It is currently 23 Sep 2017, 05:55

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

isosceles triangle

  post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
Intern
Intern
avatar
Joined: 06 Aug 2007
Posts: 31

Kudos [?]: 43 [0], given: 19

Location: Montreal
isosceles triangle [#permalink]

Show Tags

New post 04 Jun 2009, 10:13
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Hello there,

I would like to ask you a question that I got wrong. My brain has just stopped, please help;

The perimeter of an isosceles triangle is 16 + 16root2
What is the length on the hypotenuse?

Kudos [?]: 43 [0], given: 19

Senior Manager
Senior Manager
User avatar
Joined: 16 Jan 2009
Posts: 356

Kudos [?]: 228 [0], given: 16

Concentration: Technology, Marketing
GMAT 1: 700 Q50 V34
GPA: 3
WE: Sales (Telecommunications)
Re: isosceles triangle [#permalink]

Show Tags

New post 04 Jun 2009, 10:28
for a right isosceles triangle , the perimeter is
2a+a(sqrt)2
where a(sqrt)2 represents the hypot.

are you sure the problem is correct?
_________________

Lahoosaher

Kudos [?]: 228 [0], given: 16

1 KUDOS received
Intern
Intern
avatar
Joined: 27 Apr 2009
Posts: 12

Kudos [?]: 1 [1], given: 0

Re: isosceles triangle [#permalink]

Show Tags

New post 04 Jun 2009, 10:34
1
This post received
KUDOS
As we know the right angle triangle with two equal side (isosceles) has side ratio in 1:1:root2
so according to question , the perimeter is 16+16root2
so the sides are 8root2:8root2:16
so the hypotenuse is 16

Kudos [?]: 1 [1], given: 0

Senior Manager
Senior Manager
User avatar
Joined: 16 Jan 2009
Posts: 356

Kudos [?]: 228 [0], given: 16

Concentration: Technology, Marketing
GMAT 1: 700 Q50 V34
GPA: 3
WE: Sales (Telecommunications)
Re: isosceles triangle [#permalink]

Show Tags

New post 04 Jun 2009, 11:10
and I blame IPL for my low GmatPrep score!!!
Thanks bhatiasanju2002.
_________________

Lahoosaher

Kudos [?]: 228 [0], given: 16

Intern
Intern
avatar
Joined: 06 Aug 2007
Posts: 31

Kudos [?]: 43 [0], given: 19

Location: Montreal
Re: isosceles triangle [#permalink]

Show Tags

New post 04 Jun 2009, 12:03
bhatiasanju2002 and amolsk11 THANK YOU very much!
I just had one of those blackouts, thank you for explaining it!

Kudos [?]: 43 [0], given: 19

Director
Director
User avatar
Joined: 03 Jun 2009
Posts: 785

Kudos [?]: 884 [0], given: 56

Location: New Delhi
WE 1: 5.5 yrs in IT
Re: isosceles triangle [#permalink]

Show Tags

New post 06 Jun 2009, 01:34

Kudos [?]: 884 [0], given: 56

Intern
Intern
avatar
Joined: 03 Jun 2009
Posts: 49

Kudos [?]: 14 [0], given: 7

Re: isosceles triangle [#permalink]

Show Tags

New post 08 Jun 2009, 11:12
The mentioned Isosceles Right Angled Triangle has angles in the ratio 45deg:45deg:90deg

Any triangle whose angles are in the ratio 45:45:90 shall have the sides in the ratio 1:1:Sqrt(2)

Hence the sides of this traingle are x: x: x sqrt(2) (assuming each side the equal sides to be X each)

=> x+x+x Sqrt(2) = 16+16Sqrt (2)

=> x= 8 Sqrt(2) => hypotenuse = x Sqrt (2) = 8*2 = 16

Kudos [?]: 14 [0], given: 7

Re: isosceles triangle   [#permalink] 08 Jun 2009, 11:12
Display posts from previous: Sort by

isosceles triangle

  post reply Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.