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Bunuel
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Bunuel
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+1 for option D. As a rule, same date a year later is always a day ahead. Add to it the fact that leap year will contribute an extra day. We have a total of 4 days. Add another one day because the date is 20 September. That is 20 Sep 1990 will be a Thursday.
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364 divisible by 7 for integer .. therefore 365 over 7 has rem 1..

1 leap year (366) rem 2 + 2 years (365) = 2 + 1 + 1 = 4 so 4 days later
And 20 is 1 day later = 5 days

Or 365+365+366+1=1097

1097/7 = rem 5
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i solved it this way:

the same day in subsequent years is a day before except leap year that it falls in the same day as the previous year. (always ignore the i day difference between sept 19 and 20)

ordinary year (365 days)
1987 - sept 19 - saturday
1988 - sept 19 - friday (a day before)
1989 - sept 19 thursday ( a day before)
1990- sept 19 wednesday ( a day before)

leap year (assume question is same september 19 1990)
1987 - sept 19 - saturday
1988 - sept 19 - saturday (leap year)
1989 - sept 19 friday ( a day before)
1990- sept 19 thursday ( a day before)

answer D-
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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I think this is a high-quality question and I agree with explanation. Selected Wednesday calculated it for 19th Sept 1990 instead of 20th
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Major shortcut that I learnt from a similar question to this

# of days in a normal year = 365 day - 365/7 = remainder of 1 day
# of days in a leap year = 366 days - 366/7 = remainder of 2 days

19th of September 1987 was Saturday
19th of September 1988 was a leap year >> +2 days - Saturday >> Sunday, Monday
19th of September 1989 was a normal year >> + 1 day - Monday >> Tuesday
19th of September 1990 was a normal year >> + 1 day - Tuesday >> Wedneday
20th of September 1990 is therefore a Thursday
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Has this type of question appeared in GMAT FE recently?
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Bunuel
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lavanya.18
Has this type of question appeared in GMAT FE recently?

The question is relevant to GMAT Focus.
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