Author 
Message 
TAGS:

Hide Tags

Manager
Joined: 27 Oct 2011
Posts: 181
Location: United States
Concentration: Finance, Strategy
GPA: 3.7
WE: Account Management (Consumer Products)

At an amusement park, tom bought a number of red tokens and [#permalink]
Show Tags
30 Jan 2012, 20:06
3
This post received KUDOS
22
This post was BOOKMARKED
Question Stats:
68% (02:52) correct 32% (02:58) wrong based on 467 sessions
HideShow timer Statistics
At an amusement park, tom bought a number of red tokens and green tokens. Each red token costs $0.09, and each green token costs $0.14. If Tom spent a total of exactly $2.06, how many token in total did Tom buy? A. 16 B. 17 C. 18 D. 19 E. 20 This is a tough one. I am having trouble finding a fast solution for this.
Official Answer and Stats are available only to registered users. Register/ Login.
_________________
DETERMINED TO BREAK 700!!!



VP
Status: Top MBA Admissions Consultant
Joined: 24 Jul 2011
Posts: 1358
GRE 1: 1540 Q800 V740

Re: Amusement Park Tokens [#permalink]
Show Tags
30 Jan 2012, 23:20
3
This post received KUDOS
5
This post was BOOKMARKED
0.09x + 0.14y = 2.06 => 9x + 14y = 206 To solve this remember that x must be even because 14y, when subtracted from 206, will yield an even number (even  even = even). The solution comes out to be x=12, y=7. Therefore the total number of tokens bought = 12+7 = 19 Option (D).
_________________
GyanOne  Top MBA Rankings and MBA Admissions Blog
Top MBA Admissions Consulting  Top MiM Admissions Consulting
Premium MBA Essay ReviewBest MBA Interview PreparationExclusive GMAT coaching
Get a FREE Detailed MBA Profile Evaluation  Call us now +91 98998 31738



Math Expert
Joined: 02 Sep 2009
Posts: 43893

At an amusement park, tom bought a number of red tokens and [#permalink]
Show Tags
31 Jan 2012, 00:33



Senior Manager
Joined: 23 Oct 2010
Posts: 375
Location: Azerbaijan
Concentration: Finance

Re: At an amusement park, tom bought a number of red tokens and [#permalink]
Show Tags
31 Jan 2012, 00:59
I found this question not hard, but time consuming. it took some time to find x=12 y=7
_________________
Happy are those who dream dreams and are ready to pay the price to make them come true
I am still on all gmat forums. msg me if you want to ask me smth



Manager
Joined: 27 Oct 2011
Posts: 181
Location: United States
Concentration: Finance, Strategy
GPA: 3.7
WE: Account Management (Consumer Products)

Re: At an amusement park, tom bought a number of red tokens and [#permalink]
Show Tags
31 Jan 2012, 20:45
Is there any way to solve for it other than trial and error?
_________________
DETERMINED TO BREAK 700!!!



Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 7955
Location: Pune, India

Re: At an amusement park, tom bought a number of red tokens and [#permalink]
Show Tags
01 Feb 2012, 01:40
calreg11 wrote: Is there any way to solve for it other than trial and error? Check out case 2 in this post. It explains you in detail how to deal with such questions. I don't think there are pure algebraic solutions to such problems. http://www.veritasprep.com/blog/2011/06 ... ofthumb/
_________________
Karishma Veritas Prep  GMAT Instructor My Blog
Get started with Veritas Prep GMAT On Demand for $199
Veritas Prep Reviews



Math Expert
Joined: 02 Sep 2009
Posts: 43893

Re: At an amusement park, tom bought a number of red tokens and [#permalink]
Show Tags
01 Feb 2012, 01:55



Manager
Joined: 27 Oct 2011
Posts: 181
Location: United States
Concentration: Finance, Strategy
GPA: 3.7
WE: Account Management (Consumer Products)

Re: At an amusement park, tom bought a number of red tokens and [#permalink]
Show Tags
01 Feb 2012, 19:33
Thanks for the posting.
_________________
DETERMINED TO BREAK 700!!!



