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Posts: 16,401
Updated on: 21 May 2026, 10:21
Originally posted by Sajjad1994 on 01 Mar 2022, 07:00.
Last edited by Bunuel on 21 May 2026, 10:21, edited 5 times in total.
Last edited by Bunuel on 21 May 2026, 10:21, edited 5 times in total.
800 score;Moved to new forum
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
72% (03:15) correct
28%
(03:28)
wrong
based on 671
sessions
History
Date
Time
Result
Not Attempted Yet
Source: 800 score
9 runners—Lea, May, Nora, Olga, Pat, Queta, Rhea, Sue, and Tia—are divided into 3 relay teams. The 3 fastest runners are placed on team 1, the 3 slowest runners on team 3, and the remaining 3 runners on team 2.
No two runners run at the same speed. May runs faster than Queta. Queta runs faster than both Olga and Lea. Lea runs faster than both Sue and Nora. Tia runs slower than Olga. Rhea runs slower than Tia. Rhea runs faster than Pat.
Select the runner who could be on team 2 but not on team 3, and select the runner who could be on any team.
|
Team 2 but not team 3 |
Any team |
---------- |
| Lea | ||
| Nora | ||
| Olga | ||
| Rhea | ||
| Sue | ||
| Tia |
Team 2 but not team 3 - Olga.
Any team - Lea.
1. May runs faster than Queta -> M>Q
2. Queta runs faster than both Olga and Lea. Q > O & L
3. Lea runs faster than both Sue and Nora. L > S & N
4. Tia runs slower than Olga. O > T
5. Rhea runs slower than Tia. T > R
6. Rhea runs faster than Pat. R > P.
From above statements, M and Q are two fastest, so they will be in team 1.
From 4,5 and 6, definitely there are 3 persons who are slower than O, so O will not be in team 3.
From above statements it can also be seen that L can be in any team.
Posted from my mobile device
Any team - Lea.
1. May runs faster than Queta -> M>Q
2. Queta runs faster than both Olga and Lea. Q > O & L
3. Lea runs faster than both Sue and Nora. L > S & N
4. Tia runs slower than Olga. O > T
5. Rhea runs slower than Tia. T > R
6. Rhea runs faster than Pat. R > P.
From above statements, M and Q are two fastest, so they will be in team 1.
From 4,5 and 6, definitely there are 3 persons who are slower than O, so O will not be in team 3.
From above statements it can also be seen that L can be in any team.
Posted from my mobile device
Posts: 60
Let the first letter of each of the runners' names be their respective speeds.
Then, from the problem statement we can write the following relations:
1) m>q>o>t>r>p
2) m>q>l>s
3) m>q>l>n
i) From relations 1, 2 and 3, we can clearly see of all runners Olga (with speed o) could be on Team 2 (but never team 3) since there are 3 runners slower than her.
ii) Also from relations 1,2 and 3 we can say that Lea (with speed l) could be on any team (i.e. Team 1, Team 2 or Team 3) depending on her speed relative to others. For example if l > o (Lea is on Team 1); if o > l > at least one among t, r, p (Lea is on Team 2); and if p>l (Lea is on Team 3)
Then, from the problem statement we can write the following relations:
1) m>q>o>t>r>p
2) m>q>l>s
3) m>q>l>n
i) From relations 1, 2 and 3, we can clearly see of all runners Olga (with speed o) could be on Team 2 (but never team 3) since there are 3 runners slower than her.
ii) Also from relations 1,2 and 3 we can say that Lea (with speed l) could be on any team (i.e. Team 1, Team 2 or Team 3) depending on her speed relative to others. For example if l > o (Lea is on Team 1); if o > l > at least one among t, r, p (Lea is on Team 2); and if p>l (Lea is on Team 3)
M>Q
Q>O & L
L> S & N
O>T>R>P
Team 2 but not on Team 3: Olga.
Olga can be faster than Lea or slower than Lea. If Olga is faster than Lea, then Olga will be in the fastest team(Team 1), but if Olga is slower than Lea, then Olga will be in Team 2, but cannot go to Team 3.
If Olga is slower than Lea, then M Q L is the fastest team.
We know that S & N is less than L. So, S & N can be in Team 2 or in Team 3.
It is already established that O>T>R>P, O has to be paired with S & N, otherwise, the slowest 3 members condition will not be satisfied.
Any Team : Lea
If Lea is faster than Olga, then Olga will be in team 1.
