GMAT Changed on April 16th - Read about the latest changes here

 It is currently 27 May 2018, 21:52

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Is n/18 an integer?

Author Message
TAGS:

### Hide Tags

Manager
Joined: 28 Jan 2006
Posts: 116

### Show Tags

29 Aug 2006, 14:07
6
KUDOS
46
This post was
BOOKMARKED
00:00

Difficulty:

95% (hard)

Question Stats:

25% (01:11) correct 75% (00:53) wrong based on 1141 sessions

### HideShow timer Statistics

Is n/18 an integer?

(1) 5n/18 is an integer.

(2) 3n/18 is an integer.

SOLUTION IS HERE: is-n-18-an-integer-34415-20.html#p1341451

_________________

All the best!!
shinewine

VP
Joined: 02 Jun 2006
Posts: 1240

### Show Tags

29 Aug 2006, 14:33
7
KUDOS
4
This post was
BOOKMARKED
Q: n = 18 x k where k = integer.

S1: n = 18xm/5 where m = integer.

Therefore, n/18 = m/5 Not sufficient.

S2: n= 18 x s/ 3 where s = integer.

=> n/18 = s/3; Not sufficient.

S1 & S2:
n/18 = m/5
n/18 = s/3

or m/5 = s/3
or 3m = 5s

Which means m & s are multiples of both 5 and 3.

Therefore n/18 is an integer.

VP
Joined: 02 Jun 2006
Posts: 1240

### Show Tags

29 Aug 2006, 14:51
If n/18= 0 and n/18 = 1/5,

In one case, we get
5n/18 = 0 integer. n/18 => integer...

5n/18 =1 integer, n/18 => not integer...

I don't understand how its A?

X & Y wrote:
Getting A

St 1: Suff
St 2: Insuff
Manager
Joined: 09 Aug 2005
Posts: 72

### Show Tags

29 Aug 2006, 14:54
I've used just common sense here, since I'm not getting anywhere with traditional ways.

(A) St 1 is sufficient. Because, since 18 = 3*3*2, 5 and 18 have no factors in common.

Which means for 5n/18 to be an integer, n must be a multiple of 18!
Hence sufficient.

(B) is not sufficient because 3 and 18 have common factors, so n may be a multiple of 18, the only thing certain here is that it will be a multiple of 6. Therefore not sufficient.

MG
GMAT Instructor
Joined: 04 Jul 2006
Posts: 1253

### Show Tags

29 Aug 2006, 14:58
We don't know that n is an integer!
VP
Joined: 02 Jun 2006
Posts: 1240

### Show Tags

29 Aug 2006, 15:01
1
This post was
BOOKMARKED
Kevin,
Can you elaborate a little bit? I think I am losing my mind....can't seem to figure this out for some reason? Are you getting A too?

kevincan wrote:
We don't know that n is an integer!
Manager
Joined: 09 Aug 2005
Posts: 72

### Show Tags

29 Aug 2006, 16:57
Ah so then I'm wrong....

i.e. N can be 18/5 to begin with... thats true.

But Haas, going back to your solution, if N is a multiple of both 5 and 3, how can you be sure it is a multiple of 18??

It only proves it can be a multiple of 15. It still may or may not be a multiple of 18.

Does that mean hte answer is E?

MG
VP
Joined: 28 Mar 2006
Posts: 1330

### Show Tags

29 Aug 2006, 20:20
shinewine wrote:
Is n/18 an integer?

(1) 5n/18 is an integer.

(2) 3n/18 is an integer.

n/18 can be x/5 in 1 and x/3 in 2 where x is some number

taking both into consideration we get nothing

E it is
Manager
Joined: 12 May 2006
Posts: 116

### Show Tags

29 Aug 2006, 23:53
1
This post was
BOOKMARKED
I believe it is A...

I think it was said before

stmnt1- 5 shares no common factors with 18. This means that N must be a direct factor of 18. Suff

stmnt2- Insuff for reasons explained above.
GMAT Instructor
Joined: 04 Jul 2006
Posts: 1253

### Show Tags

30 Aug 2006, 05:30
6
KUDOS
4
This post was
BOOKMARKED
(1) If 5n/18 is an integer, call it k, we know that n/18=k/5, which may or may not be an integer. NOT SUFF

(2) Similarly, if 3n/18 is an integer, call it m, we know that n/18= m/3, which may or may not be an integer NOT SUFF

(1) and (2): For some integers k and m, k/5=m/3 => 3k=5m =>k=5m/3.

