December 15, 2018 December 15, 2018 10:00 PM PST 11:00 PM PST Get the complete Official GMAT Exam Pack collection worth $100 with the 3 Month Pack ($299) December 16, 2018 December 16, 2018 07:00 AM PST 09:00 AM PST Get personalized insights on how to achieve your Target Quant Score.
Author 
Message 
TAGS:

Hide Tags

Current Student
Joined: 19 Mar 2012
Posts: 4394
Location: India
GPA: 3.8
WE: Marketing (NonProfit and Government)

List M consists of 50 decimals, each of which has a value between
[#permalink]
Show Tags
10 May 2018, 10:15
Question Stats:
34% (02:04) correct 66% (02:22) wrong based on 211 sessions
HideShow timer Statistics
List M consists of 50 decimals, each of which has a value between 1 and 10 and has two nonzero digits after the decimal place (e.g. 5.68 could be a number in List M). The sum of the 50 decimals is S. The truncated sum of the 50 decimals, T, is defined as follows. Each decimal in List M is rounded down to the nearest integer (e.g. 5.68 would be rounded down to 5); T is the sum of the resulting integers. If S  T is x percent of T, which of the following is a possible value of x? I. 2% II. 34% III. 99% (A) I only (B) II only (C) I and II only (D) II and III only (E) I, II, and III
Official Answer and Stats are available only to registered users. Register/ Login.
_________________
Have an MBA application Question? ASK ME ANYTHING!
My Stuff: Four Years to 760  MBA Trends for Indian Applicants
My GMAT Resources V30V40: How to do it!  GMATPrep SC  GMATPrep CR  GMATPrep RC  Critical Reasoning Megathread  CR: Numbers and Statistics  CR: Weaken  CR: Strengthen  CR: Assumption  SC: Modifier  SC: Meaning  SC: SV Agreement  RC: Primary Purpose  PS/DS: Numbers and Inequalities  PS/DS: Combinatorics and Coordinates
My MBA Resources Everything about the MBA Application  OverRepresented MBA woes  Fit Vs Rankings  Low GPA: What you can do  Letter of Recommendation: The Guide  Indian B Schools accepting GMAT score  Why MBA?
My Reviews How I got into five schools from zero  Applicant Lab Review Veritas Prep Live Online



Intern
Joined: 20 Jan 2018
Posts: 18

Re: List M consists of 50 decimals, each of which has a value between
[#permalink]
Show Tags
10 May 2018, 10:42
souvik101990 wrote: List M consists of 50 decimals, each of which has a value between 1 and 10 and has two nonzero digits after the decimal place (e.g. 5.68 could be a number in List M). The sum of the 50 decimals is S. The truncated sum of the 50 decimals, T, is defined as follows. Each decimal in List M is rounded down to the nearest integer (e.g. 5.68 would be rounded down to 5); T is the sum of the resulting integers. If S  T is x percent of T, which of the following is a possible value of x? I. 2% II. 34% III. 99% (A) I only (B) II only (C) I and II only (D) II and III only (E) I, II, and III C according to me, can be checked by taking values for eg (reducing the cardinal no of set M): case 1: M={1.96,1.97,1.98,1.99} st/t =3.9/4 = 97.5 approx(taking only 4 maximum values) so the % cannot be 99 in any case since 50 elements are there) case2: M={5.12,6.02,7.03,8.04} st/t is definetly <2%, so, 2 can be a possible value. so these are the two extremes and any value b/w these % can be a ratio.