Manager
Joined: 08 Oct 2010
Posts: 212
Location: Uzbekistan
Schools: Johnson, Fuqua, Simon, Mendoza
WE 3: 10

Re: At an amusement park, tom bought a number of red tokens and [#permalink]
Show Tags
26 Feb 2012, 23:47
2
This post received KUDOS
Bunuel wrote: calreg11 wrote: Is there any way to solve for it other than trial and error? Trial and error along with some common sense is pretty much the only way you should approach such kind of problems on the GMAT. You won't get some very tough numbers to manipulate with or there will be some shortcut available, based on multiples concept or on the answer choices. So generally you would have to try just couple of values to get the answer. Check the links in my previous post to practice similar problems and you'll see that getting the answer is not that hard for the realistic GMAt question. Hi calreg11, supporting the explanations of Bunuel and karishma above, I can show you shortest way of solving it by some amalgamation of trial and error with the algebraic approach, though, as mentioned by karishma, there is no pure algebraic solution of this problem. Let's start: first, we have to formulate the premise in an algebraic way through expressing red and green tokens by any letters we think convenient to us> assuming, e.g., red tokens as 'r' and green tokens as 'g'; secondly, for the sake of convenience we can take the prices of red and greem tokens and also the total cost in cents, i.e., $0,09 as 9 cents, $0.14 as 14 cents, and $2.06 as 206 cents; then, thirdly, we do formulate it > 9r + 14g = 206; fourth, now we can refer to the point that red tokens and green tokens make up the total number of tokens which is unknown to us and this is why formula can be > r + g = x fifth, we have to apply trial and error approach through replacing x by each answer choice and we do it this way: r + g = 16 r = 16  greplace 'r' in the original formula > 9r + 14g = 206and we get 9(16g) + 14g = 206 > 5g=62 > 62 is not divisible by 5, and hence, we cannot derive the number of g (green tokens), consequently, that of red tokens' also. only 19 can satisfy the condition drawn from the formulae r = x  g and 9(xg) + 14g = 206 Hope, it helps!



Current Student
Joined: 06 Sep 2013
Posts: 1954
Concentration: Finance

Re: At an amusement park, tom bought a number of red tokens and [#permalink]
Show Tags
26 Dec 2013, 14:29
1
This post received KUDOS
1
This post was BOOKMARKED
calreg11 wrote: At an amusement park, tom bought a number of red tokens and green tokens. Each red token costs $0.09, and each green token costs $0.14. If Tom spent a total of exactly $2.06, how many token in total did Tom buy?
a. 16 b. 17 c. 18 d. 19 e. 20
This is a tough one. I am having trouble finding a fast solution for this. What I like to do in this questions is the following We have 9x + 14y = 206 First always try to simplify, in this case we can't Now look for a number that is the same for both and will be close to 206 In this case 9 is our best choice (You can quickly ballpark with 10 but you will realize it is >206) So with 9 for both x and y we get 207 which is one more. Now the fun part starts We need to play with this 9,9 combination to try to get one less, How so? Well, let see we need to be one lower so if we get rid of one 14 and add one 9 we be further down. If we subtract to 14's though we are down 28 and if we add 3 9's we are up 27 That perfect just to match our +1 difference! So in total we have 12+7 = 19 Hence our correct answer is D Hope it helps Cheers! J



Intern
Joined: 03 Mar 2014
Posts: 2
Concentration: Entrepreneurship, General Management
GPA: 3.04

Re: At an amusement park, tom bought a number of red tokens and [#permalink]
Show Tags
26 Apr 2014, 23:01
1
This post received KUDOS
3
This post was BOOKMARKED
I solved it this way:
Starting with the equation 9X+14Y = 206
=> 9(X+Y) + 5Y = 206
5Y = 206  9(X+Y)
we need to find X+Y. The RHS has to be a multiple of 5
Substituting the answers for X+Y abive, only 19 gives a multiple of 5. You don't need to actually multiply all the answers with 9, just look for the units digit of the difference. (it has to be either 5 or 0) When 19 is substituted, we get a units digit of 5 in the difference. So D.



Manager
Joined: 03 Jan 2015
Posts: 68
Concentration: Strategy, Marketing
WE: Research (Pharmaceuticals and Biotech)

Re: At an amusement park, tom bought a number of red tokens and [#permalink]
Show Tags
20 Jan 2015, 08:51
PROBLEM: At an amusement park, tom bought a number of red tokens and green tokens. Each red token costs $0.09, and each green token costs $0.14. If Tom spent a total of exactly $2.06, how many token in total did Tom buy?
A. 16 B. 17 C. 18 D. 19 E. 20
SOLUTION:
0.09R + 0.14G = 2.06 i.e. 9R + 14G = 206  (i) R + G = ?
Plug in answer choices for solving. The challenge is how to narrow down without too much calculation. Here is what I did:
Let X be our answer choice: R + G = X i.e. R = X  G  (ii)
Substitute (ii) in (i) 9 (X  G) + 14G = 206 9X + 5G = 206 5G = 206  9X i.e. Last digit of (206  9X) should be 5 or 0 9*19 (ANSWER D) = 171 So, 5G = 206  191 = 35 i.e. G = 7 and R = 12. Thus it satisfies the equation = (9*12) + (14*7) = 206
ANSWER: D



