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# Marta bought several pencils. If each pencil was either a 23

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Director
Joined: 23 May 2008
Posts: 739
Marta bought several pencils. If each pencil was either a 23  [#permalink]

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25 Sep 2008, 00:00
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Marta bought several pencils. If each pencil was either a 23 cent pencil or a 21 cent pencil, how many 23 cent pencils did Marta buy?

1) Marta bought a total of 6 pencils.

2) The total value of the pencils Marta bought was 130 cents.

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VP
Joined: 30 Jun 2008
Posts: 1004

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25 Sep 2008, 03:07
bigtreezl wrote:
Marta bought several pencils. If each pencil was either a 23 cent pencil or a 21 cent pencil, how many 23 cent pencils did Marta buy?

1) Marta bought a total of 6 pencils.

2) The total value of the pencils Marta bought was 130 cents.

1) says Marta bought 6 pencils. Lets say x pencils cost 23 Cents and the remaining 6-x cost Marta 21 Cents
Let T be the total amount Marta spent overall for 6 pencils

23x + 21(6-x) = T.

Two unknowns and one equation, Not sufficient.

2) Says Marta spent 130 cents overall for several pencils she bought. Say she bought n pencils and x of those we of 23 cents. Then 130 = 23x + 21(n-x). Again 2 unknowns and one equation, Not sufficient.

However, if we combine the two we get n=6 and T=130

so 23x + 21(6-x) = 130.

Now we have only one unknown here. So combining 1 & 2 is sufficient. Also note that we do not need to waste time in calculating x as the question is asking only whether the given statements are sufficient or not.

EDIT : Sheesh !! I keep falling in these C trap questions .....
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"You have to find it. No one else can find it for you." - Bjorn Borg

Intern
Joined: 02 Sep 2008
Posts: 45

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25 Sep 2008, 06:57
I will go with B.

As we have total value, it is \$130.

Now let's make an equaltion.

x is 23 cents pencils.
y is 21 cents pencils.

so, 23 x + 21 y = 130.

now with trial and error if we plug in x and y value then I come up with only one answer.

x = 2 and y = 4.

It is sufficient to answer the question.
Manager
Joined: 28 Aug 2008
Posts: 94

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25 Sep 2008, 09:03
I agree with B

Since there are a finite number of 23 and 21 cent options here it is easy to evaluate them all, the only answer that sums to 130 is 2(23) and 4(21)
Director
Joined: 23 May 2008
Posts: 739

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25 Sep 2008, 11:02
yes, the OA is B

I thought this was a tricky one
Manager
Joined: 11 Jan 2008
Posts: 54

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25 Sep 2008, 11:12
Hi bigtreezl,
Just a quick q, are veritas CAT worth giving a shot?
Are they comparable to what we see on the real GMAT?

Thanks
-Jack
Director
Joined: 23 May 2008
Posts: 739

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25 Sep 2008, 13:57
Hi Jack

I havent actually done any of veritas CATS. A friend took the 10 week course and then let me borrow the books. I've been working through the quant books. My Friend ended up getting a 730 on the real GMAT.
GMAT Instructor
Joined: 04 Jul 2006
Posts: 1253

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26 Sep 2008, 04:47
This is actually a GMATPrep question.
VP
Joined: 05 Jul 2008
Posts: 1328

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26 Sep 2008, 13:32
kevincan wrote:
This is actually a GMATPrep question.

There is a exact stamps Q in OG, If I am not mistaken
Manager
Joined: 18 Jan 2008
Posts: 221
Schools: The School that shall not be named

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26 Sep 2008, 14:05
I found this question to be really anal when i first saw it....
I thought about going through possible combination of 21x+23y, then thought "nah... it cannot be that bad, GMAT cannot be this cruel."

The OA just proved me wrong!
_________________

24 wrote:
Your East Coast bias is worse than ESPN.

Manager
Joined: 11 Mar 2008
Posts: 106

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27 Oct 2008, 12:20
the ans is B

first I selected C - just what They wanted me to do

Why B? Because unfortunately we have one possibility when 23x+21y=130 --- if x=2 and y=4.

Guys, what is the fastest way to solve/see the possibilities without falling into the GMAT trap?
Senior Manager
Joined: 21 Apr 2008
Posts: 456
Schools: Kellogg, MIT, Michigan, Berkeley, Marshall, Mellon

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11 Nov 2008, 08:40
oh \$\$\$\$\$\$\$\$\$\$! Edited by TIGER
this is a really tricky one!

When I saw it, I though that B would be enough and I'd pick it up... however, I'm not sure if I will be so brave in the real exam...

Cheers

--== Message from GMAT Club Team ==--

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I'm not linked to GMAT questions anymore, so, if you need something, please PM me

I'm already focused on my application package

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Re: veritas prep DS &nbs [#permalink] 11 Nov 2008, 08:40
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