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Anik005
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Inspirestella
Can someone please explain how did you get 1/6 as the answer
Let probability of H be x and T be y
Getting one H and one T is 2C1*x*y which is 1/3 meaning xy is 1/6
Now probability of getting 2H 2T is 4C2*x*x*y*y which is 6*(1/6)*(1/6) = 6

= 1/6*
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Anik005
Can anyone do this math with details?
1st reverse
Y =2/7
Than add +2 both side
Y+2 = 16/7
Than again reverse
1/y+2 = 7/16
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Anik005
Can anyone do this math with details?
y= 2/7, 1/y=7/2=3.5, 1/y+2=5.5
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SATYAM7777
In order to complete a reading assignment on time, Terry planned to read 90 pages per day. However, she read only 75 pages per day at first, leaving 690 pages to be read during the last 6 days before the assignment was to be completed. How many days in all did Terry have to complete the assignment on time?
Total pages is 75n + 690
Here n is the number of days it took terry to read at the rate 75 pages/day

Now we know that total time allotted to her is n+6 days and she planned to do it at the rate of 90 pages/day.
hence the total pages read are
90(n+6)

Since total pages is the common factor,
Therefore,
75n + 690 = 90(n+6)
75n + 690 = 90n + 540
15n = 150
n = 10 days
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Sorry for the long message but that’s the step-by-step approach i followed
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sh_076
Let probability of H be x and T be y Getting one H and one T is 2C1*x*y which is 1/3 meaning xy is 1/6 Now probability of getting 2H 2T is 4C2*x*x*y*y which is 6*(1/6)*(1/6) = 6
What’s 2C1 and 4C2 and why are we doing that?
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Inspirestella
What’s 2C1 and 4C2 and why are we doing that?
I just did that to calculate how many combinations of two H and Two T are possible
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gmatophobia
DS Question 1 - Sep 19 If x is a positive integer less than 30, is x odd? (1) When x is divided by 3, the remainder is 2. (2) When x is divided by 5, the remainder is 2. Difficulty: Hard | Source: Veritas Prep
1) x/3 gives R2. In this case, x can be expressed as: x=3k+2 where k is any integer.
If k is 0, x=2
If k is 1, x=5
INS
2) Similarly, x can be expressed as x=5k+2
If k is 0, x is 2
If k is 1, x is 7.
Ins.

3) If x is not divisble by both 3 and 5, it can be expressed as:
x=15k+2
Here we can have:
x=2 or 17.
Still no definite value, so ins

E.

90x=T <- amount of days "x" that lets you finish the book at a rate of 90
75(x-6)+690=T <- reading at 75 pages for (x-6) days you have 690 in excess to read before finishing the book

Equate the two
75x+240=90x
15x=240
x=16
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gmatophobia
PS Question 1 - Sep 19 When an unfair coin is tossed twice, the probability of getting one tails and one heads is 1/3. What is the probability of getting two heads and two tails if the coin is tossed 4 times? A. 2/3 B. 1/3 C. 1/4 D. 1/6 E. 1/9 Difficulty: Hard | Source: GMAT Club Tests
Can someone pls provide the correct explanation for this ques?
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Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
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poojaarora1818
Can someone pls provide the correct explanation for this ques?
That’s a Bunuel’s question 😬🥴...
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bb
That’s a Bunuel’s question 😬🥴...
But I need a simple explanation for this ques.
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bb
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Unfortunately this is a convoluted one :(

Here is the best explanation I have: m36-375430.html

Maybe someone else can do a better one?
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bb
Here is the best explanation I have: m36-375430.html
Thank you so much for the help, BB! You are awesome.
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poojaarora1818
But I need a simple explanation for this ques.
I wrote an explanation above you can check if that helps

“ Let probability of H be x and T be y
Getting one H and one T is 2C1*x*y which is 1/3 meaning xy is 1/6
Now probability of getting 2H 2T is 4C2*x*x*y*y which is 6*(1/6)*(1/6) = 1/6”

2C1 and 4C2 are just number of ways we can get 1H 1T and 2H 2T combinations
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Is the sum of the prices of the 3 books that Shana bought less than $48 ?


(1) The price of the most expensive of the 3 books that Shana bought is less than $17.
(2) The price of the least expensive of the 3 books that Shana bought is exactly $3 less than the price of the second most expensive book.

How to solve this
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I am confused if prices can be in decimals
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The for (1) prices can be 16.9,16.8,16.7 which is > 48 so INS
(2) is sufficient because
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