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Archit143
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26 Dec 2012, 12:56
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I m stuck with few concepts
1. a^2 = b^2
>>>>Is a or b + or - ve
2. a = b^2
Either a = +b or a = -b
Am i right or wrong
3. a^2 = b ^4
>>>.Which one is +or - ve
I have gone through various sources but i am getting confused over and again
Bunuel can u pls help...................
1. a^2 = b^2
>>>>Is a or b + or - ve
2. a = b^2
Either a = +b or a = -b
Am i right or wrong
3. a^2 = b ^4
>>>.Which one is +or - ve
I have gone through various sources but i am getting confused over and again
Bunuel can u pls help...................
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26 Dec 2012, 23:46
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Am not Bunuel but I can try 
Do both a and b can be positive or negative or 0
a= +b^2 or -b^2
Hope it helps!
Archit143
This means that a = +b or -b
Do both a and b can be positive or negative or 0
Archit143
In this b can be + or - but a will be + or 0 for sure as b^2 cannot be negative in any case
Archit143
Here both a and b can be positive negative or 0 as
a= +b^2 or -b^2
Hope it helps!
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26 Dec 2012, 23:52
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Archit143
1. When \(a^2 = b^2\) and you want to take square root then the answer is
\(|a|=|b|\) Now when you open the MOD the answer becomes \(a = +- b\)
2. You are wrong. Apply the above rule and you would \(\sqrt{a}= b\)
b = positive because square root of value is always positive.
3. a^2 = b ^4.. Again apply the rule of 1. You will get \(|a|=|b^2|\)
Since \(b^2\) is always positive => a is always positive. Thus \(a = b^2\)
