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Bunuel
ls quadrilateral RSTV a rectangle?

(1) The measure ∠RST of is 90°.
(2) The measure ∠TVR of is 90°.


DS20463

Statement 1: The measure ∠RST of is 90°.
=> 1 internal angle is 90°.
Clearly Insufficient.

Statement 2: The measure ∠TVR of is 90°.
=> 1 internal angle is 90°.
Clearly Insufficient.


Statement 1 + Statement 2: ∠RST and ∠TVR = 90°
=> could be a square or a rectangle.
Again Insufficient.

Answer E.
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quadrilateral RSTV a rectangle.
For a rectangle, all angles need to be 90 degrees and opposite sides equal.

Statement 1: ∠RST is 90°
NOT SUFFICIENT

Statement 2: ∠TVR is 90°
NOT SUFFICIENT

Let's combine statement 1 & 2::
opposite angles are 90 degrees each hence all four angles are 90 degrees respectively.
But it can be square or rectangle.

NOT SUFFICIENT

Hence E
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Bunuel
ls quadrilateral RSTV a rectangle?

(1) The measure ∠RST of is 90°.
(2) The measure ∠TVR of is 90°.


DS20463

Statement 1: The measure ∠RST of is 90°.
=> 1 internal angle is 90°.
Clearly Insufficient.

Statement 2: The measure ∠TVR of is 90°.
=> 1 internal angle is 90°.
Clearly Insufficient.


Statement 1 + Statement 2: ∠RST and ∠TVR = 90°
=> could be a square or a rectangle.
Again Insufficient.

Answer E.

Square is a kind of rectangle, which has equal sides. So your analysis is wrong

The reason why E is the answer is that we can draw figures with angles different from 90º.
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quadrilateral RSTV a rectangle.
For a rectangle, all angles need to be 90 degrees and opposite sides equal.

Statement 1: ∠RST is 90°
NOT SUFFICIENT

Statement 2: ∠TVR is 90°
NOT SUFFICIENT

Let's combine statement 1 & 2::
opposite angles are 90 degrees each hence all four angles are 90 degrees respectively.
But it can be square or rectangle.

NOT SUFFICIENT

Hence E


But just because it could be a square or rectangle doesnt mean its insufficient. Aren't all squares also considered rectangles?
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Bunuel chetan2u VeritasKarishma GMATBusters

Are we going for E because we are taking 'rectangle' as literally a rectangle i.e 2 pairs of opposite sides equal and parallel ? What other shape can be with two opposite angles 90 each ? If its a square then it is a subset of rectangle, otherwise it is a rectangle.

Confused here.
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Hi

The Quadrilateral with only one pair of opposite angles = 90 deg can be any random quadrilateral.

The other 2 angles can be (90, 90) or (30, 150), or (10, 170).
As long as the sum of other 2 angles = 180, we can have infinitely many possibilities.


altairahmad
Bunuel chetan2u VeritasKarishma GMATBusters

Are we going for E because we are taking 'rectangle' as literally a rectangle i.e 2 pairs of opposite sides equal and parallel ? What other shape can be with two opposite angles 90 each ? If its a square then it is a subset of rectangle, otherwise it is a rectangle.

Confused here.
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Hi

The Quadrilateral with only one pair of opposite angles = 90 deg can be any random quadrilateral.

The other 2 angles can be (90, 90) or (30, 150), or (10, 170).
As long as the sum of other 2 angles = 180, we can have infinitely many possibilities.


altairahmad
Bunuel chetan2u VeritasKarishma GMATBusters

Are we going for E because we are taking 'rectangle' as literally a rectangle i.e 2 pairs of opposite sides equal and parallel ? What other shape can be with two opposite angles 90 each ? If its a square then it is a subset of rectangle, otherwise it is a rectangle.

Confused here.

Pardon my ignorance but if we change the other two angles from anything other than 90 deg each, will the originally fixed vertices of 90 deg stay at 90 ? I think that we will not be able to make a quadrilateral where 1 pair of opposite angles is 90 and other 2 are not.
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Yes it is possible.
Please see the figure, you will understand.
Attachment:
WhatsApp Image 2020-06-22 at 5.40.45 PM.jpeg
WhatsApp Image 2020-06-22 at 5.40.45 PM.jpeg [ 11.94 KiB | Viewed 9391 times ]


altairahmad
GMATBusters
Hi

The Quadrilateral with only one pair of opposite angles = 90 deg can be any random quadrilateral.

The other 2 angles can be (90, 90) or (30, 150), or (10, 170).
As long as the sum of other 2 angles = 180, we can have infinitely many possibilities.


altairahmad
Bunuel chetan2u VeritasKarishma GMATBusters

Are we going for E because we are taking 'rectangle' as literally a rectangle i.e 2 pairs of opposite sides equal and parallel ? What other shape can be with two opposite angles 90 each ? If its a square then it is a subset of rectangle, otherwise it is a rectangle.

Confused here.

Pardon my ignorance but if we change the other two angles from anything other than 90 deg each, will the originally fixed vertices of 90 deg stay at 90 ? I think that we will not be able to make a quadrilateral where 1 pair of opposite angles is 90 and other 2 are not.
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