Life expectancy for both males and females regularly increases as medi

Question

Life expectancy for both males and females regularly increases as medical science improves. The graph below models the life expectancy trends for both men and women from 1965 to the present. Select the best answer to fill in the blanks in each of the statements below based on the data shown in the graph.

1. The percent difference in life expectancy for males born in 1995 as compared to those born in 1990 is approximately the difference in life expectancy for females born in 1995 as compared to those born in 1990.

2. The number of years by which the average female born in 2010 can expect to outlive the average male born the same year is closest to percent of the number of years by which the average female born in 1975 can expect to outlive the average male born the same year.]

Show Spoiler

Attachment:

12.jpg [ 89.17 KiB | Viewed 4550 times ]

Submit Answer

Start the Timer above, select the dropdowns, and click "Submit" to add this question to your Error log.

Show Answer

Official Answer

Dropdown 1: 10 times Dropdown 2: 70

Archit3110 · Answer

I. The percent difference in life expectancy for males born in 1995 as compared to those born in 1990 is approximately __________ the difference in life expectancy for females born in 1995 as compared to those born in 1990.

A. equal to
B. 5 times
C. 10 times

A. equal to
B. 5 times
C. 10 times

males born in 1995 72.5
males born in 1990 71.8
% ∆ : .974

females born in 1995 78.9
fe males born in 1990 78.8
% ∆ : .126
~ 5 times option B

II. The number of years by which the average female born in 2010 can expect to outlive the average male born the same year is closest to _________ percent of the number of years by which the average female born in 1975 can expect to outlive the average male born the same year.

A. 50
B. 60
C. 70

A. 50
B. 60
C. 70

∆ in age outlive of females 2010 to that of males : 81.8 - 76.2 = 5.6
∆ in age outlive of females 1975 to that of males : 76.6 -68.8 =7.8
5.6/7.8 = ~70
option C

pintukr · Answer

QUESTION 1

I. The percent difference in life expectancy for males born in 1995 as compared to those born in 1990 is approximately __________ the difference in life expectancy for females born in 1995 as compared to those born in 1990.

A. equal to
B. 5 times
C. 10 times

A. equal to
B. 5 times
C. 10 times

Using Life Expectancy (LE) figures from the Line Chart,

For males, 
LE (in 1995) = 72.5
LE (in 1990) = 71.8
% difference = (72.5-71.8)/ 71.8 = 0.7/71.8 = 1% (approx)

For females, 
LE (in 1995) = 78.9
LE (in 1990) = 78.8
% difference = (78.9-78.8)/ 78.8 = 0.1/78.8 = 0.12% = 0.1%(approx)

Hence, Option C --> 10 times (ie, 1/0.1) is the CORRECT answer
Option C

QUESTION 2

II. The number of years by which the average female born in 2010 can expect to outlive the average male born the same year is closest to _________ percent of the number of years by which the average female born in 1975 can expect to outlive the average male born the same year.

A. 50
B. 60
C. 70

A. 50
B. 60
C. 70

For year 2010,

LE (for an average female) = 81.8 years
LE (for an average male) = 76.2 years
Difference (outlive) = 5.6 years

For year 2010,

LE (for an average female) = 76.6 years
LE (for an average male) = 68.8 years
Difference (outlive) = 7.8 years

Thus, 5.6/7.8 = 28/39 = 0.72 = 72 % (ie, closest to 70%)

Hence, Option C --> 72% is the CORRECT answer
Option C

$!vakumar.m · Answer

I. The percent difference in life expectancy for males born in 1995 as compared to those born in 1990 is approximately __________ the difference in life expectancy for females born in 1995 as compared to those born in 1990.

A. equal to
B. 5 times
C. 10 times

Life expectancy for males born in 1995 = 72.5 years
Life expectancy for males born in 1990 = 71.8 years
Percent difference =  \frac{(72.5 - 71.8)}{71.8} * 100  =  \frac{0.7}{71.8} * 100  = 0.97493

life expectancy for females born in 1995 = 78.9
life expectancy for females born in 1990 = 78.8
Percent difference =  \frac{(78.9 - 78.8)}{78.8} * 100  =  \frac{0.1}{78.8} * 100  = 0.1269

therefore, 0.97493/0.1269 = 7.68 (approx) and this is closer to 10 times.

