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shameekv1989
GMAT 3: 720 Q50 V38
Posts: 820
23 Apr 2020, 16:45
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
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Question Stats:
52% (01:58) correct
48%
(02:17)
wrong
based on 156
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P and Q are positive numbers, is \(\frac{P}{Q} > 1\)
1) When Q is rounded at the units place, the result is 2
2) PQ+1 = Q
1) When Q is rounded at the units place, the result is 2
2) PQ+1 = Q
firas92
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Concentration: General Management
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GMAT 1: 740 Q50 V40
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23 Apr 2020, 17:45
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We know that \(P\) and \(Q\) are non zero so multiply both sides by \(Q\)
Is \(\frac{P}{Q}*Q>1*Q\)?
Is \(P>Q\)?
1) When \(Q\) is rounded at the units place, the result is \(2\)
No info about \(P\)
1 is not sufficient
2) \(PQ+1 = Q\)
\(Q=1+positive\), so \(Q>1\)
Subtract \(PQ\) from both sides
\(Q-PQ=1\) or \(Q(1-P)=1\)
Since \(Q>0\), \((1-P)>0\) or \(P<1\)
So we have \(0<P<1\) and \(Q>1\) which means \(\frac{P}{Q}<1\)
2 is sufficient
Answer is (B)
Posted from my mobile device
Is \(\frac{P}{Q}*Q>1*Q\)?
Is \(P>Q\)?
1) When \(Q\) is rounded at the units place, the result is \(2\)
No info about \(P\)
1 is not sufficient
2) \(PQ+1 = Q\)
\(Q=1+positive\), so \(Q>1\)
Subtract \(PQ\) from both sides
\(Q-PQ=1\) or \(Q(1-P)=1\)
Since \(Q>0\), \((1-P)>0\) or \(P<1\)
So we have \(0<P<1\) and \(Q>1\) which means \(\frac{P}{Q}<1\)
2 is sufficient
Answer is (B)
Posted from my mobile device
20 May 2020, 09:14
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Think simple.
Statement 1:
Clearly Insufficient
Say Q is 1.5 atleast--> we can assume some value for Q, but what about P?
Statement 2:
Simplify the equation-
Q(P-1)+1=0
-->Q(P-1)=-1
-->Q = -1/(P-1)
This tells us that either P or Q is negative. Definitely P/Q is negative.
Thus negative value is definitely less that 1.
Therefore, B is sufficient
Posted from my mobile device
Statement 1:
Clearly Insufficient
Say Q is 1.5 atleast--> we can assume some value for Q, but what about P?
Statement 2:
Simplify the equation-
Q(P-1)+1=0
-->Q(P-1)=-1
-->Q = -1/(P-1)
This tells us that either P or Q is negative. Definitely P/Q is negative.
Thus negative value is definitely less that 1.
Therefore, B is sufficient
Posted from my mobile device
