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16 Sep 2014, 01:20
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
46% (01:09) correct
54%
(01:26)
wrong
based on 298
sessions
History
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The 19th of September 1987 was Saturday. What day was the 20th of September 1990 if 1988 was a leap-year?
A. Monday
B. Tuesday
C. Wednesday
D. Thursday
E. Friday
A. Monday
B. Tuesday
C. Wednesday
D. Thursday
E. Friday
16 Sep 2014, 01:21
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Official Solution:
The 19th of September 1987 was Saturday. What day was the 20th of September 1990 if 1988 was a leap-year?
A. Monday
B. Tuesday
C. Wednesday
D. Thursday
E. Friday
There are 365 days in an ordinary year and 366 days in a leap-year.
365 divided by 7 (a week period) yields a remainder of 1, thus the same date after an ordinary year would fall on the next day of the week;
366 divided by 7 (a week period) yields a remainder of 2, thus the same date after a leap year would fall two days later in the week;
Thus 3 years, 1988, 1989, and 1990, will accumulate \(2+1+1=4\) days, plus the 1-day difference between the 19th and 20th, which gives a total of a 5-day difference (5-day shift). Thus, the 20th of September 1990 was \(Saturday \ + \ 5 \ days = Thursday\).
Answer: D
The 19th of September 1987 was Saturday. What day was the 20th of September 1990 if 1988 was a leap-year?
A. Monday
B. Tuesday
C. Wednesday
D. Thursday
E. Friday
There are 365 days in an ordinary year and 366 days in a leap-year.
365 divided by 7 (a week period) yields a remainder of 1, thus the same date after an ordinary year would fall on the next day of the week;
366 divided by 7 (a week period) yields a remainder of 2, thus the same date after a leap year would fall two days later in the week;
Thus 3 years, 1988, 1989, and 1990, will accumulate \(2+1+1=4\) days, plus the 1-day difference between the 19th and 20th, which gives a total of a 5-day difference (5-day shift). Thus, the 20th of September 1990 was \(Saturday \ + \ 5 \ days = Thursday\).
Answer: D
General Discussion
14 May 2016, 06:56
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I tried to only apply logic on this one:
In a leap year, the Gregorian calendar adds an extra day to the shortest month of the year - February. So instead of February having 28 days as in an ordinary year, in a leap year, February has 29 days.
Thus if 19th of September 1987 was a Saturday, 19th of September 1988 would be a Monday as you add an extra day in February 1988. Using the same logic/pattern, 19th of September 1989 would be a Tuesday, 19th of September 1990 would be a Wednesday and the 20th of September 1990 would be a Thursday.
Thursday is the correct answer, choice D.
In a leap year, the Gregorian calendar adds an extra day to the shortest month of the year - February. So instead of February having 28 days as in an ordinary year, in a leap year, February has 29 days.
Thus if 19th of September 1987 was a Saturday, 19th of September 1988 would be a Monday as you add an extra day in February 1988. Using the same logic/pattern, 19th of September 1989 would be a Tuesday, 19th of September 1990 would be a Wednesday and the 20th of September 1990 would be a Thursday.
Thursday is the correct answer, choice D.
