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25 Aug 2023, 23:39
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manav12222
Can you elaborate
Sure. The question asks to determine is k a multiple of 10 indicating any number divided by 10 will result in an integer. Statement 1: k^2+1 is a prime number. Keep listing few numbers that match this criteria. We get 2^2+1(2 is k), 6^2+1(6 is k), 10^2+1(10 is k) and so on. Each of these k^2+1 is a prime no. But we may may not divide the k by 10 as 2 and 6 surely won’t get divisible by 10, while 10 would. Insufficient
Statement 2: 2k is divisible by 5 indicates 2k can be 10, 20, 30, 40..... So k would be 5, 10, 15......
Clearly 5 isn’t divisible by 10, but 10 is. Insufficient.
Combining, we see only 10 is the common number. Similarly 20, 30,.... all will be the common numbers. So all these numbers are multiples of 10. Choice C is the correct choice.
25 Aug 2023, 23:49
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Ami0Trafalgar
i’m getting 212 can you explain how did you get 215?
Fourt digit numbers greater than 4000Starting with different number in units place, the first three digits can be 4,5,6,7,8,9 and units place can be 0 to 9. However it shouldn’t be same so 6 x 9= 54 such numbers.
Same way for different number in tens and hundredth place, 54 numbers each.
Now for different number in thousands place, for 5,6,7,8,9 the rest three can be 0 to 9 except the same digit. So 9x5= 45 numbers.
For 4, the rest three all except 0 and 4, since it should be greater than 4000. So 8 more numbers.
So 54+54+54+45+8=215
26 Aug 2023, 00:01
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jmitesh69
Fourt digit numbers greater than 4000 Starting with different number in units place, the first three digits can be 4,5,6,7,8,9 and units place can be 0 to 9. However it shouldn’t be same so 6 x 9= 54 such numbers. Same way for different number in tens and hundredth place, 54 numbers each. Now for different number in thousands place, for 5,6,7,8,9 the rest three can be 0 to 9 except the same digit. So 9x5= 45 numbers. For 4, the rest three all except 0 and 4, since it should be greater than 4000. So 8 more numbers. So 54+54+54+45+8=215
My bad i forgot to account for 0 in the case where the scheme can be (4x44, 44x4, 444x)Thank you!
Need to avoid these stupid mistakes smh
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