Rohan271
Find the number of natural numbers which lie between 10^7 and 10^8 and which have products of their digits as 6? A. 36 B. 55 C. 64 D. 81 E. 105
I think 64 also
The number of natural numbers which lie between 10.000.000 and 100.000.000
Products of their digits as 6.
The only way to get 6 as a product is
6 as number and product of others 1
61.111.111 ; 16.111.111 ; - - -; 11.111.116 =8 ways
Or Also 3 and 2 as part of that number
32.111.111 ; 31.211.111 etc…8 numbers , 8 positions with 6 identical and equal to 1 and 2 others are 2 and 3
8*7*1*1*1*1*1*1 =56
Hence 56+6=64
I’m ´not sure handle this question in 2 min with this method… please check it
56+8 =54
Edoua
56+8=64
Sorry