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Is x+y+z a square of an integer? 1). Xyz (or x, y, and z) is

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Manager
Joined: 04 Sep 2006
Posts: 113
Is x+y+z a square of an integer? 1). Xyz (or x, y, and z) is  [#permalink]

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31 May 2009, 06:10
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Is x+y+z a square of an integer?
1). Xyz (or x, y, and z) is odd, and x is the least one.
2). X, y, and z are three different integers.

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Manager
Joined: 28 Jan 2004
Posts: 198
Location: India
Re: square of an integer  [#permalink]

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31 May 2009, 09:58
E....not enough info.
Pluggin numbers can easily show different outcomes.

Stmt. 1 --- tell all 3 are odd. Not suff.
Stmt 2 --- does not tells much.
Combining both - does not helps.
what is OA?
Manager
Joined: 08 Feb 2009
Posts: 139
Schools: Anderson
Re: square of an integer  [#permalink]

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31 May 2009, 10:00
Even after Combining both the statements, we only that there are three odd integers.

x = 1, y = 5, z = 3 $$\Rightarrow$$ the SUM is Square of an integer.
x = 3, y = 5, z = 7 $$\Rightarrow$$ the SUM is NOT Square of an integer.

Thus, both statements are INSUFFICIENT.

Senior Manager
Joined: 16 Jan 2009
Posts: 339
Concentration: Technology, Marketing
GMAT 1: 700 Q50 V34
GPA: 3
WE: Sales (Telecommunications)
Re: square of an integer  [#permalink]

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01 Jun 2009, 15:55
vcbabu wrote:
Is x+y+z a square of an integer?
1). Xyz (or x, y, and z) is odd, and x is the least one.
2). X, y, and z are three different integers.

Stmt 1: x, y, and z is odd, and x is the least one.

for x=3 y=3 z=3 x+y+z is a square of an integer
for x=1 y=3 z=7 x+y+z is not a square of an integer.

Stmt 1 INSUFFICIENT.

Stmt 2: X, y, and z are three different integers.

for x=1 y=3 z=5 x+y+z is a square of an integer.
for x=1 y=3 z=7 x+y+z is not a square of an integer.

Stmt 2 INSUFFICIENT.

Together , using diffenet , odd integers for x, y, and z is odd, and x is the least one.

for x=1 y=3 z=5 x+y+z is a square of an integer.
for x=1 y=3 z=7 x+y+z is not a square of an integer.

IMO E
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Lahoosaher

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Joined: 14 May 2009
Posts: 187
Re: square of an integer  [#permalink]

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01 Jun 2009, 21:07
vcbabu wrote:
Is x+y+z a square of an integer?
1). Xyz (or x, y, and z) is odd, and x is the least one.
2). X, y, and z are three different integers.

Question:$$(X+Y+Z=M^{2}$$ where M is any integer?$$)$$

Question:$$(sqrt{X+Y+Z}=M$$ where M is any integer?$$)$$

$$X=1$$, $$Y=3$$, $$Z=5$$

$$X+Y+Z=9=3^2$$

==>YES

$$X=1$$, $$Y=3$$, $$Z=7$$

$$X+Y+Z=11$$

==> NO

YES & NO==>INSUFFICIENT

Final Answer, $$E$$.

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.

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Re: square of an integer &nbs [#permalink] 01 Jun 2009, 21:07
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