SVP
Status: The Best Or Nothing
Joined: 27 Dec 2012
Posts: 1839
Location: India
Concentration: General Management, Technology
WE: Information Technology (Computer Software)

Re: At an amusement park, tom bought a number of red tokens and [#permalink]
Show Tags
20 Jan 2015, 19:55
9x + 14y = 206 9x = 2 (103  7y)To make the RHS divisible by 9, we require to make the red colour expression (1037y) divisible by 9 103 = 99+4 (Its 4 offset from 99, the closet divisibility), so we require 7y in such a way that its 4 offset from a number divisible by 9, BUT resultant divisibly by 7 Numbers are 13, 22, 31, 40, 49, 58 Look at 49, its our match. So, y = 7 \(x = \frac{54}{9} = 6\) Total = 13 Answer = D
_________________
Kindly press "+1 Kudos" to appreciate



Director
Joined: 07 Dec 2014
Posts: 907

At an amusement park, tom bought a number of red tokens and [#permalink]
Show Tags
06 Mar 2016, 12:14
we know that tom bought at least one pair of red and green tokens cost of one pair=9+14=23¢ (8 pairs)(23¢)=$1.84; $2.06$1.84=22¢ not divisible by 9 or 14 (7 pairs)(23¢)=$1.61;$2.06$1.61=45¢ 5 red tokens at 9¢@ total tokens=7+5=12 red +7 green=19



EMPOWERgmat Instructor
Status: GMAT Assassin/CoFounder
Affiliations: EMPOWERgmat
Joined: 19 Dec 2014
Posts: 11063
Location: United States (CA)
GRE 1: 340 Q170 V170

Re: At an amusement park, tom bought a number of red tokens and [#permalink]
Show Tags
14 Jan 2018, 11:50
Hi All, If you don't immediately see an 'elegant' approach to solving this problem, then you can still solve it relatively quickly with some 'brute force' and a bit of arithmetic. From the answer choices, you can see that the total number of coins is no more than 20, so there aren't that many potential calculations that you would have to do to find the exact number of each type of coins that 'fit' this situation. In basic terms, we're told that a certain number of .09s + a certain number of .14s total 2.06.... There are some Number Property rules that we can use to save some time: .14 multiplied by an integer will end in an EVEN digit 2.06 ends in an even digit Since (even) + (even) = (even), .09 multiplied by an integer MUST end in an EVEN digit for the sum to equal 2.06 The number of red tokens MUST be EVEN, so that significantly cuts down the number of options to consider.... IF... we have.... 2 red tokens, then the remaining value is $1.88. Can that be evenly divided by .14? Try it... (the answer is NO). 4 red tokens, then the remaining value is $1.70. Can that be evenly divided by .14? Try it... (the answer is NO). 6 red tokens, then the remaining value is $1.52. Can that be evenly divided by .14? Try it... (the answer is NO). 8 red tokens, then the remaining value is $1.34. Can that be evenly divided by .14? Try it... (the answer is NO). 10 red tokens, then the remaining value is $1.16. Can that be evenly divided by .14? Try it... (the answer is NO). 12 red tokens, then the remaining value is $0.98. Can that be evenly divided by .14? Try it... (the answer is YES and the remaining 7 tokens are green). Thus, the total number of tokens is 12 red + 7 green = 19 total tokens Final Answer: GMAT assassins aren't born, they're made, Rich
_________________
760+: Learn What GMAT Assassins Do to Score at the Highest Levels Contact Rich at: Rich.C@empowergmat.com
Rich Cohen
CoFounder & GMAT Assassin
Special Offer: Save $75 + GMAT Club Tests Free
Official GMAT Exam Packs + 70 Pt. Improvement Guarantee www.empowergmat.com/
***********************Select EMPOWERgmat Courses now include ALL 6 Official GMAC CATs!***********************




Re: At an amusement park, tom bought a number of red tokens and
[#permalink]
14 Jan 2018, 11:50






