prasannar wrote:

Micheal and Adam can do together a piece of work in 20 days. After they have worked together for 12 days Micheal stops and Adam completes the remaining work in 10 days. In how many days Micheal complete the work separately.

A. 80 days

B. 100 days

C. 120 days

D. 110 days

E. 90 days

Let the total work be 60 ( LCM of 20,12 & 10 )

Efficiency of Micheal and Adam is \(\frac{60}{20} = 3\)

**Quote:**

After they have worked together for 12 days.....

Unit of work completed is 12*3 => 36 units

Units of work left is 60 - 36 => 24 units

**Quote:**

Adam completes the remaining work in 10 days

So, Adam completes 24 units in 10 days..

Efficiency of Adam = 24/10 => \(\frac{12}{5}\) => \(2.4\)

Efficiency of Micheal and Adam is = 3

Efficiency of Adam is = 2.40

So, Efficiency of Micheal is = 0.60

Thus the time required for Micheal to complete the work is = \(\frac{60}{0.60}\) => 100

Hence correct answer is (B) 100

_________________

Thanks and Regards

Abhishek....

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