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Difficulty:
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Question Stats:
71% (02:30) correct
29%
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Henry purchased 3 items during a sale. He received a 20 percent discount off the regular price of the most expensive item and a 10 percent discount off the regular price of each of the other 2 items. Was the total amount of the 3 discounts greater than 15 percent of the sum of the regular prices of the 3 items?
(1) The regular price of the most expensive item was $50, and the regular price of the next most expensive item was $20
(2) The regular price of the least expensive item was $15
(A) Statement 1 alone is sufficient, but statement 2 alone is not.
(B) Statement 2 alone is sufficient, but statement 1 alone is not.
(C) Both statements together are sufficient, but neither alone is sufficient.
(D) Each statement alone is sufficient.
(E) Neither statement is sufficient, even when combined.
Henry discount on items.GIF [ 14.71 KiB | Viewed 67220 times ]
(1) The regular price of the most expensive item was $50, and the regular price of the next most expensive item was $20
(2) The regular price of the least expensive item was $15
(A) Statement 1 alone is sufficient, but statement 2 alone is not.
(B) Statement 2 alone is sufficient, but statement 1 alone is not.
(C) Both statements together are sufficient, but neither alone is sufficient.
(D) Each statement alone is sufficient.
(E) Neither statement is sufficient, even when combined.
Attachment:
Henry discount on items.GIF [ 14.71 KiB | Viewed 67220 times ]
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docabuzar
Let the regular prices be a, b, and c, so that a > b > c.
Basically the questions: is \(0.2a+0.1b+0.1c>0.15(a+b+c)\)? --> is \(a>b+c\)?
(1) The regular price of the most expensive item was $50 and the regular price of the next most expensive item was $20 --> \(a=50\), \(b=20\), \(c\leq{20}\) (as the second most expensive item was $20 then the least expansive item, the third one, must be less than or equal to 20). So the question becomes: is \(50>20+c\) --> is \(c<30\)? As we got that \(c\leq{20}\), hence the above is always true. Sufficient.
(2) The regular price of the least expensive item was $15. Clearly insufficient.
Answer: A.
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docabuzar
The questions asks: is \(0.2a+0.1b+0.1c>0.15(a+b+c)\)? After simplifying we'll get that the question becomes: is \(a>b+c\)?
(1) says \(a=50\) and \(b=20\). Also we concluded that: \(c\leq{20}\). Now, if we substitute the values of a and b we'll get that the question boils down to: is \(50>20+c\)? or is \(c<30\)?
Hope it's clear.
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General Discussion
THe Q asks for the which of discounts will be greater 20%, 10%, 10% on A, B, C resp or 15% on (A+B+C). How can we say its same as 50> 20+C ? Now I m totally lost.
Thanks. Its clear now.
Just how do you know to keep A on one side & B & C on other? This simplied the Ans a lot.
Just how do you know to keep A on one side & B & C on other? This simplied the Ans a lot.
docabuzar
It really doesn't matter how you write it: \(a>b+c\), \(a-b-c>0\), \(a-b>c\), ... You still will get the same result. For me \(a>b+c\) was the most "attractive" form, so I chose this one.
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Bunuel: if the first item is 50, the next 2 are 20. If I take 20% of 50 I get 10 and 10% of 20 I get 2. Total discount is 14 and total price is 90. 14/90>.15. What's am I doing wrong?
bankerboy30
Total discount = $14.
The sum of the regular prices of the 3 items = $90.
15% of $90 = $13.5.
$14 > $13.5.
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I believe this question is a perfect example of an "Easy C" trap. Just by realizing that A&B would be sufficient and make the problem way too easy, we can eliminate C,D and E. This is a simple rule that could improve one's chances on 700+ problems
vishal205
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Fortunately or Unfortunately, the OA is C for this one. I'm staring at the answer on GMATPREP software :/ Attaching screenshot
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Henry Purchased 3 items.docx [823.94 KiB]
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vishal205
The OA for the question discussed above is A, NOT C.
The question you attached is not the one discussed above, it's another one discussed here: https://gmatclub.com/forum/henry-purcha ... 94280.html
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Bunuel
Hi Bunuel could you please elaborate this simplification:
0.2a+0.1b+0.1c>0.15(a+b+c)0.2a+0.1b+0.1c>0.15(a+b+c) ? --> is a>b+ca>b+c?
