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Is OG wrong in this question's answer?

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Is OG wrong in this question's answer?  [#permalink]

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New post 12 Oct 2018, 15:45
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There are 5 cars to be displayed in 5 parking spaces, with all the cars facing the same direction. Of the 5 cars, 3 are red, 1 is blue, and 1 is yellow. If the cars are identical except for color, how many different display arrangements of the 5 cars are possible?
(A) 20 (B) 25 (C) 40 (D) 60 (E) 125

The official answer is 20 which can be arrived by the formula 5!/3!. However, the question refers to direction also. My initial answer was 60 because I assumed that the cars can be arranged in opposite direction also?

Am I stretching my imagination?
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Re: Is OG wrong in this question's answer?  [#permalink]

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New post 12 Oct 2018, 20:38
PLUTO wrote:
There are 5 cars to be displayed in 5 parking spaces, with all the cars facing the same direction. Of the 5 cars, 3 are red, 1 is blue, and 1 is yellow. If the cars are identical except for color, how many different display arrangements of the 5 cars are possible?
(A) 20 (B) 25 (C) 40 (D) 60 (E) 125

The official answer is 20 which can be arrived by the formula 5!/3!. However, the question refers to direction also. My initial answer was 60 because I assumed that the cars can be arranged in opposite direction also?

Am I stretching my imagination?


With the phrase "with all the cars facing the same direction" , they already have restricted the arrangement in 1 direction.
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Re: Is OG wrong in this question's answer?  [#permalink]

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New post 12 Oct 2018, 21:05
u1983 wrote:
PLUTO wrote:
There are 5 cars to be displayed in 5 parking spaces, with all the cars facing the same direction. Of the 5 cars, 3 are red, 1 is blue, and 1 is yellow. If the cars are identical except for color, how many different display arrangements of the 5 cars are possible?
(A) 20 (B) 25 (C) 40 (D) 60 (E) 125

The official answer is 20 which can be arrived by the formula 5!/3!. However, the question refers to direction also. My initial answer was 60 because I assumed that the cars can be arranged in opposite direction also?

Am I stretching my imagination?


With the phrase "with all the cars facing the same direction" , they already have restricted the arrangement in 1 direction.


But "same direction" doesn't have to be in just one direction. The direction can be same for all the cars in multiple cases (2 in this case).

I think the important part here is the word "arrangement", which I think in this case refers only to the arrangement of colors because everything else is identical according to the question stem. So even if you consider multiple directions, the color arrangement would still be repititive.
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Re: Is OG wrong in this question's answer?  [#permalink]

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New post 12 Oct 2018, 22:46
PLUTO wrote:
There are 5 cars to be displayed in 5 parking spaces, with all the cars facing the same direction. Of the 5 cars, 3 are red, 1 is blue, and 1 is yellow. If the cars are identical except for color, how many different display arrangements of the 5 cars are possible?
(A) 20 (B) 25 (C) 40 (D) 60 (E) 125

The official answer is 20 which can be arrived by the formula 5!/3!. However, the question refers to direction also. My initial answer was 60 because I assumed that the cars can be arranged in opposite direction also?

Am I stretching my imagination?


Discussed here: https://gmatclub.com/forum/there-are-5- ... 88100.html
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Re: Is OG wrong in this question's answer?   [#permalink] 12 Oct 2018, 22:46
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