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Is that a 700+ question?
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Anki111
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if it was isosceles trapezoid, then we can say we have s1=s2. but can it be D the ?
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True. Only for Isosceles the answer can be D. Otherwise there is no way to know where the perpendicular line would cut the base.
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Anki111
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and for isosceles we know that both the cut parts are equal ? correct?
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the other two sides can have 2 different acute angles. if you assume the sides to be the same then the trapezoid is case specific by assumption and not data given.

Hence it will be E

Anki111
if it was isosceles trapezoid, then we can say we have s1=s2. but can it be D the ?
Exactly
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Nikhil418
Is that a 700+ question?
Hi please tell the level of the question as well if you dont mind
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i dont think it’s 700+

probably 650ish ?
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yeaaa it is 650-700 level
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Anki111
can anyone explain ?
I believe you are assuming its a regular trapezoid, in which case you can use the the height and pythogras but this is not stated in the question

Just that it is a trapezoid shape
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Can some one explain this? Why can’t one side be equal to the Height and the other side we can find with the help of Pythagoras Theorem. So, D should be sufficient

In ΔABC, point D lies on the side AB between vertices A and B. If CD = CB, is AD > BC?

(1) ∠ADC = 110°

(2) ∠ACD = 30°
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For any line to be height, it has to be perpendicular drawn from vertex to opposite side. It’s not said that CD is perpendicular. It’s just a line.

Is the answer C?
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YES ANSWER IS C

CAN you explain
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C

Side opposite to greater angle is greater
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Statement 1: It provides angle ADC. Through that you can conclude that angle CDB is 70 (180-110). As CD equals CB. It’s an isosceles triangle. You cannot conclude anything further.

Statement 2: Angle ACD is 30 and therefore nothing else can be concluded regarding the sides AD and BC from it.

Combining both you can find that angle ACB is 30+40 i.e 70 degree. Therefore Triangle CDB and ABC are similar. Two angles are similar and common base. Therefore AD is not greater than BC.
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Ankyt13
Statement 1: It provides angle ADC. Through that you can conclude that angle CDB is 70 (180-110). As CD equals CB. It’s an isosceles triangle. You cannot conclude anything further. Statement 2: Angle ACD is 30 and therefore nothing else can be concluded regarding the sides AD and BC from it. Combining both you can find that angle ACB is 30+40 i.e 70 degree. Therefore Triangle CDB and ABC are similar. Two angles are similar and common base. Therefore AD is not greater than BC.
"Two angles are similar and common base. Therefore AD is not greater than BC" - Can you explain how can we conclude this?
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am79021
"Two angles are similar and common base. Therefore AD is not greater than BC" - Can you explain how can we conclude this?
The traingles are similar and We know that D is a point in AB so
AD< AB
AD<AC (as AB=AC)
For an Isosceles traingle third side cannot be greater than equal sides. If it were greater then it won’t be isosceles triangle.
Therefore AD < BC (as AC is greater than BC). Hope it helps.
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gmatophobia
DS Question 1 - June 14 If [x] denotes the greatest integer less than or equal to x for any number x, is [a]+=1? (1) ab=2 (2) 0 < a < b < 2 Source: GMAT Club Tests | Difficulty: Hard
A;
stmt 1: a*b=2; 1*2 or root 2*root 2 or 20*0.1 etc
In all the cases above [a]+[b] will not be equal to 1; answer is NO
stmt 2: 0.4, 0.6 and 0.9, 1.9 will give NO & YES respectively. Hence, Insufficient

gmatophobia
[b]PS Question 1 - June 14 A cyclist travels the length of a bike path that is 225 miles long, rounded to the nearest mile. If the trip took him 5 hrs, rounded to the nearest hour, then his average speed must be between: A. 38 and 50 mph B. 40 and 50 mph C. 40 and 51 mph D. 41 and 50 mph E. 41 and 51 mph Source: Manhattan | Difficulty: Hard
D; i got 41.5 to 49
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