It is currently 20 Oct 2017, 15:24

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

Math: Circles

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Intern
Intern
avatar
Joined: 20 Feb 2016
Posts: 5

Kudos [?]: [0], given: 10

Re: Math: Circles [#permalink]

Show Tags

New post 19 Jun 2016, 09:10
Very helpful. It helped clear a lot of my concepts on circles.

Kudos [?]: [0], given: 10

Manager
Manager
avatar
Joined: 01 Sep 2016
Posts: 117

Kudos [?]: 8 [0], given: 83

Re: Math: Circles [#permalink]

Show Tags

New post 13 Sep 2016, 13:11
Quite a Refresher :)

Bunuel wrote:
chauhan2011 wrote:
• If you know the length of the minor arc and radius, the inscribed angle is: 90L/nr

Please correct me if i am wrong but i think the formula should be : 180L/nr


If you know the length \(L\) of the minor arc and radius, the inscribed angle is: \(Inscribed \ Angle=\frac{90L}{\pi{r}}\).

The way to derive the above formula:

Length of minor arc is \(L= \frac{Central \ Angle}{360}* Circumference\) --> \(L= \frac{Central \ Angle}{360}* 2\pi{r}\) --> \(L= \frac{Central \ Angle}{180}* 2\pi{r}\) --> \(Central \ Angle=\frac{180L}{\pi{r}}\) (so maybe you've mistaken central angle for inscribed angle?).

The Central Angle Theorem states that the measure of inscribed angle is always half the measure of the central angle: \(Central \ Angle=2*Inscribed \ Angle\).

So, \(2*Inscribed \ Angle=\frac{180L}{\pi{r}}\) --> \(Inscribed \ Angle=\frac{90L}{\pi{r}}\).

Hope it helps.

Kudos [?]: 8 [0], given: 83

Senior Manager
Senior Manager
avatar
G
Joined: 09 Feb 2015
Posts: 370

Kudos [?]: 3 [0], given: 196

Location: India
Concentration: Social Entrepreneurship, General Management
GMAT 1: 690 Q49 V34
GMAT 2: 720 Q49 V39
GPA: 2.8
Premium Member Reviews Badge CAT Tests
Re: Math: Circles [#permalink]

Show Tags

New post 17 Aug 2017, 13:36
Bunuel
I have a doubt here . Consider the last figure! If the lines OA and OB are drawn, what will be the resulting Angle OAP and OBP ?

Kudos [?]: 3 [0], given: 196

Re: Math: Circles   [#permalink] 17 Aug 2017, 13:36

Go to page   Previous    1   2   3   [ 43 posts ] 

Display posts from previous: Sort by

Math: Circles

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.