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10 Dec 2018, 03:11
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C
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Difficulty:
45%
(medium)
Question Stats:
61% (01:47) correct
39%
(01:32)
wrong
based on 131
sessions
History
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Not Attempted Yet
Is the two-digit positive integer, RM, a multiple of 7?
(1) R + M = 13
(2) R is divisible by 3
(1) R + M = 13
(2) R is divisible by 3
eswarchethu135
10 Dec 2018, 03:41
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(1) R + M = 13
R = 4 and M = 9
RM is divisible by 7.
R = 5 and M = 8
RM is not divisible by 7.
INSUFFICIENT
(2) R is divisible by 3
R = 6 or 9
M = 7 or 4
RM = 67 or 94. Both are not multiples of 7. SUFFICIENT.
OPTION: B
R = 4 and M = 9
RM is divisible by 7.
R = 5 and M = 8
RM is not divisible by 7.
INSUFFICIENT
(2) R is divisible by 3
R = 6 or 9
M = 7 or 4
RM = 67 or 94. Both are not multiples of 7. SUFFICIENT.
OPTION: B
Updated on: 10 Dec 2018, 09:23
Originally posted by Archit3110 on 10 Dec 2018, 05:45.
Last edited by Archit3110 on 10 Dec 2018, 09:23, edited 1 time in total.
Last edited by Archit3110 on 10 Dec 2018, 09:23, edited 1 time in total.
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Bunuel
from 1:
R,M can be
( 49,94,58,85,67,76)
so 49 is divisible by 7 so in sufficient
from 2: r divisible by 3 so RM can be ( 67 or 94) both are not divisible by 7 or 63 divisible by 7
insufficient
Combining 1 & 2 we get 94,67 both are in sufficient ,
so RM is not multiple of 7
IMO C