Thus m is a multiple of 3, so n/18=m/3 is an integer SUFF
Director
Joined: 13 Nov 2003
Posts: 779
Location: BULGARIA

### Show Tags

30 Aug 2006, 05:40
(1) If 5n/18 is an integer, call it k, we know that n/18=k/5, which may or may not be an integer. NOT SUFF

If (5n/18)=k=>5n=18k=>n=(18k/5) since both n and k are INTEGERS then k is multiple of 5 and respectively n is a multiple of 18 and an INTEGER so A) is SUFF byitself,
Director
Joined: 28 Dec 2005
Posts: 729

### Show Tags

30 Aug 2006, 09:30
rdw28 wrote:
Kevincan,

There is no way possible that 5n/18 could be an integer if n were not an integer.

There is: consider n/18 = 1/5. Then 5 (n/18) = 5. (1/5) = 1.
Current Student
Joined: 28 Dec 2004
Posts: 3293
Location: New York City
Schools: Wharton'11 HBS'12

### Show Tags

30 Aug 2006, 10:19
5
KUDOS
2
This post was
BOOKMARKED
shinewine wrote:
Is n/18 an integer?

(1) 5n/18 is an integer.

(2) 3n/18 is an integer.

lets see..the stem says nothing about N being an integer...soo

1) 5 N/18 - integer...well N can be an integer multiple of 18 or it can be 18M/5 where M is an integer not divisible by 5...Insuff

2) simplify this to N/6, so N has prime factors 2 and 3, we still dont know if it has enuff 3s or not...but we noe for sure that N is not a fraction...

combining them we now now that N is not a fraction and that its a mutliple of 18....

C it is...

Answer woud be A if we are told in the stem that N is an integer..
Intern
Joined: 29 Dec 2012
Posts: 17

### Show Tags

30 Nov 2013, 15:17
5n/18=integer
If we consider n=18M/5 Where M can be number which is not divisible by 5 .. If we consider this case,
then 5(18M/5)/18=integer is not fulfilling sinceM is not integer , to fulfill this M must be integer hence N is integer..

Thus A should be OA.
Verbal Forum Moderator
Joined: 10 Oct 2012
Posts: 620
Re: Is n/18 an integer? [#permalink]

### Show Tags

01 Dec 2013, 00:30
2
KUDOS
1
This post was
BOOKMARKED
shinewine wrote:
Is n/18 an integer?

(1) 5n/18 is an integer.

(2) 3n/18 is an integer.

From F.S 1, we know that $$\frac{5n}{18}$$ is an integer. For$$\frac{n}{18} = 1$$, we have a YES. Again, for $$\frac{n}{18} = \frac{1}{5}$$ , we have a NO.Insufficient.

From F.S 2, we know that$$\frac{3n}{18}$$ is an integer. For $$\frac{n}{18} = 1$$, we have a YES,but for $$\frac{n}{18} = \frac{1}{3}$$ , we have a NO.Insufficient.

Taking both together, we know that from F.S 1, either$$\frac{n}{18} = \frac{k}{5}$$ or $$\frac{n}{18} = p$$ , where k,p are integers and k and 5 are co-primes.

But, for $$\frac{n}{18} = \frac{k}{5}$$, $$\frac{3*n}{18} = \frac{3*k}{5}$$ and it will not be an integer. Thus, $$\frac{n}{18} = p$$ can the only be form possible.

C.
_________________
Director
Joined: 25 Apr 2012
Posts: 702
Location: India
GPA: 3.21
Re: Is n/18 an integer? [#permalink]

### Show Tags

03 Dec 2013, 01:07
7
KUDOS
4
This post was
BOOKMARKED
shinewine wrote:
Is n/18 an integer?

(1) 5n/18 is an integer.

(2) 3n/18 is an integer.

We need to find whether n is a multiple of 18 or n= 18I for some integer I

St 1: 5n/18= Integer or n = 18*Integer/ 5
Now if Integer = 2, then n =7.2 and n/18 is not an integer

but integer = 5 then n = 18 and 18/18 is an integer

------Possible values of n = 3.6,7.2,10.8,14.4,18......

So A and D ruled out

St 2: we see that n is a multiple of 6 so possible values of n =6,12,18......
If n= 6 then n/18 is not an integer but if n=18 then n/18 is an integer.
So option B ruled out

Combining we get possible values of n =18,36,54 and so on

Hence Ans C
_________________

“If you can't fly then run, if you can't run then walk, if you can't walk then crawl, but whatever you do you have to keep moving forward.”

