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Updated on: Sun Apr 28, 2013 2:05 am
Originally posted by fireinbelly on Sat Apr 27, 2013 11:06 am.
Last edited by Bunuel on Sun Apr 28, 2013 2:05 am, edited 2 times in total.
Last edited by Bunuel on Sun Apr 28, 2013 2:05 am, edited 2 times in total.
Renamed the topic and edited the question.
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
52% (00:58) correct
48%
(00:53)
wrong
based on 176
sessions
History
Date
Time
Result
Not Attempted Yet
Is m^3 > m^2?
(1) m > 0
(2) m < 1
(1) m > 0
(2) m < 1
Pure algebraic questions like this one are no longer part of the GMAT Data Sufficiency syllabus.
For relevant Data Sufficiency questions, please check the Data Sufficiency forum:
Data Sufficiency Forum
Data Sufficiency Forum
Sat Apr 27, 2013 11:15 am
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Is \(m^3 > m^2\)?
\(m^3-m^2>0\) or \(m(m^2-m)>0\)
I)The first part (m)is +ve if m>0
II)The second part (m^2-m) is +ve if \(m^2-m>0\) or if \(m>1\) or \(m<0\)
Put together the intervals I and II and you'll find that the equation is +ve(>0) if \(m>1\)
The question asks: is \(m>1\)?
1. m > 0
Not Sufficient
2. m < 1
Sufficient
B, to answer your question: the answer is C if the question were \(m^3 \geq{} m^2\)
In this case the value m=0 would be a problem, and m<1 would not be sufficient.
For any m<1 but \(\neq{}0\) the equation is negative (so no \(\geq{0}\)), but for m=0 equals 0: \(0\geq{0}\)
Only combining 1 and 2 we would be able to answer in this case
\(m^3-m^2>0\) or \(m(m^2-m)>0\)
I)The first part (m)is +ve if m>0
II)The second part (m^2-m) is +ve if \(m^2-m>0\) or if \(m>1\) or \(m<0\)
Put together the intervals I and II and you'll find that the equation is +ve(>0) if \(m>1\)
The question asks: is \(m>1\)?
1. m > 0
Not Sufficient
2. m < 1
Sufficient
B, to answer your question: the answer is C if the question were \(m^3 \geq{} m^2\)
In this case the value m=0 would be a problem, and m<1 would not be sufficient.
For any m<1 but \(\neq{}0\) the equation is negative (so no \(\geq{0}\)), but for m=0 equals 0: \(0\geq{0}\)
Only combining 1 and 2 we would be able to answer in this case
Sat Apr 27, 2013 11:27 am
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tirbah
Simplify the question first: \(m^3-m^2>0\) or \(m^2(m-1)>0\). Since \(m^2>=0\) for every \(m\),
\(m-1>0\) or \(m>1\).
So, the question is just: \(m>1?\)
(1) insufficient. For \(m=1/2\) the answer is No, and for \(m=2\) the answer is Yes.
(2) sufficient to give the answer No.
The correct answer is B.
Hope this helps.
