficient!"

Not sure I understand the question...

The equation in 2) is indeed true for 1 and -1, as you mention, but it is also true for 0 (root0=0). Thus, k can be either even (0) or odd (1, -1), and this statement is insufficient.

Is this clearer?[/quote]

DavidTutorexamPAL:

Yes i did get that it would be true for both 0, +/-1 .. what I meant was that if you simplify stmt 2 you would get k = +/-1 only .. not 0 ..

In DS my approach is usually to simplify the given relation than plug in values..

anyways statement 2 is in sufficient ... thanks for replying..

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