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On the number line, if r > s, if s is halfway between r and

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On the number line, if r > s, if s is halfway between r and [#permalink]

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On the number line, if r > s, if s is halfway between r and t, and t is halfway between r and u, then which of the following is equal to 1?

(A)\(\frac{r-t}{s-u}\)

(B) \(\frac{r-t}{u-t}\)

(C) \(\frac{s-t}{r-u}\)

(D) \(\frac{u-t}{r-s}\)

(E) \(\frac{u-t}{t-r}\)

Any idea guys how to solve this?
[Reveal] Spoiler: OA

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Re: Number line [#permalink]

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enigma123 wrote:
On the number line, if r > s, if s is halfway between r and t, and t is halfway between r and u, then which of the following is equal to 1?

(A)\(\frac{r-t}{s-u}\)

(B) \(\frac{r-t}{u-t}\)

(C) \(\frac{s-t}{r-u}\)

(D) \(\frac{u-t}{r-s}\)

(E) \(\frac{u-t}{t-r}\)

Any idea guys how to solve this?


Draw the number line and mark s, r, t, and u
s is halfway between r and t: -----------t----s----r---- (since r>s);
t is halfway between r and u: u---------t---------r----;

So, you can see that E must be correct, since u-t=r-t.

Or you can assume u=0, t=2, and r=4 (s=3) then \(\frac{u-t}{t-r}=\frac{-2}{-2}=1\).

Answer: E.
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On the number line, if r > s, if s is halfway between r and [#permalink]

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New post 18 Oct 2016, 08:40
enigma123 wrote:
On the number line, if r > s, if s is halfway between r and t, and t is halfway between r and u, then which of the following is equal to 1?

(A)\(\frac{r-t}{s-u}\)

(B) \(\frac{r-t}{u-t}\)

(C) \(\frac{s-t}{r-u}\)

(D) \(\frac{u-t}{r-s}\)

(E) \(\frac{u-t}{t-r}\)

Any idea guys how to solve this?



Quote:
r > s, if s is halfway between r and t, and t is halfway between r and u


r > s > t > x >u

Plug in some numbers...

r > s > t > x >u = 2 >4 > 6 > 8 >10

Now, check using the options , only (E) will satisfy the condition...

Hence our answer will be (E)
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On the number line, if r > s, if s is halfway between r and   [#permalink] 18 Oct 2016, 08:40
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