manav12222
Sure. The question asks to determine is k a multiple of 10 indicating any number divided by 10 will result in an integer.
Statement 1: k^2+1 is a prime number. Keep listing few numbers that match this criteria. We get 2^2+1(2 is k), 6^2+1(6 is k), 10^2+1(10 is k) and so on. Each of these k^2+1 is a prime no. But we may may not divide the k by 10 as 2 and 6 surely won’t get divisible by 10, while 10 would. Insufficient
Statement 2: 2k is divisible by 5 indicates 2k can be 10, 20, 30, 40..... So k would be 5, 10, 15......
Clearly 5 isn’t divisible by 10, but 10 is. Insufficient.
Combining, we see only 10 is the common number. Similarly 20, 30,.... all will be the common numbers. So all these numbers are multiples of 10. Choice C is the correct choice.