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Is n < 0? (1) m < n (2) -n < m

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Is n < 0? (1) m < n (2) -n < m  [#permalink]

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New post Updated on: 11 Sep 2018, 20:23
2
00:00
A
B
C
D
E

Difficulty:

  45% (medium)

Question Stats:

53% (01:36) correct 47% (01:47) wrong based on 16 sessions

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Is n < 0?

(1) m < n
(2) -n < m


As per me , neither of the statements are sufficient to answer the questions.
If i combine both the statements then i get -n<m<-n. This again does not answers if n <0 or not.

Originally posted by divyajoshi12 on 11 Sep 2018, 10:45.
Last edited by Bunuel on 11 Sep 2018, 20:23, edited 1 time in total.
Renamed the topic and edited the question.
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Re: Is n < 0? (1) m < n (2) -n < m  [#permalink]

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New post 11 Sep 2018, 10:55
divyajoshi12 wrote:
Is n<0? 1) m<n 2) -n<m


As per me , neither of the statements are sufficient to answer the questions.
If i combine both the statements then i get -n<m<-n. This again does not answers if n <0 or not.


statement (1) is not sufficient. It is obvious.

Now consider statement(2). m > -n
implies m + n > 0
now m+ n >0 is possible for three possible cases.
case 1) m<0 and n>0 and |n| > |m|
case 2) m>0 and n >0
case 3) m>0 and n<0 and |n|<|m|

so statement (2) alone is not sufficient.

Now combining statement (1) and statement (2), case (2) and case (3) are eleimnated since m<n .

only possibility is case 1) m<0 and n>0 and |n|>|m| and hence answer is c
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Re: Is n < 0? (1) m < n (2) -n < m  [#permalink]

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New post 11 Sep 2018, 10:58
As we do not know m, the statements are individually insufficient.
Combining 1) and 2);
1)m<n
2)-n<m or n>-m or -m<n
m-m<2n or 0<n
So C is the answer.
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Re: Is n < 0? (1) m < n (2) -n < m   [#permalink] 11 Sep 2018, 10:58
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