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List M consists of 50 decimals, each of which has a value between
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10 May 2018, 11:15
Question Stats:
32% (02:43) correct 68% (02:55) wrong based on 218 sessions
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List M consists of 50 decimals, each of which has a value between 1 and 10 and has two nonzero digits after the decimal place (e.g. 5.68 could be a number in List M). The sum of the 50 decimals is S. The truncated sum of the 50 decimals, T, is defined as follows. Each decimal in List M is rounded down to the nearest integer (e.g. 5.68 would be rounded down to 5); T is the sum of the resulting integers. If S  T is x percent of T, which of the following is a possible value of x? I. 2% II. 34% III. 99% (A) I only (B) II only (C) I and II only (D) II and III only (E) I, II, and III
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Intern
Joined: 20 Jan 2018
Posts: 19
Location: India
GMAT 1: 620 Q50 V24 GMAT 2: 710 Q51 V34
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Re: List M consists of 50 decimals, each of which has a value between
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10 May 2018, 11:42
souvik101990 wrote: List M consists of 50 decimals, each of which has a value between 1 and 10 and has two nonzero digits after the decimal place (e.g. 5.68 could be a number in List M). The sum of the 50 decimals is S. The truncated sum of the 50 decimals, T, is defined as follows. Each decimal in List M is rounded down to the nearest integer (e.g. 5.68 would be rounded down to 5); T is the sum of the resulting integers. If S  T is x percent of T, which of the following is a possible value of x? I. 2% II. 34% III. 99% (A) I only (B) II only (C) I and II only (D) II and III only (E) I, II, and III C according to me, can be checked by taking values for eg (reducing the cardinal no of set M): case 1: M={1.96,1.97,1.98,1.99} st/t =3.9/4 = 97.5 approx(taking only 4 maximum values) so the % cannot be 99 in any case since 50 elements are there) case2: M={5.12,6.02,7.03,8.04} st/t is definetly <2%, so, 2 can be a possible value. so these are the two extremes and any value b/w these % can be a ratio.



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Re: List M consists of 50 decimals, each of which has a value between
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10 May 2018, 11:47
souvik101990 wrote: List M consists of 50 decimals, each of which has a value between 1 and 10 and has two nonzero digits after the decimal place (e.g. 5.68 could be a number in List M). The sum of the 50 decimals is S. The truncated sum of the 50 decimals, T, is defined as follows. Each decimal in List M is rounded down to the nearest integer (e.g. 5.68 would be rounded down to 5); T is the sum of the resulting integers. If S  T is x percent of T, which of the following is a possible value of x? I. 2% II. 34% III. 99% (A) I only (B) II only (C) I and II only (D) II and III only (E) I, II, and III Question mention possible values: So let find the range of \(\frac{(S  T )}{T}*100\) Maximum percent will be when ST will be max and T will be min since S is in the form abc.yz and T will be x(rounded down) List M , term will be in form a+.bc when rounded down it will be a subtracting both=.bc Therefore ,ST=.YZ max value ST=.99*50 when first term= 1.99 and rounded down value=1 T=1*50 \(((ST)/T)*100=99\) Min value when first term =9.11 and rounded value =9 ST=.11*50 T=9*50 \(((ST)/T)*100=1.22\) So all three value will satisfy option E



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Joined: 02 May 2018
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Re: List M consists of 50 decimals, each of which has a value between
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10 May 2018, 14:14
IMO Answer is E.
Here is why:
Given is the expression (ST)/T = ((S/T)  1)
Where S  Sum of 50 decimals T  Sum of the 50 truncated decimals
Let’s test each answer choice:
i) 2%
((S/T)1) = 2/100
S/T = (2/100)+1 = 102/100
Simplified to S/T = 51/50
Certainly a possibility if each decimal in S is 1.02, added 50 times & hence each decimal in T is 1, added 50 times.
So i) is possible.
ii) 34%
((S/T)1) = 34/100
S/T = (34/100) + 1 = 134/100
Simplified to S/T = 67/50
Certainly possible if each decimal in S is 1.34, added 50 times & hence each decimal in T is 1, added 50 times.
So ii) is possible
iii) 99%
((S/T)1) = 99/100
S/T = (99/100) + 1 = 199/100
Simplified to S/T = 99.5/50
Certainly possible if each decimal in S is 1.99, added 50 times & hence each decimal in T is 1, added 50 times.
So iii) is possible.
Answer is choice E.
I may have gone horribly stupid wrong here, since it’s past 2 am & I am half sleepy, with slightly drunk from my birthday party. Thanks if you wished me.
Gump.
Sent from my iPhone using GMAT Club Forum