If Lea is slower than Olga, then one possible combination is
Team 1 = M Q O
Team 2 = L S N ( Since L>S & N)
Team 3 = T R P ( Since O>T>R>P)
Or another combination is
Team 1 = M Q O
Team 2 = T R P ( Since O>T>R>P)
Team 3 = L S N ( Since L>S & N)
So, we can see that L can be a part of Team 1, Team 2, and Team 3
Q>O & L
L> S & N
O>T>R>P
Team 2 but not on Team 3: Olga.
Olga can be faster than Lea or slower than Lea. If Olga is faster than Lea, then Olga will be in the fastest team(Team 1), but if Olga is slower than Lea, then Olga will be in Team 2, but cannot go to Team 3.
If Olga is slower than Lea, then M Q L is the fastest team.
We know that S & N is less than L. So, S & N can be in Team 2 or in Team 3.
It is already established that O>T>R>P, O has to be paired with S & N, otherwise, the slowest 3 members condition will not be satisfied.
Any Team : Lea
If Lea is faster than Olga, then Olga will be in team 1.
If Lea is slower than Olga, then one possible combination is
Team 1 = M Q O
Team 2 = L S N ( Since L>S & N)
Team 3 = T R P ( Since O>T>R>P)
Or another combination is
Team 1 = M Q O
Team 2 = T R P ( Since O>T>R>P)
Team 3 = L S N ( Since L>S & N)
So, we can see that L can be a part of Team 1, Team 2, and Team 3
Posts: 3
1.Olga(Team 2 but not Team 3)
2.Lea(Any Team)
Posted from my mobile device
2.Lea(Any Team)
Posted from my mobile device
sshwetima
Joined: 02 Aug 2019
Last visit: 09 Apr 2023
Posts: 41
Location: India
Concentration: Operations, Strategy
Schools: ISB '24 (A)
GMAT 1: 680 Q50 V31
WE:Manufacturing and Production (Manufacturing)
[quote="Sajjad1994"]9 runners—Lea, May, Nora, Olga, Pat, Queta, Rhea, Sue, and Tia—are divided into 3 relay teams. The 3 fastest runners are placed on team 1, the 3 slowest runners on team 3, and the remaining 3 runners on team 2.
No two runners run at the same speed. May runs faster than Queta. Queta runs faster than both Olga and Lea. Lea runs faster than both Sue and Nora. Tia runs slower than Olga. Rhea runs slower than Tia. Rhea runs faster than Pat.
Select the runner who could be on team 2 but not on team 3, and select the runner who could be on any team.
Order of runners :
1. M>Q>O>T>R>P>L>S>N - O in Team 1, L in Team 3
2. M>Q>L>S>N>O>T>R>P - O in Team 2, L in Team 1
3. M>Q>O>T>L>S>N>R>P - L in Team 2
In any case O will be in Team 2 or Team but not in Team 3 and L could be in all 3 teams
N, R, S and T can be in both Team 2 and Team 3
No two runners run at the same speed. May runs faster than Queta. Queta runs faster than both Olga and Lea. Lea runs faster than both Sue and Nora. Tia runs slower than Olga. Rhea runs slower than Tia. Rhea runs faster than Pat.
Select the runner who could be on team 2 but not on team 3, and select the runner who could be on any team.
| Team 2 but not team 3 | Any team | |
| Yes | Lea | |
| Nora | ||
| Yes | Olga | |
| Rhea | ||
| Sue | ||
| Tia |
Order of runners :
1. M>Q>O>T>R>P>L>S>N - O in Team 1, L in Team 3
2. M>Q>L>S>N>O>T>R>P - O in Team 2, L in Team 1
3. M>Q>O>T>L>S>N>R>P - L in Team 2
In any case O will be in Team 2 or Team but not in Team 3 and L could be in all 3 teams
N, R, S and T can be in both Team 2 and Team 3
Team 2 but not team 3 ： Olga
Any team： Lea
Better draw a chart to show their relative speed. But the basic shape is as follows:
M > Q > O > T > R > P
M > Q > L > S
M > Q > L > N
So, M and Q must be in the Team 1.
the third member in Team 1 can be either O or L
If O is in team 1, L can be in team 2, but L can also be in team 3.
If L is in team 1, O can only be in team 2 because TRP are slower than O.
Any team： Lea
Better draw a chart to show their relative speed. But the basic shape is as follows:
M > Q > O > T > R > P
M > Q > L > S
M > Q > L > N
So, M and Q must be in the Team 1.
the third member in Team 1 can be either O or L
If O is in team 1, L can be in team 2, but L can also be in team 3.
If L is in team 1, O can only be in team 2 because TRP are slower than O.
hope that you like it
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