Manager
Joined: 05 Feb 2016
Posts: 144
Location: India
Concentration: General Management, Marketing
WE: Information Technology (Computer Software)

Re: List M consists of 50 decimals, each of which has a value between
[#permalink]
Show Tags
10 May 2018, 10:47
souvik101990 wrote: List M consists of 50 decimals, each of which has a value between 1 and 10 and has two nonzero digits after the decimal place (e.g. 5.68 could be a number in List M). The sum of the 50 decimals is S. The truncated sum of the 50 decimals, T, is defined as follows. Each decimal in List M is rounded down to the nearest integer (e.g. 5.68 would be rounded down to 5); T is the sum of the resulting integers. If S  T is x percent of T, which of the following is a possible value of x? I. 2% II. 34% III. 99% (A) I only (B) II only (C) I and II only (D) II and III only (E) I, II, and III Question mention possible values: So let find the range of \(\frac{(S  T )}{T}*100\) Maximum percent will be when ST will be max and T will be min since S is in the form abc.yz and T will be x(rounded down) List M , term will be in form a+.bc when rounded down it will be a subtracting both=.bc Therefore ,ST=.YZ max value ST=.99*50 when first term= 1.99 and rounded down value=1 T=1*50 \(((ST)/T)*100=99\) Min value when first term =9.11 and rounded value =9 ST=.11*50 T=9*50 \(((ST)/T)*100=1.22\) So all three value will satisfy option E



Intern
Joined: 02 May 2018
Posts: 3

Re: List M consists of 50 decimals, each of which has a value between
[#permalink]
Show Tags
10 May 2018, 13:14
IMO Answer is E.
Here is why:
Given is the expression (ST)/T = ((S/T)  1)
Where S  Sum of 50 decimals T  Sum of the 50 truncated decimals
Let’s test each answer choice:
i) 2%
((S/T)1) = 2/100
S/T = (2/100)+1 = 102/100
Simplified to S/T = 51/50
Certainly a possibility if each decimal in S is 1.02, added 50 times & hence each decimal in T is 1, added 50 times.
So i) is possible.
ii) 34%
((S/T)1) = 34/100
S/T = (34/100) + 1 = 134/100
Simplified to S/T = 67/50
Certainly possible if each decimal in S is 1.34, added 50 times & hence each decimal in T is 1, added 50 times.
So ii) is possible
iii) 99%
((S/T)1) = 99/100
S/T = (99/100) + 1 = 199/100
Simplified to S/T = 99.5/50
Certainly possible if each decimal in S is 1.99, added 50 times & hence each decimal in T is 1, added 50 times.
So iii) is possible.
Answer is choice E.
I may have gone horribly stupid wrong here, since it’s past 2 am & I am half sleepy, with slightly drunk from my birthday party. Thanks if you wished me.
Gump.
Sent from my iPhone using GMAT Club Forum



Intern
Joined: 13 Nov 2017
Posts: 1

Re: List M consists of 50 decimals, each of which has a value between
[#permalink]
Show Tags
12 May 2018, 10:10
gump2020 wrote: IMO Answer is E.
Here is why:
Given is the expression (ST)/T = ((S/T)  1)
Where S  Sum of 50 decimals T  Sum of the 50 truncated decimals
Let’s test each answer choice:
i) 2%
((S/T)1) = 2/100
S/T = (2/100)+1 = 102/100
Simplified to S/T = 51/50
Certainly a possibility if each decimal in S is 1.02, added 50 times & hence each decimal in T is 1, added 50 times.
So i) is possible.
ii) 34%
((S/T)1) = 34/100
S/T = (34/100) + 1 = 134/100
Simplified to S/T = 67/50
Certainly possible if each decimal in S is 1.34, added 50 times & hence each decimal in T is 1, added 50 times.
So ii) is possible
iii) 99%
((S/T)1) = 99/100
S/T = (99/100) + 1 = 199/100
Simplified to S/T = 99.5/50
Certainly possible if each decimal in S is 1.99, added 50 times & hence each decimal in T is 1, added 50 times.
So iii) is possible.
Answer is choice E.
I may have gone horribly stupid wrong here, since it’s past 2 am & I am half sleepy, with slightly drunk from my birthday party. Thanks if you wished me.
Gump.
Sent from my iPhone using GMAT Club Forum Just one thing in the first part of your explanation 1.02 can be possible right? given that the two decimal digits need to be non zero?