Intern
Joined: 13 Nov 2017
Posts: 3

Re: List M consists of 50 decimals, each of which has a value between
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12 May 2018, 11:10
gump2020 wrote: IMO Answer is E.
Here is why:
Given is the expression (ST)/T = ((S/T)  1)
Where S  Sum of 50 decimals T  Sum of the 50 truncated decimals
Let’s test each answer choice:
i) 2%
((S/T)1) = 2/100
S/T = (2/100)+1 = 102/100
Simplified to S/T = 51/50
Certainly a possibility if each decimal in S is 1.02, added 50 times & hence each decimal in T is 1, added 50 times.
So i) is possible.
ii) 34%
((S/T)1) = 34/100
S/T = (34/100) + 1 = 134/100
Simplified to S/T = 67/50
Certainly possible if each decimal in S is 1.34, added 50 times & hence each decimal in T is 1, added 50 times.
So ii) is possible
iii) 99%
((S/T)1) = 99/100
S/T = (99/100) + 1 = 199/100
Simplified to S/T = 99.5/50
Certainly possible if each decimal in S is 1.99, added 50 times & hence each decimal in T is 1, added 50 times.
So iii) is possible.
Answer is choice E.
I may have gone horribly stupid wrong here, since it’s past 2 am & I am half sleepy, with slightly drunk from my birthday party. Thanks if you wished me.
Gump.
Sent from my iPhone using GMAT Club Forum Just one thing in the first part of your explanation 1.02 can be possible right? given that the two decimal digits need to be non zero?



Director
Joined: 02 Oct 2017
Posts: 733

Re: List M consists of 50 decimals, each of which has a value between
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26 May 2018, 22:11
gump2020 wrote: IMO Answer is E.
Here is why:
Given is the expression (ST)/T = ((S/T)  1)
Where S  Sum of 50 decimals T  Sum of the 50 truncated decimals
Let’s test each answer choice:
i) 2%
((S/T)1) = 2/100
S/T = (2/100)+1 = 102/100
Simplified to S/T = 51/50
Certainly a possibility if each decimal in S is 1.02, added 50 times & hence each decimal in T is 1, added 50 times.
So i) is possible.
ii) 34%
((S/T)1) = 34/100
S/T = (34/100) + 1 = 134/100
Simplified to S/T = 67/50
Certainly possible if each decimal in S is 1.34, added 50 times & hence each decimal in T is 1, added 50 times.
So ii) is possible
iii) 99%
((S/T)1) = 99/100
S/T = (99/100) + 1 = 199/100
Simplified to S/T = 99.5/50
Certainly possible if each decimal in S is 1.99, added 50 times & hence each decimal in T is 1, added 50 times.
So iii) is possible.
Answer is choice E.
I may have gone horribly stupid wrong here, since it’s past 2 am & I am half sleepy, with slightly drunk from my birthday party. Thanks if you wished me.
Gump.
Sent from my iPhone using GMAT Club Forum Explanation of I) 2% is not correct as we can't have 1.02 as it is mentioned in question that we have two non zero decimal digits. Rest all is fine. I would love to go with approach kunalcvrce has .it covers all aspects in single way Posted from my mobile device
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CEO
Joined: 12 Sep 2015
Posts: 3511
Location: Canada

Re: List M consists of 50 decimals, each of which has a value between
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29 Sep 2018, 07:46
souvik101990 wrote: List M consists of 50 decimals, each of which has a value between 1 and 10 and has two nonzero digits after the decimal place (e.g. 5.68 could be a number in List M). The sum of the 50 decimals is S. The truncated sum of the 50 decimals, T, is defined as follows. Each decimal in List M is rounded down to the nearest integer (e.g. 5.68 would be rounded down to 5); T is the sum of the resulting integers. If S  T is x percent of T, which of the following is a possible value of x? I. 2% II. 34% III. 99% (A) I only (B) II only (C) I and II only (D) II and III only (E) I, II, and III Let's examine the EXTREME CASESS  T = x percent of T So, S  T = (x/100)T Divide both sides by to get: (S  T)/T = x/100 Multiply both sides by 100 to get: x = 100(S  T)/T First, we we'll MINIMIZE the value of x by minimizing the value of S  T and maximizing the value of T. This occurs when list M = {9.11, 9.11, 9.11, 9.11, 9.11, 9.11, . . . . .9.11, 9.11} So, S = (50)(9.11) And T = (50)(9) So, S  T = (50)(9.11)  (50)(9) = (50)(9.11  9) = (50)(0.11) Plug these values into the above equation to get x =100(50)(0.11)/(50)(9) = 100(0.11)/9 = 11/9 ≈1.2222... So, the MINIMUM value of x is approximately 1.22%First, we we'll MAXIMIZE the value of x by maximizing the value of S  T and minimizing the value of T. This occurs when list M = {1.99, 1.99, 1.99, 1.99, 1.99, . . . 1.99, 1.99} So, S = (50)(1.99) And T = (50)(1) So, S  T = (50)(1.99)  (50)(1) = (50)(1.99  1) = (50)(0.99) Plug these values into the above equation to get x =100(50)(0.99)/(50)(1) = 100(0.99)/1 = 99 So, the MAXIMUM value of x is 99%Combine the results to get: 1.22% < x ≤ 99%All three values (2%, 34% and 99%) fall within this range of xvalues. Answer: E Cheers, Brent
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Re: List M consists of 50 decimals, each of which has a value between
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