Sri07
\(0.2a+0.1b+0.1c>0.15(a+b+c)\);
\(0.2a+0.1b+0.1c>0.15a+0.15b+0.15c\);
\(0.05a>0.05b+0.05c\);
\(a>b+c\).
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Bunuel : I somehow got lost in the wording of this question. The Q only says Henry purchased 3 items . No where does it mention that the other 2 items he purchased are the second most expensive item or the least expensive item.
How can we assume from statement one that Henry has indeed purchased 2nd most expensive item> He could have purchased any 2 of the other items right?
How can we assume from statement one that Henry has indeed purchased 2nd most expensive item> He could have purchased any 2 of the other items right?
Niveditha28
I think you misunderstood the question, if I got your doubt right.
So, Henry purchased 3 items in total, not more. Say regular prices of these 3 items were $a, $b, and $c, so that a > b > c. He received a 20 percent discount off the regular price of the most expensive item, so $a item, he bought for $0.8a. For the remaining 2 items, so for the items which cost $b and $c, he got 10 percent discount, so Henry purchased these 2 items for $0.9b and $0.9c.
Does this make sense?
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docabuzar
We can treat this as a MIXTURE PROBLEM.
How can we combine a 20% solution (the higher discount) with a 10% solution (the lower discount) to yield a mixture that is more than 15% (the total discount)?
If we use EQUAL amounts of 20% solution and 10% solution, the resulting solution will be exactly 15%.
Implication:
To yield a solution that is MORE THAN 15%, we must use MORE OF the 20% solution and LESS OF the 10% solution.
In other words:
The price of the most expensive item (the 20% solution) must be greater than the total cost of the two cheaper items (the 10% solution).:
Question stem, rephrased:
Is the price of the most expensive item greater than the total cost of the two cheaper items?
Statement 1: The regular price of the most expensive item was $50, and the regular price of the next most expensive item was $20.
Maximum total cost of the two cheaper items = 20+20 = 40.
Since the price of the most expensive item ($50) is greater than the maximum total cost of the 2 cheaper items ($40), the answer to the rephrased question stem is YES.
SUFFICIENT.
Statement 2: The regular price of the least expensive item was $15.
No way to determine whether the price of the most expensive item is greater than the total cost of the 2 cheaper items.
INSUFFICIENT.
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Basically the question is whether the sum of the prices of the two less expensive items is less than the price of the most expensive item.
Weighted averages is very good here:
2*10%----------15%----------20%
The total percentage will be to the right of 15% if the most expensive item costs more than the other two items together.
Weighted averages is very good here:
2*10%----------15%----------20%
The total percentage will be to the right of 15% if the most expensive item costs more than the other two items together.
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Bunuel
Hi Bunuel. First of all, thanks for the tremendous help that you have been providing to us all.
Coming back to the question, I don't think the answer is A ( it should be C ). Algebraically, what you have said is right. However, if we take specific numerical values, the answer ranges from "Yes" ( for c= 20 ) to "No" ( for c = 10 ). Also, inequality provides us with a range of values. For some, the answer is ">15%" and for some that sanwer is "<15%".
Kindly explain.
DrVanNostrand
If a = 50, b = 20 and c = 20, then \(0.2a+0.1b+0.1c=14\) and \(0.15(a+b+c)=13.5\)
If a = 50, b = 20 and c = 10, then \(0.2a+0.1b+0.1c=13\) and \(0.15(a+b+c)=12\)
Both sets (as well as all other possible sets for the first statement) give an YES answer.
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Henry purchased 3 items during a sale. He received a 20 percent discount off the regular price of the most expensive item and a 10 percent discount off the regular price of each of the other 2 items. Was the total amount of the 3 discounts greater than 15 percent of the sum of the regular prices of the 3 items?
(1) The regular price of the most expensive item was $50, and the regular price of the next most expensive item was $20
(2) The regular price of the least expensive item was $15
(1) The regular price of the most expensive item was $50, and the regular price of the next most expensive item was $20
(2) The regular price of the least expensive item was $15
Attachments
1FC95E65-B977-4642-A180-C4B972CDEA48.jpeg [ 1.13 MiB | Viewed 7149 times ]
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