alphonsa wrote:

Is x^(k+1) > x^k ?

(1) |x| > 1

(2) k+1 is divisible by 6

source: 4gmat

Simplifying the prompt we get,

\(x^k*(x - 1) > 0\)

Hence , we have 3 cases

i) x > 0, k - odd/even, then the given Expression is > 0

ii) x < 0, k - odd, then the given Expression is > 0

iii)x < 0, k - even, then the given Expression is < 0

Statement 1 - |x| > 1, hence x < -1 or x > 1

However, No information about k

Statement 1 alone is Not Sufficient.

Statement 2: (k + 1) = 6p, hence k = 6p - 1 = (even) - 1.

k = odd

However, No information about x

Statement 2 alone is Not Sufficient.

Combining both, we get x > 1 or x < -1 & k = odd

We can see from the 3 cases above, the given conditions satisfy cases i) & ii).

Hence the given expression > 0

Combining is Sufficient.

Hence Answer is C.

Thanks,

GyM

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