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Difficulty:
15%
(low)
Question Stats:
78% (01:21) correct
22%
(02:13)
wrong
based on 150
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Not Attempted Yet
On the line above, if AB < BC < CD < DE, which of the following must be true?
(A) AC < CD
(B) AC < CE
(C) AD < CE
(D) AD < DE
(E) BD < DE
Attachment:
2017-07-12_1253.png [ 3.09 KiB | Viewed 4782 times ]
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I tried to solve this question by plugging in nos. but really didn't get anything out of it.
Just my best guess:
Is it B?
AC<CE
That's because: AB<BC and BC<CD and DE
So AB is also less than CD and DE.
So the sum of the smaller two nos. would be less than sum of the bigger two nos.
(I am not sure if this correct).
Waiting for your method Bunuel.
Thanks
Just my best guess:
Is it B?
AC<CE
That's because: AB<BC and BC<CD and DE
So AB is also less than CD and DE.
So the sum of the smaller two nos. would be less than sum of the bigger two nos.
(I am not sure if this correct).
Waiting for your method Bunuel.
Thanks
Luckisnoexcuse
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Bunuel
Given AB<BC<CD<DE
Please note that all the values which AB, BC, CD or DE take will be positive. Lets assume
AB = a
BC=a+x
CD=a+x+y
DE=a+x+y+z
All a,x,y,z are positive
(A) AC < CD => AB+BC<CD => a+a+x<a+x+y (a could be greater than y) Nope
(B) AC < CE => AB+BC<CD+DE => a+a+x<a+x+y+a+x+y+z => 0<y+x+y+z and since x,y,z is positive..this is our answer
(C) AD < CE => AB+BC+CD<CD+DE => AB+BC<DE => a+a+x<a+x+y+z (a could be greater than y+z) Nope
(D) AD < DE => AB+BC+CD < DE => a+a+x+a+x+y<a+x+y+z (2a+x could be larger than z) Nope
(E) BD < DE => BC+CD<DE => a+x+a+x+y<a+x+y+z (a+x could be larger than z) Nope
Hence B
We can also use smart numbers like a=6, x=2, y=3, z=4
try to split the inequalities..
AB<BC
BC<CD
add the above equztions...AC<BD....(1)
BC<CD
CD<DE
adding will give BD<CE....(2)
from 1 and 2 we get AC<CE..
ans B
AB<BC
BC<CD
add the above equztions...AC<BD....(1)
BC<CD
CD<DE
adding will give BD<CE....(2)
from 1 and 2 we get AC<CE..
ans B
tapasgupta
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GMAT 1: 550 Q44 V23
Posts: 115
The addition of 2 smaller quantities will be less than the addition of 2 greater quantities....hence B
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Sent from my MI PAD using GMAT Club Forum mobile app
shoumkrish
Joined: 20 Aug 2015
Last visit: 18 Aug 2023
Posts: 62
Location: India
Schools: ISB '21 (A)
GMAT 1: 710 Q50 V36
GPA: 3
Bunuel
AB < CD
BC < DE
AB + BC < CD + DE
AC < CE
Ans B.
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