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Is x - y < 0 ? (1) 9y - 6x > 0 (2) xy > 0

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Is x - y < 0 ? (1) 9y - 6x > 0 (2) xy > 0  [#permalink]

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New post Updated on: 07 Jun 2020, 01:09
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  25% (medium)

Question Stats:

79% (01:35) correct 21% (01:49) wrong based on 56 sessions

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Is \(x - y < 0\) ?


(1) \(9y - 6x > 0\)

(2) \(xy > 0\)

Originally posted by Codebug4it on 06 Jun 2020, 15:07.
Last edited by Bunuel on 07 Jun 2020, 01:09, edited 1 time in total.
Renamed the topic.
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Re: Is x - y < 0 ? (1) 9y - 6x > 0 (2) xy > 0  [#permalink]

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New post 06 Jun 2020, 18:49
2
Codebug4it wrote:
Is \(x - y < 0\) ?

(1) \(9y - 6x > 0\)
(2) \(xy > 0\)


The question is - Is x-y<0 or x<y?

1) 9y-6x>0........3y>2x....y>2x/3
y=5 and x=6......y<x...answer is NO
y=10 and x=6.......y>x...answer is YES

2) xy>0
Both x and y have same sign.

Combined..
y>2x/3, but y can be 5x/6 or 5x
The statement I still stands
Insuff

E
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Re: Is x - y < 0 ? (1) 9y - 6x > 0 (2) xy > 0  [#permalink]

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New post 06 Jun 2020, 23:35
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Attachment:
Untitled.png
Untitled.png [ 6.53 KiB | Viewed 340 times ]


\(9y - 6x > 0\) represents the region above the line y=(2/3)x

xy>0 represents the first and third quadrant.

common region (in light yellow) lies both above and below y=x line.

E



Codebug4it wrote:
Is \(x - y < 0\) ?

(1) \(9y - 6x > 0\)
(2) \(xy > 0\)
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Re: Is x - y < 0 ? (1) 9y - 6x > 0 (2) xy > 0  [#permalink]

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New post 07 Jun 2020, 01:07
Codebug4it wrote:
Is \(x - y < 0\) ?

(1) \(9y - 6x > 0\)
(2) \(xy > 0\)


Question: Is x < y?

Statement 1: 9y - 6x > 0

i.e. 3x > 2y
i.e. x > 0.66y

i,e. x may be greater than y or less than y hence

NOT SUFFICIENT

Statement 2: x*y>0

i.e. x and y have same signs and are non zero but the comparison between values is still absent hence

NOT SUFFICIENT

COmbining the statements
x*y > 0 and x > (2/3)y

Case 1: y = 3 and x = 2.5 i.e x < y
Case 2: y = 3 and x = 4 i.e x > y

NOT SUFFICIENT

Answer: Option E
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Re: Is x - y < 0 ? (1) 9y - 6x > 0 (2) xy > 0  [#permalink]

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New post 07 Jun 2020, 01:23
Codebug4it wrote:
Is \(x - y < 0\) ?


(1) \(9y - 6x > 0\)

(2) \(xy > 0\)


target is x<y
#1
9y>6x
3y>2x
we can have x=y =1
or y=1 and x= 2
insufficient
#2
xy>0
means both are of same sign insufficient
from 1 &2
nothing can be determined
OPTION E
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Re: Is x - y < 0 ? (1) 9y - 6x > 0 (2) xy > 0  [#permalink]

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New post 07 Jun 2020, 01:37
Codebug4it wrote:
Is \(x - y < 0\) ?


(1) \(9y - 6x > 0\)

(2) \(xy > 0\)


Question can be rephrased : Is y > x ?


(1) \(9y - 6x > 0\)

\(9y > 6x\)............\(3y > 2x\)

Let y =1 & x =1.............Answer is No

let y =1 & x =1/2.............Answer is Yes

Insufficient

(2) [m]xy > 0[/m

Let y =1 & x =1.............Answer is No

let y =1 & x =1/2.............Answer is Yes

Insufficient

Combine 1 & 2

Take same examples above. Is is still Insufficient

Answer: E
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Re: Is x - y < 0 ? (1) 9y - 6x > 0 (2) xy > 0   [#permalink] 07 Jun 2020, 01:37

Is x - y < 0 ? (1) 9y - 6x > 0 (2) xy > 0

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