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# On a certain road, 10 percent of the motorists exceed the

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Manager
Joined: 07 Jul 2003
Posts: 56

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On a certain road, 10 percent of the motorists exceed the [#permalink]

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18 Feb 2004, 11:59
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

On a certain road, 10 percent of the motorists exceed the posted speed limit and receive speeding tickets, but 20 percent of the motorists who exceed the posted speed limit do not receive speeding tickets. What percent of the motorists on that road exceed the posted speed limit ?

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SVP
Joined: 30 Oct 2003
Posts: 1788

Kudos [?]: 112 [0], given: 0

Location: NewJersey USA

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18 Feb 2004, 14:11
Hi

geethu u r on the same track again.

Anand.

Total motorists = T
People who exceed speed = E
people who exceed and get ticket = ET
people who exceed and get no ticket = ENT
So E = ET + ENT

From the stem ET = 0.1T
ENT = 0.2E
E = 0.1T+0.2E
0.8E = 0.1T
Hence E = 12.5%

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Senior Manager
Joined: 23 Sep 2003
Posts: 292

Kudos [?]: 4 [0], given: 0

Location: US

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18 Feb 2004, 14:15
12.5%. You need a grid to figure it out fast.

Let x be the % of drivers who exceed the speed limit.
# who exceed speed limit and receive ticket = 0.1
# who do not receive ticket but exceed speed limit = 0.2x
which means that 10% represents 80% of motorists who exceed the speed limit.

0.1 = 0.8x
x = 12.5%

Kudos [?]: 4 [0], given: 0

18 Feb 2004, 14:15
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# On a certain road, 10 percent of the motorists exceed the

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