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# On the number line, if r > s, if s is halfway between r and

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Senior Manager
Status: Finally Done. Admitted in Kellogg for 2015 intake
Joined: 25 Jun 2011
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GMAT 1: 730 Q49 V45
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On the number line, if r > s, if s is halfway between r and  [#permalink]

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06 Mar 2012, 14:19
1
2
00:00

Difficulty:

45% (medium)

Question Stats:

71% (02:12) correct 29% (02:13) wrong based on 134 sessions

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On the number line, if r > s, if s is halfway between r and t, and t is halfway between r and u, then which of the following is equal to 1?

(A)$$\frac{r-t}{s-u}$$

(B) $$\frac{r-t}{u-t}$$

(C) $$\frac{s-t}{r-u}$$

(D) $$\frac{u-t}{r-s}$$

(E) $$\frac{u-t}{t-r}$$

Any idea guys how to solve this?

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E.

MGMAT 1 --> 530
MGMAT 2--> 640
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GMAT ==> 730

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06 Mar 2012, 14:44
2
enigma123 wrote:
On the number line, if r > s, if s is halfway between r and t, and t is halfway between r and u, then which of the following is equal to 1?

(A)$$\frac{r-t}{s-u}$$

(B) $$\frac{r-t}{u-t}$$

(C) $$\frac{s-t}{r-u}$$

(D) $$\frac{u-t}{r-s}$$

(E) $$\frac{u-t}{t-r}$$

Any idea guys how to solve this?

Draw the number line and mark s, r, t, and u
s is halfway between r and t: -----------t----s----r---- (since r>s);
t is halfway between r and u: u---------t---------r----;

So, you can see that E must be correct, since u-t=r-t.

Or you can assume u=0, t=2, and r=4 (s=3) then $$\frac{u-t}{t-r}=\frac{-2}{-2}=1$$.

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On the number line, if r > s, if s is halfway between r and  [#permalink]

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18 Oct 2016, 07:40
enigma123 wrote:
On the number line, if r > s, if s is halfway between r and t, and t is halfway between r and u, then which of the following is equal to 1?

(A)$$\frac{r-t}{s-u}$$

(B) $$\frac{r-t}{u-t}$$

(C) $$\frac{s-t}{r-u}$$

(D) $$\frac{u-t}{r-s}$$

(E) $$\frac{u-t}{t-r}$$

Any idea guys how to solve this?

Quote:
r > s, if s is halfway between r and t, and t is halfway between r and u

r > s > t > x >u

Plug in some numbers...

r > s > t > x >u = 2 >4 > 6 > 8 >10

Now, check using the options , only (E) will satisfy the condition...

Hence our answer will be (E)
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Thanks and Regards

Abhishek....

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On the number line, if r > s, if s is halfway between r and &nbs [#permalink] 18 Oct 2016, 07:40
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