Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized for You
we will pick new questions that match your level based on your Timer History
Track Your Progress
every week, we’ll send you an estimated GMAT score based on your performance
Practice Pays
we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
Re: Is xy < 6 (1) x < 3 and y < 2 (2) 1/2 < x < 2/3 and y^2 < 64
[#permalink]
Show Tags
24 Oct 2009, 05:46
5
2
IMO B.
stmt1: if both x and y are negative such that the product of their absolute values is > 6 then xy>6. eg. x=-8, y=-3
stmt2: x is +ve, -8<y<8. Let us take max value of x =2/3 and max value of y=8, the product is <6. Now, let us take max value of x=2/3 and a negative value of y=-8, the product is -ve and hence < 6. One more try, take x=2/3 and y=5, the product is <6.
Re: Is xy < 6 (1) x < 3 and y < 2 (2) 1/2 < x < 2/3 and y^2 < 64
[#permalink]
Show Tags
06 Nov 2010, 21:50
3
2
Geronimo wrote:
I don't really agree with OG's answer. What about you ?
Is xy<6 ? (1) x<3 and y<2 (2) 1/2 < x < 2/3 and y^2<64
Is \(xy<6\)?
(1) \(x<3\) and \(y<2\) --> now, if both \(x\) and \(y\) are equal to zero then \(xy=0<6\) and the answer will be YES but if both \(x\) and \(y\) are small enough negative numbers, for example -10 and -10 then \(xy=100>6\) and the answer will be YES. Not sufficient.
(2) \(\frac{1}{2}<x<\frac{2}{3}\) and \(y^2<64\), which is equivalent to \(-8<y<8\) (not y<8, y>-8. as written above) --> even if we take the boundary values of \(x\) and \(y\) to maixmize their product we'll get: \(xy=\frac{2}{3}*8\approx{5.3}<6\), so the answer to the question "is \(xy<6\)" will always be YES. Sufficient.
Re: Is xy < 6 (1) x < 3 and y < 2 (2) 1/2 < x < 2/3 and y^2 < 64
[#permalink]
Show Tags
28 Feb 2011, 02:56
Clearly 1) is sufficient. It says x is less than 3 and y is less than 2 so product can not be greater than 6.
Lets examine 2) x lies between 1/2 and 2/3 and y^2 is less than 64, or y lies within (-8,8). On the extreme, xy can be just below 2/3*8 or ~5.33 so it will always be less than 6. Sufficient.
Re: Is xy < 6 (1) x < 3 and y < 2 (2) 1/2 < x < 2/3 and y^2 < 64
[#permalink]
Show Tags
28 Feb 2011, 03:05
beyondgmatscore wrote:
Clearly 1) is sufficient. It says x is less than 3 and y is less than 2 so product can not be greater than 6.
Lets examine 2) x lies between 1/2 and 2/3 and y^2 is less than 64, or y lies within (-8,8). On the extreme, xy can be just below 2/3*8 or ~5.33 so it will always be less than 6. Sufficient.
Answer should be D.
Statement (1) is not sufficient: if x and y are small enough negative numbers, for example -10 and -10 then xy=100>6. So answer is B, not D.
_________________
Re: Is xy < 6 (1) x < 3 and y < 2 (2) 1/2 < x < 2/3 and y^2 < 64
[#permalink]
Show Tags
28 May 2013, 15:14
Bunuel wrote:
mymbadreamz wrote:
I didn't understand this one. could someone please explain why C is not the answer? thanks.
Is \(xy<6\)?
(1) \(x<3\) and \(y<2\) --> now, if both \(x\) and \(y\) are equal to zero then \(xy=0<6\) and the answer will be YES but if both \(x\) and \(y\) are small enough negative numbers, for example -10 and -10 then \(xy=100>6\) and the answer will be NO. Not sufficient.
(2) \(\frac{1}{2}<x<\frac{2}{3}\) and \(y^2<64\), which is equivalent to \(-8<y<8\) --> even if we take the boundary values of \(x\) and \(y\) to maixmize their product we'll get: \(xy=\frac{2}{3}*8\approx{5.3}<6\), so the answer to the question "is \(xy<6\)?" will always be YES. Sufficient.