A. equal to
B. 5 times  
  C. 10 times

II. The number of years by which the average female born in 2010 can expect to outlive the average male born the same year is closest to _________ percent of the number of years by which the average female born in 1975 can expect to outlive the average male born the same year.

A. 50
B. 60
C. 70

the average female born in 2010 = 81.8 years
the average male born in 2010 = 76.2 years
Difference is 5.6 years

the average female born in 1975 = 76.6 years 
the average male born in 1975 = 68.8 years
Difference is 7.8 years

therefore, the required percent is = 5.6/7.8 * 100 = 71.79 % = 70% approx.

A. 50
B. 60  
  C. 70

TenthCentury · Answer

I. C (10times) 
% difference in life expectancy for males born in 1995 as compared to those born in 1990 = (72.5 - 71.8)/(71.8) = 0.009
% difference in life expectancy for males born in 1995 as compared to those born in 1990 = (78.9 - 78.8)/(78.8) = 0.001
Ratio = 0.009 / 0.001 = 9 = 10(Approx)

II. C (70) 
number of years by which the average female born in 2010 can expect to outlive the average male born= 81.8 - 76.2 = 5.6
number of years by which the average female born in 1975 can expect to outlive the average male born the same year = 76.6 - 68.8 = 7.8
% = (5.6 / 7.8)*100% = 71.79%= 70%(approx)

RahulJain293 · Answer

I. The percent difference in life expectancy for males born in 1995 as compared to those born in 1990 is approximately __________ the difference in life expectancy for females born in 1995 as compared to those born in 1990.

A. equal to
B. 5 times
C. 10 times

A. equal to
B. 5 times
C. 10 times

IMO (C) 10 times

Males born in 95' - 72.5
Males born in 90' - 71.8
Difference - (72.5-71.8) = 0.7
% difference - (0.7/71.8)*100 =  0.97 (approx. 1%)

Females born in 95' - 78.9
Females born in 90' - 78.8
Difference - (78.9-78.8) = 0.1
% difference - (0.1/78.8)*100 =  0.12 %

Hence 0.1% is  10 times  1%

II. The number of years by which the average female born in 2010 can expect to outlive the average male born the same year is closest to _________ percent of the number of years by which the average female born in 1975 can expect to outlive the average male born the same year.

A. 50
B. 60
C. 70

A. 50
B. 60
C. 70

IMO (C) 70

Females born in 10' - 81.8
Males born in 10' - 76.2
Hence, females outlived males in 2010 by  5.6 years

Females born in 75' - 76.6
Males born in 75' - 68.8
Hence, females outlived males in 1975 by  7.8 years

We need to find 'Value of 2010' is 'what percent of' 'value of 1975'
Hence, (5.6/7.8)*100 =  71.7% which is approx 70%

Catman · Answer

I.The percent difference in life expectancy for males born in 1995 as compared to those born in 1990 is approximately __________ the difference in life expectancy for females born in 1995 as compared to those born in 1990.
 Choice C.   
Life expectancy of males born in 1995= 72.5
Life expectancy of males born in 1990= 71.8

Percentage Difference = (72.5-71.8)/71.8*100 = 0.974%

Life expectancy of females born in 1995= 78.9
Life expectancy of females born in 1990= 78.8

Percentage Difference = (78.9-78.8)/78.8*100
=0.126%
Using approximation Required Ratio is 10 times.

II.The number of years by which the average female born in 2010 can expect to outlive the average male born the same year is closest to _________ percent of the number of years by which the average female born in 1975 can expect to outlive the average male born the same year.
 Choice C.   
The number of years by which the average female born in 2010 can expect to outlive the average male born the same year is (81.8-76.2) =5.6
The average female born in 1975 can expect to outlive the average male born the same year is (76.6-68.8)= 7.8

Required Percentage= (5.6/7.8)*100 is approximately 70%.

