ExpertsGlobal5
Mary had two boxes filled with balls. The first box had red and white balls in the ratio 1:4; the second box had red and white balls in the ratio 3:2. When the balls in the two boxes were mixed into an empty bigger box, the new box had 40% red balls. If the bigger box had 600 balls in all, how many white balls did the second box have?
A. 120
B. 180
C. 200
D. 240
E. 300
FIRST BOX, the number of Red balls : White balls = 1 : 4
SECOND BOX, the number of Red balls : White balls = 3 : 2
when the two balls are mixed, we get a total of 600 balls. The number of Red Balls = 40% * 600 = 240
The number of Blue Balls = 60% * 600 = 360
Using Alligations and Mixtures, ( RED Balls )
First box ————————— Total ————————- Second box
1/5 ———————————— (2/5) ——-——————— (3/5)
Multiplying by 5 throughout, we get
1 ————————————- 2 ————————————- 3
ratio of
First box : Second Box = 1:1 With a total of 600 Balls, the balls in the first Box and Second Box are 300 balls each respectively.
The number of WHITE BALLS in the Second box = ?
Red : White = 3:2 = 5x so, 5x = 300
x = 60
The number of White Balls = 2x = 2*60 =
120 Balls.
Option A