kshitizbansal92 wrote:

is x > y?

1) |x| >|y|

2) \(\frac{1}{4}\) x - \(\frac{1}{3}\) y >0

Great question. Here's how I solved it.

is x > y?Statement 1: |x| >|y| - Not Sufficient. Make x=2 and y=1, yes. Make x=-2 and y=-1, no.

Both of these options work for statement 1, but give different answers to the original question. So this statement has a "yes, no" answer. Therefore Not Sufficient.

Statement 2: \(\frac{1}{4}\)x - \(\frac{1}{3}\)y >0 - To make this one a little bit easier on the eyes, I multiplied both sides by the LCM just to eliminate fractions.

That gave me 3x - 4y > 0. Make x=2 and y=1 ----> 3(2) - 4(1) --> 6-4=2 --> 2>0. YES

Make x=-2 and y=-3 --> 3(-2) - 4(-3) --> -6+12=6 --> 6>0. NO

Both of these options for statement 2, but give different results for the original question. Therefore not sufficient.

Statement 1 and 2:

3x - 4y > 0 and

|x| >|y|x=2 and y=1. Works for both statements and answers the original question as YES.

x=-10 and y=-9. Works for both statements, answers the original question as NO.

Not Sufficient.

Answer E

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