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Thanks for sharing I use the basics principle that took too much time 2^89 = 2^7*…….(12times) *2^5 2^7 /89 remainder is 39 As 2^5 is not divisible by 89 2^89=R( 2^7/89)*…..(10times)..* R R =78 Remainder of (a*b*…..z)/n =R(a/n)*……R(z/n) —->> R 39 is not divisible by 89 but 39*39 yes And R(39*39)/89=8 —->> R *…(4times)*R R =1 We then have to find the remainder of 8*8*8*8*1 =4096 when divided by 89 4096= 89*46 +2 Time consuming

Do we have free GMAT club tests available ? @bunuel I have my exam in 5 days. Just need to give some and feel a bit at peace.

There is one test available for free, others are paid. You can do the 6 official practice tests 2 times each FYI Some of these companies also have a free test mock available Kaplan Veritas GMAT Club Princeton Review e-GMAT Experts’ Global Best My Test TTP Diagnostic Quant and Verbal I would not recommend doing a mock test from an unofficial source so close to the exam unless you are very confident and will not be shaken up if things go sideways

Such questions would not be tested on GMAT. But try finding a pattern in such questions and you should get your answer. Here too the remainders repeat after 11 different values. So 2^(89) or 2^(11*8+1) will have same remainder as 2^1 or 2. Of course you will have to find the pattern by multiplying consecutive reminders by 2.

Can you explain a bit more pls?

Two Quantities are equal Two Quantities are equal

take condition 3, we get - n is even, then from condition 2, n can be 8,18,28, ..98 and from condition 3 again, we find n can be 8,38,68,98. so 4 values

a 1/b. So, denominator in option A will be higher than that in option B. If denominator is higher, 1/ denominator will be lower

If x is a k-digit integer and x=(4^9)(5^17). What is the value of k? How should we approach a question like this?

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