Answer: B.
i dont understand i put A....i could answer the question with that information. N why are we letting x times y = to 0 why cant we let it be equal to 1 or 2?
if a number times a number is less than 6......cant we just say use 1?
Re: Is xy < 6 (1) x < 3 and y < 2 (2) 1/2 < x < 2/3 and y^2 < 64
[#permalink]
Show Tags
28 May 2013, 15:23
1
madzstar wrote:
Bunuel wrote:
mymbadreamz wrote:
I didn't understand this one. could someone please explain why C is not the answer? thanks.
Is \(xy<6\)?
(1) \(x<3\) and \(y<2\) --> now, if both \(x\) and \(y\) are equal to zero then \(xy=0<6\) and the answer will be YES but if both \(x\) and \(y\) are small enough negative numbers, for example -10 and -10 then \(xy=100>6\) and the answer will be NO. Not sufficient.
(2) \(\frac{1}{2}<x<\frac{2}{3}\) and \(y^2<64\), which is equivalent to \(-8<y<8\) --> even if we take the boundary values of \(x\) and \(y\) to maixmize their product we'll get: \(xy=\frac{2}{3}*8\approx{5.3}<6\), so the answer to the question "is \(xy<6\)?" will always be YES. Sufficient.
Answer: B.
i dont understand i put A....i could answer the question with that information. N why are we letting x times y = to 0 why cant we let it be equal to 1 or 2?
if a number times a number is less than 6......cant we just say use 1?
On DS questions when plugging numbers, goal is to prove that the statement is not sufficient. So we should try to get a YES answer with one chosen number(s) and a NO with another.
Now, for x=y=0 we got an YES answer and for x=y=-10 we got a NO answer, thus the statement is NOT sufficient.
Of course we could use some other numbers to get an YES and a NO answers to prove that the statement is not sufficient: x=y=0 and x=y=-10 are just examples of many possible sets.
Re: Is xy < 6 (1) x < 3 and y < 2 (2) 1/2 < x < 2/3 and y^2 < 64
[#permalink]
Show Tags
Updated on: 01 Feb 2014, 14:04
4
Statement (1)
We are given x < 3 and y < 2 ; no lower bound specified for either of the variables. x and y could be x=-3 and y=-2 we get xy=6 or they could be very small negative numbers then xy would be much greater than 6. On the other hand x=1 y=1 which results in xy=1 which is smaller than 6 so Statement (1) is not sufficient
Statement (2)
y^2 < 64 can be rewritten as -8< y <8 , Since x is positive, we can test the extremes without worrying about changing the direction of the inequality sign -8*(2/3) < xy < 8*(2/3)
-5.3333 < xy < 5.333 So we can answer the question "Is xy<6" with the Statement (2) ALONE.
Re: Is xy < 6 (1) x < 3 and y < 2 (2) 1/2 < x < 2/3 and y^2 < 64
[#permalink]
Show Tags
19 Oct 2016, 06:07
2
1
Geronimo wrote:
Is xy < 6
(1) x < 3 and y < 2
(2) 1/2 < x < 2/3 and y^2 < 64
We need to determine whether the product of x and y is less than 6.
Statement One Alone
x < 3 and y < 2
Using the information in statement one we do not have enough information to determine whether the product of x and y is less than 6. For example, if x = -4 and y = -2, the product of x and y is 8, which is greater than 6. However, if x = 0 and y = 0, the product of x and y is 0, which is less than 6. We can eliminate answer choices A and D.
Statement Two Alone
1/2 < x < 2/3 and y^2 < 64
Using the information in statement two, we see that x is less than 2/3 and that y is less than 8. Thus, the maximum product of x and y is less than (2/3)(8) = 16/3, which is less 5.33 and thus less than 6. Since the maximum product of x and y is less than 6, statement two is sufficient to answer the question. Note that we did not even consider the case when -8 < y < 0 because in that case, xy will be negative and thus will be less than 6.
close
67% (01:44) correct 
