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# isosceles triangle

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Intern
Joined: 06 Aug 2007
Posts: 31
Location: Montreal

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04 Jun 2009, 10:13
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Hello there,

The perimeter of an isosceles triangle is 16 + 16root2
What is the length on the hypotenuse?
Senior Manager
Joined: 16 Jan 2009
Posts: 350
Concentration: Technology, Marketing
GMAT 1: 700 Q50 V34
GPA: 3
WE: Sales (Telecommunications)

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04 Jun 2009, 10:28
for a right isosceles triangle , the perimeter is
2a+a(sqrt)2
where a(sqrt)2 represents the hypot.

are you sure the problem is correct?
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Lahoosaher

Intern
Joined: 27 Apr 2009
Posts: 12

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04 Jun 2009, 10:34
1
KUDOS
As we know the right angle triangle with two equal side (isosceles) has side ratio in 1:1:root2
so according to question , the perimeter is 16+16root2
so the sides are 8root2:8root2:16
so the hypotenuse is 16
Senior Manager
Joined: 16 Jan 2009
Posts: 350
Concentration: Technology, Marketing
GMAT 1: 700 Q50 V34
GPA: 3
WE: Sales (Telecommunications)

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04 Jun 2009, 11:10
and I blame IPL for my low GmatPrep score!!!
Thanks bhatiasanju2002.
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Lahoosaher

Intern
Joined: 06 Aug 2007
Posts: 31
Location: Montreal

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04 Jun 2009, 12:03
bhatiasanju2002 and amolsk11 THANK YOU very much!
I just had one of those blackouts, thank you for explaining it!
Director
Joined: 03 Jun 2009
Posts: 774
Location: New Delhi
WE 1: 5.5 yrs in IT

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06 Jun 2009, 01:34
Intern
Joined: 03 Jun 2009
Posts: 49

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08 Jun 2009, 11:12
The mentioned Isosceles Right Angled Triangle has angles in the ratio 45deg:45deg:90deg

Any triangle whose angles are in the ratio 45:45:90 shall have the sides in the ratio 1:1:Sqrt(2)

Hence the sides of this traingle are x: x: x sqrt(2) (assuming each side the equal sides to be X each)

=> x+x+x Sqrt(2) = 16+16Sqrt (2)

=> x= 8 Sqrt(2) => hypotenuse = x Sqrt (2) = 8*2 = 16
Re: isosceles triangle   [#permalink] 08 Jun 2009, 11:12
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# isosceles triangle

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