Intern
Joined: 06 Feb 2014
Posts: 3
Re: Is n/18 an integer? [#permalink]

### Show Tags

11 Feb 2014, 12:53
1
KUDOS
From 1: 5n/18 = a (an integer) => n/18 = a/5 (we cannot be sure if this is an interger)
From 2: 3n/18 = b (an integer) => n/18 = b/3 (we cannot be sure if this is an interger)
Combining 1&2:
2*(statement 2) - (statement 1) => 6n/18 - 5n/18 = 18*2*b - 18*a
=> n/18 = 18(2b-a) {this we know for sure is an integer}
Thus, Option C
Intern
Joined: 13 Feb 2014
Posts: 3
Re: Is n/18 an integer? [#permalink]

### Show Tags

13 Feb 2014, 20:12
3
KUDOS
1
This post was
BOOKMARKED
It's C, but I think this is as clear as it can be explained:

S1: $$\frac{5n}{18}=K1$$ (Letting K1 be an integer)

Then, isolating n we get $$n=\frac{18K1}{5}$$

Going back to the original question if n is divisible by 18, based on this answer is "Maybe" (provided that K1 is a multiple of 5)

Insufficient.

S2: $$\frac{3n}{18}=K2$$ (Letting K2 be an integer)

Then, isolating n we get $$n=\frac{18K2}{3}$$, reducing $$n=6K2$$

Going back to the original question if n is divisible by 18, based on this answer is "Maybe" (Provided that K2 is a multiple of 3)

Insufficient.

S1 & S2: We will make the expressions for n equal:

$$\frac{18K1}{5}=6K2$$, simplifying
$$K2=\frac{3K1}{5}$$
The key here is understanding that K1 and K2 MUST be integers. As such, the "Maybes" of S1 and S2 are proven to be true.
From the expression above, K2 is a multiple of 3 and K1 is a multiple of 5.

This is perhaps an extended explanation, but I think is clear enough.
Director
Affiliations: CrackVerbal
Joined: 03 Oct 2013
Posts: 518
Location: India
GMAT 1: 780 Q51 V46
Re: Is n/18 an integer? [#permalink]

### Show Tags

13 Feb 2014, 23:30
1
KUDOS
3
This post was
BOOKMARKED
shinewine wrote:
Is n/18 an integer?

(1) 5n/18 is an integer.

(2) 3n/18 is an integer.

Statement I is insufficient:

n = 36 (YES)
n = 18/5 (NO)

Statement II is insufficient:

n = 36 (YES)
n = 6 (NO)

Combining is sufficient:

Since 5 and 3 are co primes to each other n will have to be a multiple of 18 for 5n/18 and 3n/18 to be an integer.

_________________

Register for CrackVerbal MBA Achiever's Summit here -
http://crackverbal.com/mba-summit-2018

Enroll for our GMAT Trial Course here -
http://gmatonline.crackverbal.com/

Manager
Joined: 28 Aug 2013
Posts: 92
Location: India
Concentration: Operations, Marketing
GMAT Date: 08-28-2014
GPA: 3.86
WE: Supply Chain Management (Manufacturing)
Re: Is n/18 an integer? [#permalink]

### Show Tags

08 Mar 2014, 07:40
3
This post was
BOOKMARKED
ndiaz17 wrote:
It's C, but I think this is as clear as it can be explained:

S1: $$\frac{5n}{18}=K1$$ (Letting K1 be an integer)

Then, isolating n we get $$n=\frac{18K1}{5}$$

Going back to the original question if n is divisible by 18, based on this answer is "Maybe" (provided that K1 is a multiple of 5)

Insufficient.

S2: $$\frac{3n}{18}=K2$$ (Letting K2 be an integer)

Then, isolating n we get $$n=\frac{18K2}{3}$$, reducing $$n=6K2$$

Going back to the original question if n is divisible by 18, based on this answer is "Maybe" (Provided that K2 is a multiple of 3)

Insufficient.

S1 & S2: We will make the expressions for n equal:

$$\frac{18K1}{5}=6K2$$, simplifying
$$K2=\frac{3K1}{5}$$
The key here is understanding that K1 and K2 MUST be integers. As such, the "Maybes" of S1 and S2 are proven to be true.
From the expression above, K2 is a multiple of 3 and K1 is a multiple of 5.

This is perhaps an extended explanation, but I think is clear enough.

Umm...I am having 1 query ...very simple

I don't want to get into such complex solution my only query is ...

S 1 : tells 5n/18 is an integer - 5 is prime, hence it must be clear that "n" will be divisible by 18 , in that case n/18 will be an integer .

then why some folks are not mentioning A wrong ??

Is i am missing any logic plz explain ?
_________________

G-prep1 540 --> Kaplan 580-->Veritas 640-->MGMAT 590 -->MGMAT 2 640 --> MGMAT 3 640 ---> MGMAT 4 650 -->MGMAT 5 680 -- >GMAT prep 1 570

Give your best shot...rest leave upto Mahadev, he is the extractor of all negativity in the world !!

Re: Is n/18 an integer?   [#permalink] 08 Mar 2014, 07:40

Go to page    1   2    Next  [ 37 posts ]

Display posts from previous: Sort by