Director
Joined: 02 Oct 2017
Posts: 728

Re: List M consists of 50 decimals, each of which has a value between
[#permalink]
Show Tags
26 May 2018, 21:11
gump2020 wrote: IMO Answer is E.
Here is why:
Given is the expression (ST)/T = ((S/T)  1)
Where S  Sum of 50 decimals T  Sum of the 50 truncated decimals
Let’s test each answer choice:
i) 2%
((S/T)1) = 2/100
S/T = (2/100)+1 = 102/100
Simplified to S/T = 51/50
Certainly a possibility if each decimal in S is 1.02, added 50 times & hence each decimal in T is 1, added 50 times.
So i) is possible.
ii) 34%
((S/T)1) = 34/100
S/T = (34/100) + 1 = 134/100
Simplified to S/T = 67/50
Certainly possible if each decimal in S is 1.34, added 50 times & hence each decimal in T is 1, added 50 times.
So ii) is possible
iii) 99%
((S/T)1) = 99/100
S/T = (99/100) + 1 = 199/100
Simplified to S/T = 99.5/50
Certainly possible if each decimal in S is 1.99, added 50 times & hence each decimal in T is 1, added 50 times.
So iii) is possible.
Answer is choice E.
I may have gone horribly stupid wrong here, since it’s past 2 am & I am half sleepy, with slightly drunk from my birthday party. Thanks if you wished me.
Gump.
Sent from my iPhone using GMAT Club Forum Explanation of I) 2% is not correct as we can't have 1.02 as it is mentioned in question that we have two non zero decimal digits. Rest all is fine. I would love to go with approach kunalcvrce has .it covers all aspects in single way Posted from my mobile device
_________________
Give kudos if you like the post



CEO
Joined: 11 Sep 2015
Posts: 3238
Location: Canada

Re: List M consists of 50 decimals, each of which has a value between
[#permalink]
Show Tags
29 Sep 2018, 06:46
souvik101990 wrote: List M consists of 50 decimals, each of which has a value between 1 and 10 and has two nonzero digits after the decimal place (e.g. 5.68 could be a number in List M). The sum of the 50 decimals is S. The truncated sum of the 50 decimals, T, is defined as follows. Each decimal in List M is rounded down to the nearest integer (e.g. 5.68 would be rounded down to 5); T is the sum of the resulting integers. If S  T is x percent of T, which of the following is a possible value of x? I. 2% II. 34% III. 99% (A) I only (B) II only (C) I and II only (D) II and III only (E) I, II, and III Let's examine the EXTREME CASESS  T = x percent of T So, S  T = (x/100)T Divide both sides by to get: (S  T)/T = x/100 Multiply both sides by 100 to get: x = 100(S  T)/T First, we we'll MINIMIZE the value of x by minimizing the value of S  T and maximizing the value of T. This occurs when list M = {9.11, 9.11, 9.11, 9.11, 9.11, 9.11, . . . . .9.11, 9.11} So, S = (50)(9.11) And T = (50)(9) So, S  T = (50)(9.11)  (50)(9) = (50)(9.11  9) = (50)(0.11) Plug these values into the above equation to get x =100(50)(0.11)/(50)(9) = 100(0.11)/9 = 11/9 ≈1.2222... So, the MINIMUM value of x is approximately 1.22%First, we we'll MAXIMIZE the value of x by maximizing the value of S  T and minimizing the value of T. This occurs when list M = {1.99, 1.99, 1.99, 1.99, 1.99, . . . 1.99, 1.99} So, S = (50)(1.99) And T = (50)(1) So, S  T = (50)(1.99)  (50)(1) = (50)(1.99  1) = (50)(0.99) Plug these values into the above equation to get x =100(50)(0.99)/(50)(1) = 100(0.99)/1 = 99 So, the MAXIMUM value of x is 99%Combine the results to get: 1.22% < x ≤ 99%All three values (2%, 34% and 99%) fall within this range of xvalues. Answer: E Cheers, Brent
_________________
Test confidently with gmatprepnow.com




Re: List M consists of 50 decimals, each of which has a value between &nbs
[#permalink]
29 Sep 2018, 06:46