RheaBhatia0302 · Answer

Life expectancy for males in 1995: 72.5
Life expectancy for males in 1990: 71.8
Percentage difference = (0.7/71.8) * 100 = 0.97

Life expectancy for females in 1995: 78.9
Life expectancy for females in 1990: 78.8
Percentage difference = (0.1/78.8) * 100 = 0.12

0.12 and 0.97 are approximately the same

Therefore the answer is  A. equal to

rn1112 · Answer

I. The percent difference in life expectancy for males born in 1995 as compared to those born in 1990 is approximately __________ the difference in life expectancy for females born in 1995 as compared to those born in 1990.

A. equal to
B. 5 times
C. 10 times

A. equal to
B. 5 times
C. 10 times

1990 males -- 71.8
1995 males -- 72.5
 Difference = 0.7
Difference (in %) = 0.7 / 71.8 = 7/718 = 1%.............(1)

Similarly, 1990 females -- 78.8
 1995 females -- 78.9
 Difference = 0.1
Difference (in %) = 0.1 / 78.8 = 1/788 = 0.12 %............(2)

(1) is approximately 10 times of (2)

Option C -- 10 times

II. The number of years by which the average female born in 2010 can expect to outlive the average male born the same year is closest to _________ percent of the number of years by which the average female born in 1975 can expect to outlive the average male born the same year. 
 
A. 50
B. 60
C. 70

In 2010 , Female outlives Male by = 81.8 - 76.2 = 5.6 years...........(1)
In 1975 , Female outlives Male by = 76.6 - 68.8 = 7.8 years...........(2)

(5.6 years / 7.6 years ) x 100 = 71.79%

Closest to 70%

Option C -- 70 percent

Oppenheimer1945 · Answer

I) 
Males:
 LE_1995=72.5
LE=_1990=71.8 
% diff_male= 0.7/71.8*100=0.97%

Females:
  LE_1995=78.9
LE_1990=78.8  
 diff= 0.1

Ans= 9.7/0.1=9.7  
 
C)

II)
In 2010:
No of years by which Females outlive male=  81.8-76.2=5.6 yrs
  
The number of years by which the average female born in 1975 can expect to outlive the average male born the same year=76.6-68.8=7.8

5.6 is what % of 7.8
 = 5.6/7.8*100=71%  
C)

Sajjad1994 · Answer

Official Explanation

The answer to the first question is C. Life expectancy for females born in 1995 is about 0.1 percent greater than for females born in 1990; life expectancy for males born in 1995 is about 1 percent greater than for males born in 1990, so the increase is about ten times as great.

The answer to the second question is C. The average female born in 1975 can expect to outlive the average male born the same year by 7.8

Answer: C and C

Sajjad1994 · Answer

OA to this question is posted, it is C for both of the questions.

Competition mode is off now.

Almost everyone did a good job.

Cheers.

Pranavsawant · Answer

The percent difference in life expectancy for males born in 1995 as compared to those born in 1990 is approximately x times the difference in life expectancy for females born in 1995 as compared to those born in 1990.

They mention %diff for males but only diff for females. The first part has a percent difference but in the second part, they only state "the difference" and not percentage difference. Either you misworded the question or the OE is incorrect. If it's percentage difference in both, it needs to be said clearly.

The statement " The percent difference in life expectancy for males born in 1995 as compared to those born in 1990 is approximately 10 times the difference in life expectancy for females born in 1995 as compared to those born in 1990." is incorrect.

Life expectancy for both males and females regularly increases as medi

Prep Toolkit

Top 5 GMAT Debrief Videos

615 to 715 in 15 Days (Ria's Strategies)

More than Quant/Verbal Abilities: Speed vs. Accuracy

745 with Only Self-Prep and GMAT Club

From 555 to 765: 210-point Improvement

Perfect 805 Score Debrief by Julia

My Rewards

GMAT Graphs and Tables (G&T) Questions

Life expectancy for both males and females regularly increases as medi

Prep Toolkit

615 to 715 in 15 Days (Ria's Strategies)

More than Quant/Verbal Abilities: Speed vs. Accuracy

745 with Only Self-Prep and GMAT Club

From 555 to 765: 210-point Improvement

Perfect 805 Score Debrief by Julia

My Rewards